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first distribute the 3 into (y-2) to get rid of the parenthesis what do you get?
ok so now since 3y-6 divided by 5 doesn't come out evenly you can multiply both sides by 5 instead, now what do you have?
3y - 6 = 1 - 3y * 5
.....ok um let's focus on the right side, to get rid of /5 from the left you have to multiply everything on the right by 5, what do you get?
oh lol 15. wasn't if i multiply something w. a variable next to it.
lol yeah you do.... so do you get how to do the rest of it?
now divide both sides by 18
my study guide says the answer should be 11/18. not sure how tho.
Nv Ty :)
With equations like this you have to follow your order of operations. First parentheses, 3(y-2)/5=1-3y therefore your have (3y-6)/5=1-3y. Next you have Division, multiply both sides by 5 to cancel out the 5 on the left 5((3y-6)/5)=(1-3y)5 this gives you 3y-6=5-15y. Now we are ready for the last step of the order of operations before we start over, Add/Subbtract from both sides and it will look like this, 18y=11. we now have to start back from the top to get y by its self devide both sides by 18 to cancel, final answer y=11/18