andriod09
  • andriod09
Quadratic Equation question How do i get from: \[x=-11\pm \frac{121-60}{ 6 }\] to the next part?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
andriod09
  • andriod09
@jwheele1
jwheele1
  • jwheele1
ok
anonymous
  • anonymous
im working on those problems too im not that good but i would simplify 121-6/ then.. which is?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

jwheele1
  • jwheele1
well first of all.....write out two different equations to eliminate that +-
andriod09
  • andriod09
@cos00155079 you doing the Life of Fred series?
andriod09
  • andriod09
you don't have to do that @jwheele1
jwheele1
  • jwheele1
i know you dont have to but its easier...its cool we wont do that then
anonymous
  • anonymous
the what? nooo...
jwheele1
  • jwheele1
121 - 60 = ?
andriod09
  • andriod09
61
andriod09
  • andriod09
10
andriod09
  • andriod09
\[1\] \[-21\]
anonymous
  • anonymous
why 60/6 if it was a 61?
andriod09
  • andriod09
ik
jwheele1
  • jwheele1
alright lets see now...
andriod09
  • andriod09
the equation is: \[x=-11\pm \frac{ \sqrt{121-60} }{ 6 } \]
jwheele1
  • jwheele1
oh lawd....lol
jwheele1
  • jwheele1
sq rt of 121 = 11
jwheele1
  • jwheele1
whats with teh line over the 0?
andriod09
  • andriod09
its just how it is. not my doing.
jwheele1
  • jwheele1
well...it means that its a repeating number but its usually only after a decimal point...weird.
jwheele1
  • jwheele1
I have no idea what to do with the 60 and the line over it.
andriod09
  • andriod09
the original equation is: \[3x^{2}+11x+5=0\]
jwheele1
  • jwheele1
any specific way she is wanting you to go about that?
andriod09
  • andriod09
its a messup about square roots.
jwheele1
  • jwheele1
or can we solve for x any old way?
andriod09
  • andriod09
yea, using \[ax^{2}+bx+c=0\] and the \[x=-b\pm\frac{ \sqrt{b^{2}-4ac} }{ 2a }\]
jwheele1
  • jwheele1
the QuAdRaTiC ForMulA.....lol
jwheele1
  • jwheele1
ok so 3x^2 + 11x +5 = 0 ax^2 + bx +c
jwheele1
  • jwheele1
a = 3 b = 11 c = 5
jwheele1
  • jwheele1
\[-11\pm \frac{ \sqrt{11^{2}-4(3*5c)} }{ 2(3) }\]
jwheele1
  • jwheele1
does that look right?
jwheele1
  • jwheele1
ignore the c next to the 5, lol |dw:1348620564257:dw|
jwheele1
  • jwheele1
|dw:1348620625370:dw|
jwheele1
  • jwheele1
i see where we screwed up now in the beginning
jwheele1
  • jwheele1
|dw:1348620687638:dw|
jwheele1
  • jwheele1
NOW......what has your teacher said to do with this?
jwheele1
  • jwheele1
because you can find common denominaters and put it all over one bar or you can leave it the way it is.
andriod09
  • andriod09
I teach my self. I am homeschooled, i use the LoF series.
jwheele1
  • jwheele1
oh, cool
jwheele1
  • jwheele1
well....you could work it out to this way if you wanted to.... |dw:1348620830185:dw|
andriod09
  • andriod09
the last answer i got was \[x_{1}\] and \[x_{2}\]
jwheele1
  • jwheele1
OH yeah...i forgot this was all part of an original equation....this one might be too complicated for the quad formula. have you tried grouping method?
jwheele1
  • jwheele1
i mean factoring
andriod09
  • andriod09
and it was \[x=\frac{-9\pm7} { 8 }\] I did the quadratic formula on all of these so far, its a quadratic formula page. they're supposed to use the quadratic formula
jwheele1
  • jwheele1
ok well then we must find exact values
jwheele1
  • jwheele1
the sq rt of 61 is 7.810249675906654
jwheele1
  • jwheele1
divided by 6 = 1.301708279317776
jwheele1
  • jwheele1
-11 + 1.301708279317776 = ? -11 - 1.301708279317776 = ?
andriod09
  • andriod09
we need not find exact values, we need to find \[x_1\] and \[x_2\]
jwheele1
  • jwheele1
x1 and x2 are exact values
jwheele1
  • jwheele1
it appears anyways...this one is ugly
jwheele1
  • jwheele1
x1 = -9.698291720682224, x2 = -12.30170827931778 lol
jwheele1
  • jwheele1
none of this seems right to me and its driving me nuts, lol
jwheele1
  • jwheele1
for sure you need to find the square root of 61
jwheele1
  • jwheele1
which is not what you have in your original problem at the top
jwheele1
  • jwheele1
http://www.mathsisfun.com/quadratic-equation-solver.html
jwheele1
  • jwheele1
Heres your answer
jwheele1
  • jwheele1
1 Attachment
andriod09
  • andriod09
its these: \[x_{1}=\frac{ -11+\sqrt{61} }{ 6 }\] and \[x_{1}=\frac{ -11-\sqrt{61} }{ 6 }\]
jwheele1
  • jwheele1
thats what i would put....what you just put
andriod09
  • andriod09
this is what my brother says, who is in college.
jwheele1
  • jwheele1
i am also in college. I woudl also stop there...I thought it was weird that were were trying to find the actual value for x1 and 2
andriod09
  • andriod09
|dw:1348621589793:dw|
jwheele1
  • jwheele1
That is if you put it all under one common denominator which some teachers ask for...usually that is not what they want though
jwheele1
  • jwheele1
it means the same thing but most people show it liek yoru brother did
andriod09
  • andriod09
w/e i have it and its done. thanks for any help!
jwheele1
  • jwheele1
yw

Looking for something else?

Not the answer you are looking for? Search for more explanations.