Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

lilsis76 Group Title

Suppose AD=1. Find the length of each of the other line segments in the figure. When radicals appear in an answer, leave the answer in that form rather than using a calculator. No CALCULATOR. I will post a drawing. and this is under RIGHT TRIANGLES in PRECAL @hartnn @timo86m

  • one year ago
  • one year ago

  • This Question is Closed
  1. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1348604530701:dw|

    • one year ago
  2. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    So far I figured: first triangle: AD________ <D=90 deg <A=30 deg <E= im going to say 60 deg. middle triangle: AE_________ AB_________ BE__________ <A_________ <B=90 deg <E=45 deg bottom triangle: BC____________ CE____________ <B____________ <C=60 deg. <E____________

    • one year ago
  3. gezimbasha Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    The sum of angles within each triangle is always 180 deg. So you were right when you assumed that <E is 60 deg on the first triangle. Try computing the rest of the angles and then I will help you with the lengths.

    • one year ago
  4. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    YAY! thank you for dble checking my 60 deg. okay thank you so far i have....

    • one year ago
  5. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    first triangle: <D=90 <A=30 <E=60 2nd triangle: <B=90 <E=45 <A=45 right? last Triangle: <B=90 <C=60 <E=75 right?

    • one year ago
  6. gezimbasha Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    Ok, your first two triangles are perfect. Your last triangle has a small mistake. Double check it. Its a small error on your calculation.

    • one year ago
  7. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    okay let me look

    • one year ago
  8. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    okay its <B=45

    • one year ago
  9. gezimbasha Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    No no, you were right at <B=90. If <B=90 and your other angle is <C=60. <E=180-(B+C) , hence your <E=30. Heh, small error. Dont worry. Let's continue with lengths now. Have you studied trigonometry?

    • one year ago
  10. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    okay thank you. No i haven't studied trignometry before, today my instructor guided us further into trig. functions, and triangles, but she goes so fast I am trying to keep up in our homework

    • one year ago
  11. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    i thank you for taking the time to assit me with this, its a pain to me cuz i dont really understand it as much as i want to for some reason

    • one year ago
  12. gezimbasha Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    Hey dont worry. It's difficult at first. Glad to help, and its good to see that people want to learn not just get their homework solved by someone else. Now let me solve one of the triangles of you, and then I will watch and you solve the other two. I will solve the first triangle. Hang on.

    • one year ago
  13. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    okay thank you.

    • one year ago
  14. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    OH! and we got this chart from the book i dont know if it will help: heita or theta(circle with a line going horizontal) Heita / Sin / Cos / Tan 30 deg 1/2 squ.rt.3 /2 squ rt 3 / 3 45 deg squ rt2/2 squrt. 2/2 1 60 deg squrt3/2 1/2 squrt 3

    • one year ago
  15. gezimbasha Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1348606638092:dw| We know that a =1, because AD=1. Now we use the trigonometry equations, and the chart you provided,\[\sin (60)=\frac{ a }{ c } =\frac{ 1 }{ c }\]we know from the table that \[\sin(60)=\frac{ \sqrt{3}}{ 2 }\]when we make that equal to 1/c, we get; \[\frac{ \sqrt{3} }{ 2 } = \frac{ 1 }{ c}\]and from there c is equal to the inverse of the result in the left,\[c=\frac{2}{\sqrt{3}}\]We repeat the same calculation for b, but this time instead of sin(60) we use sin(30). And we get,\[\sin(30)=\frac{b}{c}\]Now we know c from the result above so we substitute.\[\frac{ 1 }{ 2 } = \frac{b \sqrt{3}}{2}\]Multiply both sides by two, and you get\[1=b\sqrt{3}\]Divide by sqrt(3) and you get,\[b=\frac{1}{\sqrt{3}}\]

    • one year ago
  16. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    WOOW. lol okay sorry okay i am barely on the first part Sin60=Opp/Hyp so sin 60= 1/c okay sorry im taking such a step at a time. and Just letting you know ahead of time. Im going to take off at 220 to get sister from school and Ill be back by 245. Is it okay If i try and read thru your notes and get back to you around 245?

    • one year ago
  17. gezimbasha Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    Ok hang on. What timezone you at? Time over here is 11:13PM. I will probably be awake tho. I can help you. Dont worry.

