## andriod09 3 years ago Okay people, I need help with Quadratic equations, i.e. $ax^{2}+bx+c=0$ I have 5 and i will only put 1 here. so keep up!

Sounds easy enough. DO you know the Quadratic formula?

2. andriod09

$4x^{2}+9x+2-0$ I know that the answer is: $x=\frac{ -9\pm \sqrt{81-4(4)(2)} }{ 8 }$

3. andriod09

How do i get from point A to point B? aka from the equation to the answer

4. andriod09

yea, thats what it says in my book. I do the Life of Fred series and i am doing Quadratic Equation.

5. andriod09

rly? its that easy?!?!?!?!?! omfg!

Take it a step further and come up with two different answers android. I believe in you.

7. andriod09

how are ther two different answers?

8. andriod09

Honestly, ill say it in the 3 different launguages i know. English:no Spanish:no ASL:shankes head

9. andriod09

ik but, i don't get how you got them. how do you go from$-9\pm \frac{ \sqrt{81-32} }{ 8 } \to -9\pm \frac{\sqrt{49} }{ 2 }$

10. Outkast3r09

For $ax^2+bx+c=0=4x^2+9x+2$ $a=4,b=9,c=2$ using the quadratic formula $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ substituting in $a=4,b=9,c=2$ $x=\frac{-9\pm \sqrt{9^2-4(4)(2)}}{2(4)}$ $x=\frac{-9\pm \sqrt{81-32}}{8}$ $x=\frac{-9 \pm \sqrt{49}}{8}$ $x=\frac{-9\pm 7}{8}$ $x=\frac{-9+7}{8}$ $x=\frac{-2}{8}=\frac{-1}{4}$ and $x=\frac{-9-7}{8}$ $x=\frac{-16}{8}=-2$

11. andriod09

okay, delete that long post and spearate the posts by a $\to$ that get put into each other so its easier to read.