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tvise

  • 3 years ago

b^2+16b+1=0 is the answer b=8+3root7?

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  1. mathslover
    • 3 years ago
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    \[\large{x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}}\] are you sure that you applied this formula?

  2. tvise
    • 3 years ago
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    It says complete the square do i still do the quadratic formula?

  3. radar
    • 3 years ago
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    If requests that you complete the square, you should do so. I think you have it almost whipped, check your signs.

  4. tvise
    • 3 years ago
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    ahh it should be a - 8

  5. mathslover
    • 3 years ago
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    no if it says complete the square then : \[\large{b^2+16b+1=0}\] \[\large{b^2+16b+1+64=0+64}\] \[\large{(b+8)^2 = 63}\] \[\large{b = \sqrt{63} -8}\]

  6. radar
    • 3 years ago
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    I came up with:\[-8\pm3\sqrt{7}\]

  7. mathslover
    • 3 years ago
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    \[\large{b = -8 \pm \sqrt{63}}\] \[\large{b = -8 \pm 3\sqrt{7}}\]

  8. radar
    • 3 years ago
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    Note that \[\sqrt{63}=\sqrt{9}\sqrt{7}\]

  9. mathslover
    • 3 years ago
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    got it @tvise ?

  10. tvise
    • 3 years ago
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    Yes. When i originally did it i did not isolate the variable so when i re did it i forgot to change signs

  11. mathslover
    • 3 years ago
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    no problem, take care of it from now, :)

  12. radar
    • 3 years ago
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    Good luck, and the "signs" can bite you. lol

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