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suneja
Group Title
let g(x)= 1+x[x] and f(x)= 1,x<0
0, x=0
1, x>1
then for all x f[g(x)] is equal to
a)x b)1 c)f(x) g(x)
 one year ago
 one year ago
suneja Group Title
let g(x)= 1+x[x] and f(x)= 1,x<0 0, x=0 1, x>1 then for all x f[g(x)] is equal to a)x b)1 c)f(x) g(x)
 one year ago
 one year ago

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tamtoan Group TitleBest ResponseYou've already chosen the best response.0
what is [x] ? is it absolute value of x ? if yes, then answer is b
 one year ago

suneja Group TitleBest ResponseYou've already chosen the best response.0
[x] is the integer fn ( dont knw greatest or smallest integer fn) and the ans is b how did u do dat
 one year ago

Zekarias Group TitleBest ResponseYou've already chosen the best response.1
[x] is to mean that ' the greatest integer of x'.
 one year ago

suneja Group TitleBest ResponseYou've already chosen the best response.0
can anyone explain me greatest/smallest integer fn
 one year ago

suneja Group TitleBest ResponseYou've already chosen the best response.0
so how do u solve for those type functions
 one year ago

tamtoan Group TitleBest ResponseYou've already chosen the best response.0
thanks zekarias
 one year ago

tamtoan Group TitleBest ResponseYou've already chosen the best response.0
[x] is greatest integer of x , does it mean if 0 <= x <= 1 then [x] is 1 ? and 3 <= x <= 2 then [x] is 2 ?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
no, the other way round
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
[1.5] =1 [1.5]=2
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
also called floor function
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
defination :For all real numbers x, the greatest integer function returns the largest integer less than or equal to x.
 one year ago

Zekarias Group TitleBest ResponseYou've already chosen the best response.1
Here is the answer... For values of x the expression x[x] is b/n 0 and 1 so that 1+x[x] is always above 1. Therefore f([g(x)]) = f(>1)=1 Thus answer B
 one year ago
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