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suneja

  • 2 years ago

let g(x)= 1+x-[x] and f(x)= -1,x<0 0, x=0 1, x>1 then for all x f[g(x)] is equal to a)x b)1 c)f(x) g(x)

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  1. tamtoan
    • 2 years ago
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    what is [x] ? is it absolute value of x ? if yes, then answer is b

  2. suneja
    • 2 years ago
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    [x] is the integer fn ( dont knw greatest or smallest integer fn) and the ans is b how did u do dat

  3. Zekarias
    • 2 years ago
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    [x] is to mean that ' the greatest integer of x'.

  4. suneja
    • 2 years ago
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    can anyone explain me greatest/smallest integer fn

  5. suneja
    • 2 years ago
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    so how do u solve for those type functions

  6. tamtoan
    • 2 years ago
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    thanks zekarias

  7. tamtoan
    • 2 years ago
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    [x] is greatest integer of x , does it mean if 0 <= x <= 1 then [x] is 1 ? and -3 <= x <= -2 then [x] is -2 ?

  8. hartnn
    • 2 years ago
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    no, the other way round

  9. hartnn
    • 2 years ago
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    [1.5] =1 [-1.5]=-2

  10. hartnn
    • 2 years ago
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    also called floor function

  11. hartnn
    • 2 years ago
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    defination :For all real numbers x, the greatest integer function returns the largest integer less than or equal to x.

  12. Zekarias
    • 2 years ago
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    Here is the answer... For values of x the expression x-[x] is b/n 0 and 1 so that 1+x-[x] is always above 1. Therefore f([g(x)]) = f(>1)=1 Thus answer B

  13. suneja
    • 2 years ago
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    thanks all

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