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darkmare
Group Title
f(x) = 2x^2+4x for x <0 and 8x^23 for x greater or equal to zero
what would the difference quotient's be for lim x>0 and lim x> 0+?
 one year ago
 one year ago
darkmare Group Title
f(x) = 2x^2+4x for x <0 and 8x^23 for x greater or equal to zero what would the difference quotient's be for lim x>0 and lim x> 0+?
 one year ago
 one year ago

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ash2326 Group TitleBest ResponseYou've already chosen the best response.0
Function is defined as: \[f(x)=2x^2+4x, for\ x<0\] \[f(x)=8x^23. for\ x\ge 0\] for limit 0, f(x) defined for x<0 \[\large \lim_{x \to 0^{}} (2x^2+4x)\] for limit 0+, f(x) defined for \(x\ge 0\) \[\large \lim_{x \to 0^{+}} (8x^23)\]
 one year ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.0
@darkmare do you get this?
 one year ago

darkmare Group TitleBest ResponseYou've already chosen the best response.0
yes I understand that for the limit of each one that those are used but the questions asks the lim of those values for f prime (0) so those are not the answers they are looking for apparently
 one year ago

suneja Group TitleBest ResponseYou've already chosen the best response.0
f(x)=−2x2+4x,for x<0 f(x)=8x2−3.for x≥0 for limit 0, f(x) defined for x<0 lim x→0−(−2x2+4x)= 0 for limit 0+, f(x) defined for x≥0 lim x→0+(8x2−3)=3
 one year ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.0
\[\large f'(x)=\lim_{h \to 0^}\frac{f(xh)f(0)}{xhx}\] to evaluate f'(0), from left hand side ( or to check differentiability) put x=0 in this \[\large f'(x)=\lim_{h \to 0^}\frac{2(xh)^2+4(xh)(2x^2+4x)}{xhx}\] now put x=0 in this, for 0+, use f(x)=8x^23
 one year ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.0
do you get it ? @darkmare
 one year ago

darkmare Group TitleBest ResponseYou've already chosen the best response.0
yes I do understand that, it is still not accepting it as an answer so I will have to look into it further, perhaps simplify further
 one year ago

ash2326 Group TitleBest ResponseYou've already chosen the best response.0
yeah, you have to simplify it further.
 one year ago
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