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Turner

  • 2 years ago

If tan x ̊= 3/y and cos x ̊= y/z , what is the value of sin x°? sin x°= 3/z sin x°= 3y sin x°= z/3 sin x°= 3z

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  1. Turner
    • 2 years ago
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  2. mraarm
    • 2 years ago
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    Remember that tan(x) = sin(x) / cos(x)

  3. mathslover
    • 2 years ago
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    \[\large{\tan x = \frac{3}{y}}\] \[\large{\cos x = \frac{y}{z}}\] since : \(\large{\tan x = \frac{\sin x}{\cos x}}\) @Turner put the given values of tan x and cos x in the formula (above) ... Can you tell me what do you get ?

  4. Turner
    • 2 years ago
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    is it \[\frac{ 3z }{ y ^{2} }\] ???

  5. mathslover
    • 2 years ago
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    \[\large{\frac{3}{y}=\frac{\sin x }{\frac{y}{z}}}\] \[\large{\frac{3}{y}\times \frac{y}{z}=\sin x}\] \[\large{\frac{3}{z}=\sin x}\]

  6. mathslover
    • 2 years ago
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    Check your process again @Turner ...

  7. Turner
    • 2 years ago
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    ohhh okay! thankyou!!!

  8. mathslover
    • 2 years ago
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    You're always welcome. Best of luck.

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