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andriod09
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Okay people, I need help with Quadratic equations, i.e. \[ax^{2}+bx+c=0\]
I have 5 and i will only put 1 here. so keep up!
 one year ago
 one year ago
andriod09 Group Title
Okay people, I need help with Quadratic equations, i.e. \[ax^{2}+bx+c=0\] I have 5 and i will only put 1 here. so keep up!
 one year ago
 one year ago

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cgreenwade2000 Group TitleBest ResponseYou've already chosen the best response.0
Sounds easy enough. DO you know the Quadratic formula?
 one year ago

andriod09 Group TitleBest ResponseYou've already chosen the best response.0
\[4x^{2}+9x+20\] I know that the answer is: \[x=\frac{ 9\pm \sqrt{814(4)(2)} }{ 8 }\]
 one year ago

andriod09 Group TitleBest ResponseYou've already chosen the best response.0
How do i get from point A to point B? aka from the equation to the answer
 one year ago

andriod09 Group TitleBest ResponseYou've already chosen the best response.0
yea, thats what it says in my book. I do the Life of Fred series and i am doing Quadratic Equation.
 one year ago

andriod09 Group TitleBest ResponseYou've already chosen the best response.0
rly? its that easy?!?!?!?!?! omfg!
 one year ago

cgreenwade2000 Group TitleBest ResponseYou've already chosen the best response.0
Take it a step further and come up with two different answers android. I believe in you.
 one year ago

andriod09 Group TitleBest ResponseYou've already chosen the best response.0
how are ther two different answers?
 one year ago

andriod09 Group TitleBest ResponseYou've already chosen the best response.0
Honestly, ill say it in the 3 different launguages i know. English:no Spanish:no ASL:shankes head
 one year ago

andriod09 Group TitleBest ResponseYou've already chosen the best response.0
ik but, i don't get how you got them. how do you go from\[9\pm \frac{ \sqrt{8132} }{ 8 } \to 9\pm \frac{\sqrt{49} }{ 2 } \]
 one year ago

Outkast3r09 Group TitleBest ResponseYou've already chosen the best response.0
For \[ax^2+bx+c=0=4x^2+9x+2\] \[a=4,b=9,c=2\] using the quadratic formula \[x=\frac{b\pm \sqrt{b^24ac}}{2a}\] substituting in \[a=4,b=9,c=2\] \[x=\frac{9\pm \sqrt{9^24(4)(2)}}{2(4)}\] \[x=\frac{9\pm \sqrt{8132}}{8}\] \[x=\frac{9 \pm \sqrt{49}}{8}\] \[x=\frac{9\pm 7}{8}\] \[x=\frac{9+7}{8}\] \[x=\frac{2}{8}=\frac{1}{4}\] and \[x=\frac{97}{8}\] \[x=\frac{16}{8}=2\]
 one year ago

andriod09 Group TitleBest ResponseYou've already chosen the best response.0
okay, delete that long post and spearate the posts by a \[\to\] that get put into each other so its easier to read.
 one year ago
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