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andriod09
Need help on Quadratic equations please! The equation is on the comments.
\[4x^{2}+9x=0\] i know that the answer is: \[x=\frac{ -9\pm \sqrt{81-4(4)(2)} }{ 8 }\]
Much easier to solve your problem would be to factor out an x,\[x(4x+9)=0\]now you have two solutions,\[x=0\]and\[4x+9=0\]\[4x=-9\]\[x=-\frac{9}{4}\]and you get
The equation is correct. But you put innocent "2" instead of "0" for c.
huh? the thing messed up, give me a sec
Well, then you can do the following:\[x_{1/2}=\frac{-9 \pm \sqrt{9^2-4*4*0}}{2*4}\]simplifying that you get,\[x_{1/2}=\frac{ -9 \pm 9 }{ 8 }\]Compute the rest
I have to use: \[ax^{2}+bx+c=0\] and i have to use: \[x=\frac{ -b\pm \sqrt{b^{2}-4ac} }{ 2a }\]
Yes.. that is what I have used. Just make c=0, and you will get the same result as I have.
but c = 2... thats what the answer says.
Well then you have given us a wrong problem\[4x^2+9x=0\]does not have a c in it..
my bad... /facepalm its: \[4x^{2}+9x+2=0\]
Hehe, no worries. Now you have to use the formula you input\[x_{1/2}=\frac{-9 \pm \sqrt{9^2-4*4*2}}{2*4}\]compute the values inside the square root first\[x_{1/2}=\frac{-9 \pm \sqrt{81- 32}}{8}\]and complete calculation\[x_{1/2}=\frac{-9 \pm 7}{8}\] and you get,\[x_1= -2\]\[x_2=-\frac{1}{4}\]
where did you get \[x _{1/2} \]
That just means that there are two solutions we will get from the equation. Its just mathematical notation. I am used to writing it like that. Don't worry, you can write just x, it will be fine.
im only in high school. :/ :L
Yeah I figured. The quadratic equations are studied extensively in high school. You're doing good tho. Might want to reconsider your profile picture heh ;)
it says i don't hate math. open my profile and look at the white! everyone says that. lol do you not see the white scribble on the \[^{don't}\] I hate math
Oh.. then I owe you an apology. XD.
Its okay. I need to make it bigger anyway. lol. Thanks tho.
You're welcome man. Anytime!
I gave you a medal. dont for get to give one back~ ;)
Hey, my bad, my first day over here.
This is my first day in open study, so I'm still getting used to the medals and stuff.
how would i set up: \[3x^{2}+11x+5=0\] and oh. i didn't know
Same principle, replace a=3, b=11, and c=5.
i mean in the fraction form