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andriod09

  • 2 years ago

Quadratic Equation question How do i get from: \[x=-11\pm \frac{121-60}{ 6 }\] to the next part?

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  1. andriod09
    • 2 years ago
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    @jwheele1

  2. jwheele1
    • 2 years ago
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    ok

  3. cos00155079
    • 2 years ago
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    im working on those problems too im not that good but i would simplify 121-6/ then.. which is?

  4. jwheele1
    • 2 years ago
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    well first of all.....write out two different equations to eliminate that +-

  5. andriod09
    • 2 years ago
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    @cos00155079 you doing the Life of Fred series?

  6. andriod09
    • 2 years ago
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    you don't have to do that @jwheele1

  7. jwheele1
    • 2 years ago
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    i know you dont have to but its easier...its cool we wont do that then

  8. cos00155079
    • 2 years ago
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    the what? nooo...

  9. jwheele1
    • 2 years ago
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    121 - 60 = ?

  10. andriod09
    • 2 years ago
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    61

  11. andriod09
    • 2 years ago
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    10

  12. andriod09
    • 2 years ago
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    \[1\] \[-21\]

  13. cos00155079
    • 2 years ago
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    why 60/6 if it was a 61?

  14. andriod09
    • 2 years ago
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    ik

  15. jwheele1
    • 2 years ago
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    alright lets see now...

  16. andriod09
    • 2 years ago
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    the equation is: \[x=-11\pm \frac{ \sqrt{121-60} }{ 6 } \]

  17. jwheele1
    • 2 years ago
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    oh lawd....lol

  18. jwheele1
    • 2 years ago
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    sq rt of 121 = 11

  19. jwheele1
    • 2 years ago
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    whats with teh line over the 0?

  20. andriod09
    • 2 years ago
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    its just how it is. not my doing.

  21. jwheele1
    • 2 years ago
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    well...it means that its a repeating number but its usually only after a decimal point...weird.

  22. jwheele1
    • 2 years ago
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    I have no idea what to do with the 60 and the line over it.

  23. andriod09
    • 2 years ago
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    the original equation is: \[3x^{2}+11x+5=0\]

  24. jwheele1
    • 2 years ago
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    any specific way she is wanting you to go about that?

  25. andriod09
    • 2 years ago
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    its a messup about square roots.

  26. jwheele1
    • 2 years ago
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    or can we solve for x any old way?

  27. andriod09
    • 2 years ago
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    yea, using \[ax^{2}+bx+c=0\] and the \[x=-b\pm\frac{ \sqrt{b^{2}-4ac} }{ 2a }\]

  28. jwheele1
    • 2 years ago
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    the QuAdRaTiC ForMulA.....lol

  29. jwheele1
    • 2 years ago
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    ok so 3x^2 + 11x +5 = 0 ax^2 + bx +c

  30. jwheele1
    • 2 years ago
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    a = 3 b = 11 c = 5

  31. jwheele1
    • 2 years ago
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    \[-11\pm \frac{ \sqrt{11^{2}-4(3*5c)} }{ 2(3) }\]

  32. jwheele1
    • 2 years ago
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    does that look right?

  33. jwheele1
    • 2 years ago
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    ignore the c next to the 5, lol |dw:1348620564257:dw|

  34. jwheele1
    • 2 years ago
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    |dw:1348620625370:dw|

  35. jwheele1
    • 2 years ago
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    i see where we screwed up now in the beginning

  36. jwheele1
    • 2 years ago
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    |dw:1348620687638:dw|

  37. jwheele1
    • 2 years ago
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    NOW......what has your teacher said to do with this?

  38. jwheele1
    • 2 years ago
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    because you can find common denominaters and put it all over one bar or you can leave it the way it is.

  39. andriod09
    • 2 years ago
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    I teach my self. I am homeschooled, i use the LoF series.

  40. jwheele1
    • 2 years ago
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    oh, cool

  41. jwheele1
    • 2 years ago
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    well....you could work it out to this way if you wanted to.... |dw:1348620830185:dw|

  42. andriod09
    • 2 years ago
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    the last answer i got was \[x_{1}\] and \[x_{2}\]

  43. jwheele1
    • 2 years ago
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    OH yeah...i forgot this was all part of an original equation....this one might be too complicated for the quad formula. have you tried grouping method?

  44. jwheele1
    • 2 years ago
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    i mean factoring

  45. andriod09
    • 2 years ago
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    and it was \[x=\frac{-9\pm7} { 8 }\] I did the quadratic formula on all of these so far, its a quadratic formula page. they're supposed to use the quadratic formula

  46. jwheele1
    • 2 years ago
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    ok well then we must find exact values

  47. jwheele1
    • 2 years ago
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    the sq rt of 61 is 7.810249675906654

  48. jwheele1
    • 2 years ago
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    divided by 6 = 1.301708279317776

  49. jwheele1
    • 2 years ago
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    -11 + 1.301708279317776 = ? -11 - 1.301708279317776 = ?

  50. andriod09
    • 2 years ago
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    we need not find exact values, we need to find \[x_1\] and \[x_2\]

  51. jwheele1
    • 2 years ago
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    x1 and x2 are exact values

  52. jwheele1
    • 2 years ago
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    it appears anyways...this one is ugly

  53. jwheele1
    • 2 years ago
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    x1 = -9.698291720682224, x2 = -12.30170827931778 lol

  54. jwheele1
    • 2 years ago
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    none of this seems right to me and its driving me nuts, lol

  55. jwheele1
    • 2 years ago
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    for sure you need to find the square root of 61

  56. jwheele1
    • 2 years ago
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    which is not what you have in your original problem at the top

  57. jwheele1
    • 2 years ago
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    http://www.mathsisfun.com/quadratic-equation-solver.html

  58. jwheele1
    • 2 years ago
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    Heres your answer

  59. jwheele1
    • 2 years ago
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  60. andriod09
    • 2 years ago
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    its these: \[x_{1}=\frac{ -11+\sqrt{61} }{ 6 }\] and \[x_{1}=\frac{ -11-\sqrt{61} }{ 6 }\]

  61. jwheele1
    • 2 years ago
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    thats what i would put....what you just put

  62. andriod09
    • 2 years ago
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    this is what my brother says, who is in college.

  63. jwheele1
    • 2 years ago
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    i am also in college. I woudl also stop there...I thought it was weird that were were trying to find the actual value for x1 and 2

  64. andriod09
    • 2 years ago
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    |dw:1348621589793:dw|

  65. jwheele1
    • 2 years ago
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    That is if you put it all under one common denominator which some teachers ask for...usually that is not what they want though

  66. jwheele1
    • 2 years ago
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    it means the same thing but most people show it liek yoru brother did

  67. andriod09
    • 2 years ago
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    w/e i have it and its done. thanks for any help!

  68. jwheele1
    • 2 years ago
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    yw

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