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Faris_Waleed Group Title

factorise:50a5-8a3b2

  • 2 years ago
  • 2 years ago

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  1. mathslover Group Title
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    take \(a^3\) common @Faris_Waleed What do you get?

    • 2 years ago
  2. Faris_Waleed Group Title
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    a3(50a2-8ab2)

    • 2 years ago
  3. mathslover Group Title
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    good , now take 2 common from 50a2 - 8ab2

    • 2 years ago
  4. Faris_Waleed Group Title
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    2(50a-8ab)

    • 2 years ago
  5. Faris_Waleed Group Title
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    sorry

    • 2 years ago
  6. Faris_Waleed Group Title
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    i meant 2(25a2-4ab2)

    • 2 years ago
  7. jiteshmeghwal9 Group Title
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    i think it is \(50a^2-8ab^2\)

    • 2 years ago
  8. mathslover Group Title
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    \[\large{(a^3)(50a^2-8b^2)}\] \[\large{\color{blue}{a^3 (2)(25a^2-4b^2)}}\] \[\large{\color{green}{2a^3(25a^2-4b^2)}}\]

    • 2 years ago
  9. mathslover Group Title
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    now we have : \[\large{a^2-b^2 = \color{blue}{(a+b)(a-b)}}\] \[\large{(2a^3)\color{green}{(5a)^2-(2b)^2})}\] \[\large{(2a^3)\color{blue}{(5a+2b)(5a-2b)}}\]

    • 2 years ago
  10. Faris_Waleed Group Title
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    yes thats the answer i got in my notebook

    • 2 years ago
  11. jiteshmeghwal9 Group Title
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    @mathslover is right , forever ;)

    • 2 years ago
  12. mathslover Group Title
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    thanks @jiteshmeghwal9

    • 2 years ago
  13. jiteshmeghwal9 Group Title
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    you deserved that ;)

    • 2 years ago
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