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Need help on Quadratic equations please!
The equation is on the comments.
 one year ago
 one year ago
Need help on Quadratic equations please! The equation is on the comments.
 one year ago
 one year ago

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andriod09Best ResponseYou've already chosen the best response.1
\[4x^{2}+9x=0\] i know that the answer is: \[x=\frac{ 9\pm \sqrt{814(4)(2)} }{ 8 }\]
 one year ago

gezimbashaBest ResponseYou've already chosen the best response.1
Much easier to solve your problem would be to factor out an x,\[x(4x+9)=0\]now you have two solutions,\[x=0\]and\[4x+9=0\]\[4x=9\]\[x=\frac{9}{4}\]and you get
 one year ago

imron07Best ResponseYou've already chosen the best response.0
The equation is correct. But you put innocent "2" instead of "0" for c.
 one year ago

andriod09Best ResponseYou've already chosen the best response.1
huh? the thing messed up, give me a sec
 one year ago

gezimbashaBest ResponseYou've already chosen the best response.1
Well, then you can do the following:\[x_{1/2}=\frac{9 \pm \sqrt{9^24*4*0}}{2*4}\]simplifying that you get,\[x_{1/2}=\frac{ 9 \pm 9 }{ 8 }\]Compute the rest
 one year ago

andriod09Best ResponseYou've already chosen the best response.1
I have to use: \[ax^{2}+bx+c=0\] and i have to use: \[x=\frac{ b\pm \sqrt{b^{2}4ac} }{ 2a }\]
 one year ago

gezimbashaBest ResponseYou've already chosen the best response.1
Yes.. that is what I have used. Just make c=0, and you will get the same result as I have.
 one year ago

andriod09Best ResponseYou've already chosen the best response.1
but c = 2... thats what the answer says.
 one year ago

gezimbashaBest ResponseYou've already chosen the best response.1
Well then you have given us a wrong problem\[4x^2+9x=0\]does not have a c in it..
 one year ago

andriod09Best ResponseYou've already chosen the best response.1
my bad... /facepalm its: \[4x^{2}+9x+2=0\]
 one year ago

gezimbashaBest ResponseYou've already chosen the best response.1
Hehe, no worries. Now you have to use the formula you input\[x_{1/2}=\frac{9 \pm \sqrt{9^24*4*2}}{2*4}\]compute the values inside the square root first\[x_{1/2}=\frac{9 \pm \sqrt{81 32}}{8}\]and complete calculation\[x_{1/2}=\frac{9 \pm 7}{8}\] and you get,\[x_1= 2\]\[x_2=\frac{1}{4}\]
 one year ago

andriod09Best ResponseYou've already chosen the best response.1
where did you get \[x _{1/2} \]
 one year ago

gezimbashaBest ResponseYou've already chosen the best response.1
That just means that there are two solutions we will get from the equation. Its just mathematical notation. I am used to writing it like that. Don't worry, you can write just x, it will be fine.
 one year ago

andriod09Best ResponseYou've already chosen the best response.1
im only in high school. :/ :L
 one year ago

gezimbashaBest ResponseYou've already chosen the best response.1
Yeah I figured. The quadratic equations are studied extensively in high school. You're doing good tho. Might want to reconsider your profile picture heh ;)
 one year ago

andriod09Best ResponseYou've already chosen the best response.1
it says i don't hate math. open my profile and look at the white! everyone says that. lol do you not see the white scribble on the \[^{don't}\] I hate math
 one year ago

gezimbashaBest ResponseYou've already chosen the best response.1
Oh.. then I owe you an apology. XD.
 one year ago

andriod09Best ResponseYou've already chosen the best response.1
Its okay. I need to make it bigger anyway. lol. Thanks tho.
 one year ago

gezimbashaBest ResponseYou've already chosen the best response.1
You're welcome man. Anytime!
 one year ago

andriod09Best ResponseYou've already chosen the best response.1
I gave you a medal. dont for get to give one back~ ;)
 one year ago

gezimbashaBest ResponseYou've already chosen the best response.1
Hey, my bad, my first day over here.
 one year ago

gezimbashaBest ResponseYou've already chosen the best response.1
This is my first day in open study, so I'm still getting used to the medals and stuff.
 one year ago

andriod09Best ResponseYou've already chosen the best response.1
how would i set up: \[3x^{2}+11x+5=0\] and oh. i didn't know
 one year ago

gezimbashaBest ResponseYou've already chosen the best response.1
Same principle, replace a=3, b=11, and c=5.
 one year ago

andriod09Best ResponseYou've already chosen the best response.1
i mean in the fraction form
 one year ago
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