    • one year ago
  18. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    for the first one when we did the C, i multiplied up and down of the...i think its called a rational the squ 3... well i did...\[C \sqrt{3} / 2 = 2, then (C/1 )\sqrt{3}/2 = 1/C (C/1) \to get: C \sqrt{3} = 2/\sqrt{3} then i mult. both \right side by \sqrt{3} the \top and bottom \to get 2\sqrt{3} / \sqrt{9} giving me the answer 2\sqrt{3}/3\]

    • one year ago
  19. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    AH! okay my thingy didnt work with everything i typed. its 2:15pm in the US. Okay if u have to go I understand. Well have a goodnite, i have to start taking off. thank you for everything

    • one year ago
  20. gezimbasha Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    Lol, no i don't have to go. I just wanted to know what time it is because i didnt understand 220. But now its ok. I'll be around. Just reply when you're back.

    • one year ago
  21. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    okay thank you i will.

    • one year ago
  22. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    okay im back.

    • one year ago
  23. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    okay let me review the work u placed again give me a min. please.

    • one year ago
  24. gezimbasha Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    Hey welcome back! Let's get to solving the probs then.

    • one year ago
  25. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    haha okay, hey where are you that the time is night?

    • one year ago
  26. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    okay from this: first part, where did the 2 come from? We repeat the same calculation for b, but this time instead of sin(60) we use sin(30). And we get, sin(30)=bc Now we know c from the result above so we substitute. 12=b3√2 Multiply both sides by two, and you get 1=b3√ Divide by sqrt(3) and you get, b=13√

    • one year ago
  27. gezimbasha Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    I live in Kosovo, which is in Europe. I need some clarification. Which 2 are you asking about?

    • one year ago
  28. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    wow, ive always wanted to go to europe. okay the 2 as in the number 2 ----Now we know c from the result above so we substitute. sin 30 12=b3√2

    • one year ago
  29. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    okay i dont know if u could see my last typing. but ill draw what i have gotten as an answer.

    • one year ago
  30. gezimbasha Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    Hehe, its a great place really. Europe is nice. I visited a couple of countries myself this summer. Was pretty cool. The two comes from the fact that:|dw:1348610270623:dw|

    • one year ago
  31. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1348610123789:dw|

    • one year ago
  32. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1348610422667:dw|

    • one year ago
  33. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    okay im done, is that right tho?

    • one year ago
  34. gezimbasha Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    Hmm hang on a minute, ill solve the whole problem and check yoru answers one by one.

    • one year ago
  35. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    okay. haha oh man, i thought you had fallen asleep for a sec. thank u for waitin for me to finish

    • one year ago
  36. gezimbasha Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    lol, no dont worry, i'm awake. i will help you solve this prob completely.

    • one year ago
  37. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    thank you

    • one year ago
  38. gezimbasha Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    Have you tried solving the third triangle or the middle triangle?

    • one year ago
  39. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    im trying to work on them right now, but it looks as tho i need a length, but im still going by the degrees. right now im trying to do the middle one and im using the first triangle measurements as an example to look back onto for guidence

    • one year ago
  40. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    But, i think Im going to u

    • one year ago
  41. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    haha but i think im going to use a=1 for AC=1 because i need something to use as an opposite

    • one year ago
  42. gezimbasha Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    Ok, here's what we have then..|dw:1348611838196:dw|

    • one year ago
  43. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    YA, thats what i have so far, haha but i forgot to place the 1 for x in the far right for length

    • one year ago
  44. gezimbasha Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    You dont need to compute AC, lets compute AB first. We can use \[\tan (45)=\frac{ AB }{ \frac{2}{\sqrt{3}} }\]This gives you\[1=\frac{AB}{\frac{2}{\sqrt{3}}}\]And from that\[AB=\frac{2}{\sqrt{3}}\]

    • one year ago
  45. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1348612135479:dw| the part where i put a dot it would be the same exact answer right for the length to solve the next triangle?

    • one year ago
  46. gezimbasha Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    Yes, you have the following values,\[AD=1\]\[AE=\frac{2}{\sqrt{3}}\]\[DE=\frac{1}{\sqrt{3}}\]

    • one year ago
  47. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    yes

    • one year ago
  48. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    now with filling out the middle triangle, i use either of the answers from the first one to get the answer for the middle one. okay let me see. Sorry im taking so long. i feel like im keeping u

    • one year ago
  49. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    AH! sorry for saying sorry

    • one year ago
  50. gezimbasha Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    lol relax don't worry. I am enjoying this. Otherwise I wouldn't be here. You try to solve that, and I will wait for your answer.

    • one year ago
  51. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    okay, well right now im trying to figure out which is best, so im going to stick with |dw:1348612826468:dw|

    • one year ago
  52. gezimbasha Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    Ok, very good. Calculate that and draw the triangle and tell me where x is.

