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\[4x^{2}+9x=0\]
i know that the answer is:
\[x=\frac{ -9\pm \sqrt{81-4(4)(2)} }{ 8 }\]

The equation is correct. But you put innocent "2" instead of "0" for c.

huh? the thing messed up, give me a sec

I have to use:
\[ax^{2}+bx+c=0\]
and i have to use:
\[x=\frac{ -b\pm \sqrt{b^{2}-4ac} }{ 2a }\]

Yes.. that is what I have used. Just make c=0, and you will get the same result as I have.

but c = 2... thats what the answer says.

Well then you have given us a wrong problem\[4x^2+9x=0\]does not have a c in it..

my bad... /facepalm
its:
\[4x^{2}+9x+2=0\]

where did you get \[x _{1/2} \]

im only in high school. :/ :L

Oh.. then I owe you an apology. XD.

Its okay. I need to make it bigger anyway. lol. Thanks tho.

You're welcome man. Anytime!

I gave you a medal. dont for get to give one back~ ;)

Hey, my bad, my first day over here.

what do you mean?

This is my first day in open study, so I'm still getting used to the medals and stuff.

how would i set up:
\[3x^{2}+11x+5=0\] and oh. i didn't know

Same principle, replace a=3, b=11, and c=5.

i mean in the fraction form