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suneja
Group Title
let g(x)= 1+x[x] and f(x)= 1,x<0
0, x=0
1, x>1
then for all x f[g(x)] is equal to
a)x b)1 c)f(x) g(x)
 2 years ago
 2 years ago
suneja Group Title
let g(x)= 1+x[x] and f(x)= 1,x<0 0, x=0 1, x>1 then for all x f[g(x)] is equal to a)x b)1 c)f(x) g(x)
 2 years ago
 2 years ago

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tamtoan Group TitleBest ResponseYou've already chosen the best response.0
what is [x] ? is it absolute value of x ? if yes, then answer is b
 2 years ago

suneja Group TitleBest ResponseYou've already chosen the best response.0
[x] is the integer fn ( dont knw greatest or smallest integer fn) and the ans is b how did u do dat
 2 years ago

Zekarias Group TitleBest ResponseYou've already chosen the best response.1
[x] is to mean that ' the greatest integer of x'.
 2 years ago

suneja Group TitleBest ResponseYou've already chosen the best response.0
can anyone explain me greatest/smallest integer fn
 2 years ago

suneja Group TitleBest ResponseYou've already chosen the best response.0
so how do u solve for those type functions
 2 years ago

tamtoan Group TitleBest ResponseYou've already chosen the best response.0
thanks zekarias
 2 years ago

tamtoan Group TitleBest ResponseYou've already chosen the best response.0
[x] is greatest integer of x , does it mean if 0 <= x <= 1 then [x] is 1 ? and 3 <= x <= 2 then [x] is 2 ?
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
no, the other way round
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
[1.5] =1 [1.5]=2
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
also called floor function
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
defination :For all real numbers x, the greatest integer function returns the largest integer less than or equal to x.
 2 years ago

Zekarias Group TitleBest ResponseYou've already chosen the best response.1
Here is the answer... For values of x the expression x[x] is b/n 0 and 1 so that 1+x[x] is always above 1. Therefore f([g(x)]) = f(>1)=1 Thus answer B
 2 years ago
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