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mathslover
 2 years ago
Best ResponseYou've already chosen the best response.2\[\large{x=\frac{b \pm \sqrt{b^24ac}}{2a}}\] are you sure that you applied this formula?

tvise
 2 years ago
Best ResponseYou've already chosen the best response.0It says complete the square do i still do the quadratic formula?

radar
 2 years ago
Best ResponseYou've already chosen the best response.1If requests that you complete the square, you should do so. I think you have it almost whipped, check your signs.

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.2no if it says complete the square then : \[\large{b^2+16b+1=0}\] \[\large{b^2+16b+1+64=0+64}\] \[\large{(b+8)^2 = 63}\] \[\large{b = \sqrt{63} 8}\]

radar
 2 years ago
Best ResponseYou've already chosen the best response.1I came up with:\[8\pm3\sqrt{7}\]

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.2\[\large{b = 8 \pm \sqrt{63}}\] \[\large{b = 8 \pm 3\sqrt{7}}\]

radar
 2 years ago
Best ResponseYou've already chosen the best response.1Note that \[\sqrt{63}=\sqrt{9}\sqrt{7}\]

tvise
 2 years ago
Best ResponseYou've already chosen the best response.0Yes. When i originally did it i did not isolate the variable so when i re did it i forgot to change signs

mathslover
 2 years ago
Best ResponseYou've already chosen the best response.2no problem, take care of it from now, :)

radar
 2 years ago
Best ResponseYou've already chosen the best response.1Good luck, and the "signs" can bite you. lol
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