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Faris_Waleed

  • 3 years ago

factorise:50a5-8a3b2

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  1. mathslover
    • 3 years ago
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    take \(a^3\) common @Faris_Waleed What do you get?

  2. Faris_Waleed
    • 3 years ago
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    a3(50a2-8ab2)

  3. mathslover
    • 3 years ago
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    good , now take 2 common from 50a2 - 8ab2

  4. Faris_Waleed
    • 3 years ago
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    2(50a-8ab)

  5. Faris_Waleed
    • 3 years ago
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    sorry

  6. Faris_Waleed
    • 3 years ago
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    i meant 2(25a2-4ab2)

  7. jiteshmeghwal9
    • 3 years ago
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    i think it is \(50a^2-8ab^2\)

  8. mathslover
    • 3 years ago
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    \[\large{(a^3)(50a^2-8b^2)}\] \[\large{\color{blue}{a^3 (2)(25a^2-4b^2)}}\] \[\large{\color{green}{2a^3(25a^2-4b^2)}}\]

  9. mathslover
    • 3 years ago
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    now we have : \[\large{a^2-b^2 = \color{blue}{(a+b)(a-b)}}\] \[\large{(2a^3)\color{green}{(5a)^2-(2b)^2})}\] \[\large{(2a^3)\color{blue}{(5a+2b)(5a-2b)}}\]

  10. Faris_Waleed
    • 3 years ago
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    yes thats the answer i got in my notebook

  11. jiteshmeghwal9
    • 3 years ago
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    @mathslover is right , forever ;)

  12. mathslover
    • 3 years ago
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    thanks @jiteshmeghwal9

  13. jiteshmeghwal9
    • 3 years ago
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    you deserved that ;)

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