Kris5
1/x^2+4x+3+ 1/ x^21 ...please help me solve this



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nphuongsun93
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is it this\[\huge \frac{1}{x^2} +4x + 3 + \frac{1}{x^21}\]?

Kris5
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no the 4x+3 goes under 1 in the first fraction

nphuongsun93
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\[\frac{1}{x^2+4x+3}+ \frac{1}{x^21}\]right?

Kris5
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yes :)

nphuongsun93
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let's see what i can do with this, just simplify i guess
first factor \[x^2 + 4x + 3 \space and \space x^2  1\]

Kris5
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(x+3) (x+1) and (x+1) (x1)

nphuongsun93
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\[\frac{1}{(x+3)(x+1)} + \frac{1}{(x+1)(x1)}\]make the denominators common~

Kris5
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that's what I don't get..I'm stuck there

nphuongsun93
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\[\frac{(x1)+(x+3)}{(x+3)(x+1)(x1)}\]rings any bells? :s

Kris5
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sort of

nphuongsun93
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dw:1348609884918:dw

Kris5
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okay

nphuongsun93
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\[\frac{2x+2}{(x+3)(x+1)(x1)}=\frac{2(x+1)}{(x+3)(x+1)(x1)}=\frac{2}{(x+3)(x1)}\]

Kris5
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thanks :)