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tvise

b^2+16b+1=0 is the answer b=8+3root7?

  • one year ago
  • one year ago

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  1. mathslover
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    \[\large{x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}}\] are you sure that you applied this formula?

    • one year ago
  2. tvise
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    It says complete the square do i still do the quadratic formula?

    • one year ago
  3. radar
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    If requests that you complete the square, you should do so. I think you have it almost whipped, check your signs.

    • one year ago
  4. tvise
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    ahh it should be a - 8

    • one year ago
  5. mathslover
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    no if it says complete the square then : \[\large{b^2+16b+1=0}\] \[\large{b^2+16b+1+64=0+64}\] \[\large{(b+8)^2 = 63}\] \[\large{b = \sqrt{63} -8}\]

    • one year ago
  6. radar
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    I came up with:\[-8\pm3\sqrt{7}\]

    • one year ago
  7. mathslover
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    \[\large{b = -8 \pm \sqrt{63}}\] \[\large{b = -8 \pm 3\sqrt{7}}\]

    • one year ago
  8. radar
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    Note that \[\sqrt{63}=\sqrt{9}\sqrt{7}\]

    • one year ago
  9. mathslover
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    got it @tvise ?

    • one year ago
  10. tvise
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    Yes. When i originally did it i did not isolate the variable so when i re did it i forgot to change signs

    • one year ago
  11. mathslover
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    no problem, take care of it from now, :)

    • one year ago
  12. radar
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    Good luck, and the "signs" can bite you. lol

    • one year ago
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