    • one year ago
  53. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    how would u multiply |dw:1348612939771:dw|

    • one year ago
  54. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1348613038024:dw|

    • one year ago
  55. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1348613098124:dw|

    • one year ago
  56. gezimbasha Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    Ok, hang on. You do know SOH CAH TOA right? That will help you alot in trigonometry.

    • one year ago
  57. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    OH SORRY. how would i go about mulitplying...|dw:1348613263475:dw| yea I got the hang of SOH CAH TOA, but i cant seem to figure out a way to remember the other ones like cot or sec i think the other was scs? haha

    • one year ago
  58. gezimbasha Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1348613426139:dw|

    • one year ago
  59. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    okay, thank you, i thought it would be a 4 then squ rt 6, thank you for clarifying

    • one year ago
  60. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    okay but is that the answer for the side .....A-B? did i do it ?

    • one year ago
  61. gezimbasha Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    Hmm, how did you get to that multiplication? You're close tho...

    • one year ago
  62. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    dang im always close. ill draw it.

    • one year ago
  63. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1348613700910:dw|

    • one year ago
  64. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1348613888683:dw|

    • one year ago
  65. gezimbasha Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    Yes but you dont have a multiplication|dw:1348613976437:dw|

    • one year ago
  66. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    why is the X over the AE length?

    • one year ago
  67. gezimbasha Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    Because you are using sin which means opposite over hypotenuse.

    • one year ago
  68. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1348614388796:dw| I rotated it, i think its confusing me when its laying down.

    • one year ago
  69. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1348614492175:dw|

    • one year ago
  70. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    Okay i see it Sin= Opp/hyp.

    • one year ago
  71. gezimbasha Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    Yes, but you have two 45, so you need to use 90-45-45.

    • one year ago
  72. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    AH haha sorry hold on

    • one year ago
  73. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1348614636423:dw|

    • one year ago
  74. gezimbasha Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    Ok now just take AE and divide it by sqrt(2) and you will get x. Which means you effectively solve both AB and BE.

    • one year ago
  75. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    I got 4 ----- sq.rt. 6

    • one year ago
  76. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1348614899720:dw|

    • one year ago
  77. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1348614944183:dw|

    • one year ago
  78. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    this is what im getting, im so confused

    • one year ago
  79. gezimbasha Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1348615010146:dw| Close again haha :))

    • one year ago
  80. gezimbasha Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    Divide the other way around.

    • one year ago
  81. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    oh... okay i got that. Now i see how you told me I was close. I had to make it a fraction

    • one year ago
  82. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    so that 2 / sq.rt 6 is lengths Ab & Ae?

    • one year ago
  83. gezimbasha Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    Yes.. you're catching quick!. Let's continue with the third triangle.

    • one year ago
  84. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1348615274270:dw|

    • one year ago
  85. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1348615336270:dw| okay let me see the next part

    • one year ago
  86. gezimbasha Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    Ok, try to solve and send the solution to me.

    • one year ago
  87. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    okay

    • one year ago
  88. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1348615597032:dw|

    • one year ago
  89. gezimbasha Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    Perfect! Calculate that and show result..

    • one year ago
  90. gezimbasha Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    Be careful with the nominator. You have division not multiplication there.

    • one year ago
  91. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1348615813336:dw|

    • one year ago
  92. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    then im stuck

    • one year ago
  93. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    do i multiply the numerator and denomenator by sq. rt. 6? if I do I get: 2sqrt 6 / 3sqrt 6

    • one year ago
  94. gezimbasha Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    \[\tan(60)=\sqrt{3}\]And use this,\[x\sqrt{3}=\frac{2}{\sqrt{6}}\]

    • one year ago
  95. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    okay let me look at it again

    • one year ago
  96. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    so i wasn't close then. :/ hmm. okay on the = squrt 3, where did that come from?? on the tan60 = 3 from that chart thingy i first drew

    • one year ago
  97. gezimbasha Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    Heita / Sin / Cos / Tan 30 deg 1/2 squ.rt.3 /2 squ rt 3 / 3 45 deg squ rt2/2 squrt. 2/2 1 60 deg squrt3/2 1/2 squrt 3 It's sqrt(3) not 3 :))

    • one year ago
  98. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    so dang............I put it wrong ROAR! sorry

    • one year ago
  99. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    okay so where did the x come from when u put|dw:1348616685558:dw|

    • one year ago
  100. gezimbasha Group Title
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1348616752298:dw|

    • one year ago
  101. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    wait, is the X there because we're trying to find X right?

    • one year ago
  102. lilsis76 Group Title
    Best Response
    You've already chosen the best response.
    Medals 1

    okay |dw:1348617331171:dw|

    • one year ago