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mayankdevnani
 3 years ago
Given: 3x4y=7 and x+cy=13 , for what value of "c" will the two equations not have a solution?
mayankdevnani
 3 years ago
Given: 3x4y=7 and x+cy=13 , for what value of "c" will the two equations not have a solution?

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mayankdevnani
 3 years ago
Best ResponseYou've already chosen the best response.0options are : a) \[\frac{3}{4}\] b)\[\frac{4}{3}\] c) \[4\] d) \[\frac{4}{3}\]

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2i think there is easier way out....

ash2326
 3 years ago
Best ResponseYou've already chosen the best response.3Rewrite first equation \[x\frac{4}{3}y=7\] for no solution we need to have parallel lines second equation \[x+cy=13\] compare this with the first \[c=\frac{4}{3}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0WELL FOLLOW @ash2326 THAT ONE MUCH EASIER..... agreed with @hartnn

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2no solution is of the form: ax+b=c ax+b=d

mayankdevnani
 3 years ago
Best ResponseYou've already chosen the best response.0@ash2326 gd and then

Zarkon
 3 years ago
Best ResponseYou've already chosen the best response.0and why would that have an infinite # of solutions?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2because ax+b=c and ax+b=c are satisfied by infinite number of points (x,y) simultaneously.

Zarkon
 3 years ago
Best ResponseYou've already chosen the best response.0ash2326's solution is mostly correct

Zarkon
 3 years ago
Best ResponseYou've already chosen the best response.0this one doesn't satisfy that

Zarkon
 3 years ago
Best ResponseYou've already chosen the best response.03x4y=7 and x+cy=13 \[x\frac{4}{3}y=\frac{7}{3}\] \[x+cy=13\]

mayankdevnani
 3 years ago
Best ResponseYou've already chosen the best response.0yaa ... i also agree with @Zarkon don't you @mathslover

Zarkon
 3 years ago
Best ResponseYou've already chosen the best response.0if c=4/3 then you get \[x\frac{4}{3}y=\frac{7}{3}\] and \[x\frac{4}{3}y=13\] ie \[\frac{7}{3}=13\]

mayankdevnani
 3 years ago
Best ResponseYou've already chosen the best response.0isn't like this \[3x4y=7\] \[3x=74y\] \[xy=\frac{7}{12}\] \[x=\frac{7}{12}+y\]

mayankdevnani
 3 years ago
Best ResponseYou've already chosen the best response.0and then solve it

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.5What I did is this : \[\large{7+4y = 3(13cy)}\] \[\large{7+4y=393cy}\] \[\large{32= 4y+3cy}\] We have to find the value of c when the RHS becomes zero which will give no solution. \[\large{4y+3(c)(y)=0}\] \[\large{c = \frac{4y}{3y}}\] \[\large{c=\frac{4}{3}}\] hence at c = 4/3 we get no solutions for the variables in the given two equations .

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@mayankdevnani what r u doing?

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.5@mayankdevnani you need to concentrate hardly on understanding questions... You are solving for x or y but in the question we have to find the value for c which makes the solutions for the equation as null set.

mayankdevnani
 3 years ago
Best ResponseYou've already chosen the best response.0how did you get it......... @mathslover

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.5btw , @Zarkon sir , was my method acceptable? I know there are easy methods too.. but that is what I did..

mayankdevnani
 3 years ago
Best ResponseYou've already chosen the best response.0ANSWER is correct... but i did'nt understand..... plz tell me once again.....

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.5@mayankdevnani where are you not getting ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0THAT WAS exactly what I was thinking @mathslover THAT IS ABSOULETLY CORRECT

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.5OK thanks @sauravshakya Let us wait for honorable zarkon sir ..

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.5OK thanks a lot @Zarkon .. that fine made a lot sense sir.. :)

mayankdevnani
 3 years ago
Best ResponseYou've already chosen the best response.0@mathslover how did you get it \[7+4y=1(13cy)\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0that will be a prallal line

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.53x4y = 7 x = (7+4y) / 3 and then : x + cy = 13 x = 13cy 13cy = (7+4y)/3 (since they are equal to x) 3(13cy) = 7+4y

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.5got it @mayankdevnani ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0just put 4/3 at C and you will have a parallel set of line and parallel set of lines have no solution

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@mayankdevnani clear?

mayankdevnani
 3 years ago
Best ResponseYou've already chosen the best response.0ok... @mathslover

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.03x4y=7 and 3x4y=39 are parallel lines how could they have a solution ..they intersect nowhere

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0neither do they overlap

mayankdevnani
 3 years ago
Best ResponseYou've already chosen the best response.0thnx.... @Zarkon @ghazi @sauravshakya @ash2326 but special thnx to @mathslover

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@mathslover is my approach correct?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Isnt your method same as @ash2326 's method........ @ghazi

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i didn't see ...i just came here read the question and identified these are parallel lines...i guess yes both have same solution and we don't need to solve anything because already it is visible that it's case of parallel line when c= 4/3 hence no solution

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes it is similar to that of @ash2326
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