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options are :
a) \[\frac{3}{4}\]
b)\[\frac{4}{3}\]
c) \[-4\]
d) \[\frac{-4}{3}\]

i think there is easier way out....

^^ exactly

@hartnn: Oh yeah

no solution is of the form:
ax+b=c
ax+b=d

Yes.

@ash2326 gd and then

and why would that have an infinite # of solutions?

because ax+b=c and ax+b=c are satisfied by infinite number of points (x,y) simultaneously.

ash2326's solution is mostly correct

this one doesn't satisfy that

ok! then @Zarkon

3x-4y=7 and x+cy=13
\[x-\frac{4}{3}y=\frac{7}{3}\]
\[x+cy=13\]

yaa ... i also agree with @Zarkon
don't you @mathslover

thus no solution

isn't like this
\[3x-4y=7\]
\[3x=7-4y\]
\[x-y=\frac{7}{12}\]
\[x=\frac{7}{12}+y\]

and then solve it

@mayankdevnani what r u doing?

how did you get it......... @mathslover

ANSWER is correct... but i did'nt understand..... plz tell me once again.....

@mayankdevnani where are you not getting ?

step by step

THAT WAS exactly what I was thinking @mathslover THAT IS ABSOULETLY CORRECT

yes...your way is fine

OK thanks @sauravshakya Let us wait for honorable zarkon sir ..

OK thanks a lot @Zarkon .. that fine made a lot sense sir.. :)

@mathslover how did you get it
\[7+4y=1(13-cy)\]

-4/3

ya.. but how??

that will be a prallal line

got it @mayankdevnani ?

@mayankdevnani clear?

ok... @mathslover

3x-4y=7 and 3x-4y=39 are parallel lines how could they have a solution ..they intersect nowhere

neither do they overlap

:)

@mathslover is my approach correct?