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AlainBarreto
Please help. 3(y-2)/5 = 1- 3y
first distribute the 3 into (y-2) to get rid of the parenthesis what do you get?
ok so now since 3y-6 divided by 5 doesn't come out evenly you can multiply both sides by 5 instead, now what do you have?
3y - 6 = 1 - 3y * 5
.....ok um let's focus on the right side, to get rid of /5 from the left you have to multiply everything on the right by 5, what do you get?
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oh lol 15. wasn't if i multiply something w. a variable next to it.
lol yeah you do.... so do you get how to do the rest of it?
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now divide both sides by 18
my study guide says the answer should be 11/18. not sure how tho.
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With equations like this you have to follow your order of operations. First parentheses, 3(y-2)/5=1-3y therefore your have (3y-6)/5=1-3y. Next you have Division, multiply both sides by 5 to cancel out the 5 on the left 5((3y-6)/5)=(1-3y)5 this gives you 3y-6=5-15y. Now we are ready for the last step of the order of operations before we start over, Add/Subbtract from both sides and it will look like this, 18y=11. we now have to start back from the top to get y by its self devide both sides by 18 to cancel, final answer y=11/18