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anonymous
 4 years ago
Okay people, I need help with Quadratic equations, i.e. \[ax^{2}+bx+c=0\]
I have 5 and i will only put 1 here. so keep up!
anonymous
 4 years ago
Okay people, I need help with Quadratic equations, i.e. \[ax^{2}+bx+c=0\] I have 5 and i will only put 1 here. so keep up!

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cgreenwade2000
 4 years ago
Best ResponseYou've already chosen the best response.0Sounds easy enough. DO you know the Quadratic formula?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[4x^{2}+9x+20\] I know that the answer is: \[x=\frac{ 9\pm \sqrt{814(4)(2)} }{ 8 }\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0How do i get from point A to point B? aka from the equation to the answer

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yea, thats what it says in my book. I do the Life of Fred series and i am doing Quadratic Equation.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0rly? its that easy?!?!?!?!?! omfg!

cgreenwade2000
 4 years ago
Best ResponseYou've already chosen the best response.0Take it a step further and come up with two different answers android. I believe in you.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how are ther two different answers?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Honestly, ill say it in the 3 different launguages i know. English:no Spanish:no ASL:shankes head

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ik but, i don't get how you got them. how do you go from\[9\pm \frac{ \sqrt{8132} }{ 8 } \to 9\pm \frac{\sqrt{49} }{ 2 } \]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0For \[ax^2+bx+c=0=4x^2+9x+2\] \[a=4,b=9,c=2\] using the quadratic formula \[x=\frac{b\pm \sqrt{b^24ac}}{2a}\] substituting in \[a=4,b=9,c=2\] \[x=\frac{9\pm \sqrt{9^24(4)(2)}}{2(4)}\] \[x=\frac{9\pm \sqrt{8132}}{8}\] \[x=\frac{9 \pm \sqrt{49}}{8}\] \[x=\frac{9\pm 7}{8}\] \[x=\frac{9+7}{8}\] \[x=\frac{2}{8}=\frac{1}{4}\] and \[x=\frac{97}{8}\] \[x=\frac{16}{8}=2\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay, delete that long post and spearate the posts by a \[\to\] that get put into each other so its easier to read.
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