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suneja

let g(x)= 1+x-[x] and f(x)= -1,x<0 0, x=0 1, x>1 then for all x f[g(x)] is equal to a)x b)1 c)f(x) g(x)

  • one year ago
  • one year ago

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  1. tamtoan
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    what is [x] ? is it absolute value of x ? if yes, then answer is b

    • one year ago
  2. suneja
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    [x] is the integer fn ( dont knw greatest or smallest integer fn) and the ans is b how did u do dat

    • one year ago
  3. Zekarias
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    [x] is to mean that ' the greatest integer of x'.

    • one year ago
  4. suneja
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    can anyone explain me greatest/smallest integer fn

    • one year ago
  5. suneja
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    so how do u solve for those type functions

    • one year ago
  6. tamtoan
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    thanks zekarias

    • one year ago
  7. tamtoan
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    [x] is greatest integer of x , does it mean if 0 <= x <= 1 then [x] is 1 ? and -3 <= x <= -2 then [x] is -2 ?

    • one year ago
  8. hartnn
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    no, the other way round

    • one year ago
  9. hartnn
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    [1.5] =1 [-1.5]=-2

    • one year ago
  10. hartnn
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    also called floor function

    • one year ago
  11. hartnn
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    defination :For all real numbers x, the greatest integer function returns the largest integer less than or equal to x.

    • one year ago
  12. Zekarias
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    Here is the answer... For values of x the expression x-[x] is b/n 0 and 1 so that 1+x-[x] is always above 1. Therefore f([g(x)]) = f(>1)=1 Thus answer B

    • one year ago
  13. suneja
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    thanks all

    • one year ago
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