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Aluminum hydroxide + calcium  =

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I am just confused on one thing. Is the Aluminum Hydroxide writted in a chemical equation as AlOH or is is Al(OH)3(small 3)
When an equation, any equation is written the elements must be compounded right and so Al(OH)3 should be correct?
according to this page it's \(\Large \text{Al(OH)}_{3}\)

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Yes, because it is unpossible for the compound to our without the 3 OH's
I have one more question
Aluminum essentially always has an oxidation state of +3, because it loses control of its 3 valence electrons, so it would be Al(OH)3.
I am learning how to predict the type of reaction when certain elements and compounds are put together, i have a question --- water reacts to form ...--- and i have to predict the type of reaction - what type whould it be
As for the reaction, calcium is more active metal than aluminum: Al(s) -> Al+3(aq) + 3e E0 = -1.66V Ca(s) -> Ca+2(aq) + 2e E0 = -2.87V principle the calcium can reduce the aluminum: 3 Ca(s) +2 Al(OH)3 -> 3 Ca(OH)2 + 2 Al(s)
Thanks Guys

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