Quadratic Equation question
How do i get from:
\[x=-11\pm \frac{121-60}{ 6 }\]
to the next part?

- andriod09

Quadratic Equation question
How do i get from:
\[x=-11\pm \frac{121-60}{ 6 }\]
to the next part?

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- schrodinger

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- andriod09

@jwheele1

- jwheele1

ok

- anonymous

im working on those problems too im not that good but i would simplify 121-6/ then.. which is?

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## More answers

- jwheele1

well first of all.....write out two different equations to eliminate that +-

- andriod09

@cos00155079 you doing the Life of Fred series?

- andriod09

you don't have to do that @jwheele1

- jwheele1

i know you dont have to but its easier...its cool we wont do that then

- anonymous

the what? nooo...

- jwheele1

121 - 60 = ?

- andriod09

61

- andriod09

10

- andriod09

\[1\]
\[-21\]

- anonymous

why 60/6 if it was a 61?

- andriod09

ik

- jwheele1

alright lets see now...

- andriod09

the equation is:
\[x=-11\pm \frac{ \sqrt{121-60} }{ 6 } \]

- jwheele1

oh lawd....lol

- jwheele1

sq rt of 121 = 11

- jwheele1

whats with teh line over the 0?

- andriod09

its just how it is. not my doing.

- jwheele1

well...it means that its a repeating number but its usually only after a decimal point...weird.

- jwheele1

I have no idea what to do with the 60 and the line over it.

- andriod09

the original equation is:
\[3x^{2}+11x+5=0\]

- jwheele1

any specific way she is wanting you to go about that?

- andriod09

its a messup about square roots.

- jwheele1

or can we solve for x any old way?

- andriod09

yea, using \[ax^{2}+bx+c=0\] and the
\[x=-b\pm\frac{ \sqrt{b^{2}-4ac} }{ 2a }\]

- jwheele1

the QuAdRaTiC ForMulA.....lol

- jwheele1

ok so
3x^2 + 11x +5 = 0
ax^2 + bx +c

- jwheele1

a = 3
b = 11
c = 5

- jwheele1

\[-11\pm \frac{ \sqrt{11^{2}-4(3*5c)} }{ 2(3) }\]

- jwheele1

does that look right?

- jwheele1

ignore the c next to the 5, lol
|dw:1348620564257:dw|

- jwheele1

|dw:1348620625370:dw|

- jwheele1

i see where we screwed up now in the beginning

- jwheele1

|dw:1348620687638:dw|

- jwheele1

NOW......what has your teacher said to do with this?

- jwheele1

because you can find common denominaters and put it all over one bar or you can leave it the way it is.

- andriod09

I teach my self. I am homeschooled, i use the LoF series.

- jwheele1

oh, cool

- jwheele1

well....you could work it out to this way if you wanted to....
|dw:1348620830185:dw|

- andriod09

the last answer i got was \[x_{1}\] and \[x_{2}\]

- jwheele1

OH yeah...i forgot this was all part of an original equation....this one might be too complicated for the quad formula. have you tried grouping method?

- jwheele1

i mean factoring

- andriod09

and it was \[x=\frac{-9\pm7} { 8 }\]
I did the quadratic formula on all of these so far, its a quadratic formula page. they're supposed to use the quadratic formula

- jwheele1

ok well then we must find exact values

- jwheele1

the sq rt of 61 is 7.810249675906654

- jwheele1

divided by 6 = 1.301708279317776

- jwheele1

-11 + 1.301708279317776 = ?
-11 - 1.301708279317776 = ?

- andriod09

we need not find exact values, we need to find \[x_1\] and \[x_2\]

- jwheele1

x1 and x2 are exact values

- jwheele1

it appears anyways...this one is ugly

- jwheele1

x1 = -9.698291720682224, x2 = -12.30170827931778 lol

- jwheele1

none of this seems right to me and its driving me nuts, lol

- jwheele1

for sure you need to find the square root of 61

- jwheele1

which is not what you have in your original problem at the top

- jwheele1

http://www.mathsisfun.com/quadratic-equation-solver.html

- jwheele1

Heres your answer

- jwheele1

##### 1 Attachment

- andriod09

its these:
\[x_{1}=\frac{ -11+\sqrt{61} }{ 6 }\]
and
\[x_{1}=\frac{ -11-\sqrt{61} }{ 6 }\]

- jwheele1

thats what i would put....what you just put

- andriod09

this is what my brother says, who is in college.

- jwheele1

i am also in college. I woudl also stop there...I thought it was weird that were were trying to find the actual value for x1 and 2

- andriod09

|dw:1348621589793:dw|

- jwheele1

That is if you put it all under one common denominator which some teachers ask for...usually that is not what they want though

- jwheele1

it means the same thing but most people show it liek yoru brother did

- andriod09

w/e i have it and its done. thanks for any help!

- jwheele1

yw

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