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mathslover Group TitleBest ResponseYou've already chosen the best response.2
\[\large{x=\frac{b \pm \sqrt{b^24ac}}{2a}}\] are you sure that you applied this formula?
 2 years ago

tvise Group TitleBest ResponseYou've already chosen the best response.0
It says complete the square do i still do the quadratic formula?
 2 years ago

radar Group TitleBest ResponseYou've already chosen the best response.1
If requests that you complete the square, you should do so. I think you have it almost whipped, check your signs.
 2 years ago

tvise Group TitleBest ResponseYou've already chosen the best response.0
ahh it should be a  8
 2 years ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
no if it says complete the square then : \[\large{b^2+16b+1=0}\] \[\large{b^2+16b+1+64=0+64}\] \[\large{(b+8)^2 = 63}\] \[\large{b = \sqrt{63} 8}\]
 2 years ago

radar Group TitleBest ResponseYou've already chosen the best response.1
I came up with:\[8\pm3\sqrt{7}\]
 2 years ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
\[\large{b = 8 \pm \sqrt{63}}\] \[\large{b = 8 \pm 3\sqrt{7}}\]
 2 years ago

radar Group TitleBest ResponseYou've already chosen the best response.1
Note that \[\sqrt{63}=\sqrt{9}\sqrt{7}\]
 2 years ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
got it @tvise ?
 2 years ago

tvise Group TitleBest ResponseYou've already chosen the best response.0
Yes. When i originally did it i did not isolate the variable so when i re did it i forgot to change signs
 2 years ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
no problem, take care of it from now, :)
 2 years ago

radar Group TitleBest ResponseYou've already chosen the best response.1
Good luck, and the "signs" can bite you. lol
 2 years ago
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