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\(\large g(t) = 5cos^3(\pi t)\)

HINT - pie and t are constant

use the trig formulas for derivatives

where do i take the derivative first for this function?

use the chain rule , not the product rule

ok so whta rule would i be using in this case when i take ther derivative of the outermost function

The power rule :) and then as Unkle mentioned, the chain rule after that.

ok..... so using the power rule in order to find the outermost function first this would be 15?

\[(f\circ h)'(x)=f(h(x))'=f'(h(x))\cdot h'(x)\]

ok i got this step now i must find the derivative of (cos(piet))^2 right?

ok so i find the derivative of that and that is -sin(piet) right?

ok! thanks! ummm... would this be no wait u lost me

\[(d/dt)(\pi t)=\pi(d/dt)t=?\]

zepdrix :[

im sorry u guys lost me completely

Let's restart everything, haha

nooo don't get lost :D you were so close!

is it just pie?

yayyyy \:D/

pi* lol

\[g(t) = 5\cos^3(\pi t)\]
\[f(x)=5\cos^3(x)\]
\[h(x)= \pi x\]

CHAIN RULE :D

ok how it pi though

how is it pi

\(\large 3*5(cos^2(\pi t))*\frac{d}{dt}cos(\pi t)*\frac{d}{dt}(\pi t)\)***
Sorry

ok !!!! i think i got!!! THANKS SOOOOO MUCH I WAS HAVING TROUBLEE!!!!!!