Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

nphuongsun93Best ResponseYou've already chosen the best response.0
is it this\[\huge \frac{1}{x^2} +4x + 3 + \frac{1}{x^21}\]?
 one year ago

Kris5Best ResponseYou've already chosen the best response.0
no the 4x+3 goes under 1 in the first fraction
 one year ago

nphuongsun93Best ResponseYou've already chosen the best response.0
\[\frac{1}{x^2+4x+3}+ \frac{1}{x^21}\]right?
 one year ago

nphuongsun93Best ResponseYou've already chosen the best response.0
let's see what i can do with this, just simplify i guess first factor \[x^2 + 4x + 3 \space and \space x^2  1\]
 one year ago

Kris5Best ResponseYou've already chosen the best response.0
(x+3) (x+1) and (x+1) (x1)
 one year ago

nphuongsun93Best ResponseYou've already chosen the best response.0
\[\frac{1}{(x+3)(x+1)} + \frac{1}{(x+1)(x1)}\]make the denominators common~
 one year ago

Kris5Best ResponseYou've already chosen the best response.0
that's what I don't get..I'm stuck there
 one year ago

nphuongsun93Best ResponseYou've already chosen the best response.0
\[\frac{(x1)+(x+3)}{(x+3)(x+1)(x1)}\]rings any bells? :s
 one year ago

nphuongsun93Best ResponseYou've already chosen the best response.0
dw:1348609884918:dw
 one year ago

nphuongsun93Best ResponseYou've already chosen the best response.0
\[\frac{2x+2}{(x+3)(x+1)(x1)}=\frac{2(x+1)}{(x+3)(x+1)(x1)}=\frac{2}{(x+3)(x1)}\]
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.