Faris_Waleed
factorise:50a5-8a3b2
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mathslover
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take \(a^3\) common @Faris_Waleed What do you get?
Faris_Waleed
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a3(50a2-8ab2)
mathslover
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good , now take 2 common from 50a2 - 8ab2
Faris_Waleed
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2(50a-8ab)
Faris_Waleed
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sorry
Faris_Waleed
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i meant 2(25a2-4ab2)
jiteshmeghwal9
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i think it is \(50a^2-8ab^2\)
mathslover
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\[\large{(a^3)(50a^2-8b^2)}\]
\[\large{\color{blue}{a^3 (2)(25a^2-4b^2)}}\]
\[\large{\color{green}{2a^3(25a^2-4b^2)}}\]
mathslover
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now we have :
\[\large{a^2-b^2 = \color{blue}{(a+b)(a-b)}}\]
\[\large{(2a^3)\color{green}{(5a)^2-(2b)^2})}\]
\[\large{(2a^3)\color{blue}{(5a+2b)(5a-2b)}}\]
Faris_Waleed
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yes thats the answer i got in my notebook
jiteshmeghwal9
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@mathslover is right , forever ;)
mathslover
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thanks @jiteshmeghwal9
jiteshmeghwal9
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you deserved that ;)