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j23 Group TitleBest ResponseYou've already chosen the best response.0
if i have N would it be 73= zeff?
 2 years ago

benjaminf Group TitleBest ResponseYou've already chosen the best response.1
Ah, I think it's actually 72=5. If you go back to the s, p, d, f shells, there are only two inner electrons that shield the valence electrons from the 7 protons in the nucleus. so Zeff = Z  S, with Z = 7 and S = 2
 2 years ago

Carl_Pham Group TitleBest ResponseYou've already chosen the best response.0
The simplest way is simply to assume all inner electrons shield perfectly, so Zeff = Z  n_ve, where n_ve = number of valence electrons. That gives a Zeff that begins with +1 in Group 1A and advances by 1 for each A group, ending in +8 for Group 8A. Zeff for the transition metals is hard to get by this method, and the method generally does poorly for Period 3 and below. You can be more sophisticated by using "Slater's Rules" (which you can google), which assign a certain fraction of a +1 charge canceled by each electron, depending on its particular n and l values. You can also look up sophisticated calculations on webelements.com.
 2 years ago

j23 Group TitleBest ResponseYou've already chosen the best response.0
Ok thank you . i dont think i need to use slaters rule just yet.another question so if i was trying to calculate the Zeff of Ti Since its in the 3D^2 how would i do that
 2 years ago

Carl_Pham Group TitleBest ResponseYou've already chosen the best response.0
I would include the 3d as well as 4s electrons for the first transition series, so Ti would have Zeff = +4.
 2 years ago
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