anonymous
  • anonymous
factorise:50a5-8a3b2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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mathslover
  • mathslover
take \(a^3\) common @Faris_Waleed What do you get?
anonymous
  • anonymous
a3(50a2-8ab2)
mathslover
  • mathslover
good , now take 2 common from 50a2 - 8ab2

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anonymous
  • anonymous
2(50a-8ab)
anonymous
  • anonymous
sorry
anonymous
  • anonymous
i meant 2(25a2-4ab2)
jiteshmeghwal9
  • jiteshmeghwal9
i think it is \(50a^2-8ab^2\)
mathslover
  • mathslover
\[\large{(a^3)(50a^2-8b^2)}\] \[\large{\color{blue}{a^3 (2)(25a^2-4b^2)}}\] \[\large{\color{green}{2a^3(25a^2-4b^2)}}\]
mathslover
  • mathslover
now we have : \[\large{a^2-b^2 = \color{blue}{(a+b)(a-b)}}\] \[\large{(2a^3)\color{green}{(5a)^2-(2b)^2})}\] \[\large{(2a^3)\color{blue}{(5a+2b)(5a-2b)}}\]
anonymous
  • anonymous
yes thats the answer i got in my notebook
jiteshmeghwal9
  • jiteshmeghwal9
@mathslover is right , forever ;)
mathslover
  • mathslover
thanks @jiteshmeghwal9
jiteshmeghwal9
  • jiteshmeghwal9
you deserved that ;)

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