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Quadratic Equation question How do i get from: \[x=-11\pm \frac{121-60}{ 6 }\] to the next part?

Mathematics
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ok
im working on those problems too im not that good but i would simplify 121-6/ then.. which is?

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Other answers:

well first of all.....write out two different equations to eliminate that +-
@cos00155079 you doing the Life of Fred series?
you don't have to do that @jwheele1
i know you dont have to but its easier...its cool we wont do that then
the what? nooo...
121 - 60 = ?
61
10
\[1\] \[-21\]
why 60/6 if it was a 61?
ik
alright lets see now...
the equation is: \[x=-11\pm \frac{ \sqrt{121-60} }{ 6 } \]
oh lawd....lol
sq rt of 121 = 11
whats with teh line over the 0?
its just how it is. not my doing.
well...it means that its a repeating number but its usually only after a decimal point...weird.
I have no idea what to do with the 60 and the line over it.
the original equation is: \[3x^{2}+11x+5=0\]
any specific way she is wanting you to go about that?
its a messup about square roots.
or can we solve for x any old way?
yea, using \[ax^{2}+bx+c=0\] and the \[x=-b\pm\frac{ \sqrt{b^{2}-4ac} }{ 2a }\]
the QuAdRaTiC ForMulA.....lol
ok so 3x^2 + 11x +5 = 0 ax^2 + bx +c
a = 3 b = 11 c = 5
\[-11\pm \frac{ \sqrt{11^{2}-4(3*5c)} }{ 2(3) }\]
does that look right?
ignore the c next to the 5, lol |dw:1348620564257:dw|
|dw:1348620625370:dw|
i see where we screwed up now in the beginning
|dw:1348620687638:dw|
NOW......what has your teacher said to do with this?
because you can find common denominaters and put it all over one bar or you can leave it the way it is.
I teach my self. I am homeschooled, i use the LoF series.
oh, cool
well....you could work it out to this way if you wanted to.... |dw:1348620830185:dw|
the last answer i got was \[x_{1}\] and \[x_{2}\]
OH yeah...i forgot this was all part of an original equation....this one might be too complicated for the quad formula. have you tried grouping method?
i mean factoring
and it was \[x=\frac{-9\pm7} { 8 }\] I did the quadratic formula on all of these so far, its a quadratic formula page. they're supposed to use the quadratic formula
ok well then we must find exact values
the sq rt of 61 is 7.810249675906654
divided by 6 = 1.301708279317776
-11 + 1.301708279317776 = ? -11 - 1.301708279317776 = ?
we need not find exact values, we need to find \[x_1\] and \[x_2\]
x1 and x2 are exact values
it appears anyways...this one is ugly
x1 = -9.698291720682224, x2 = -12.30170827931778 lol
none of this seems right to me and its driving me nuts, lol
for sure you need to find the square root of 61
which is not what you have in your original problem at the top
http://www.mathsisfun.com/quadratic-equation-solver.html
Heres your answer
1 Attachment
its these: \[x_{1}=\frac{ -11+\sqrt{61} }{ 6 }\] and \[x_{1}=\frac{ -11-\sqrt{61} }{ 6 }\]
thats what i would put....what you just put
this is what my brother says, who is in college.
i am also in college. I woudl also stop there...I thought it was weird that were were trying to find the actual value for x1 and 2
|dw:1348621589793:dw|
That is if you put it all under one common denominator which some teachers ask for...usually that is not what they want though
it means the same thing but most people show it liek yoru brother did
w/e i have it and its done. thanks for any help!
yw

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