## A community for students. Sign up today

Here's the question you clicked on:

## ghazi 3 years ago dividing rational numbers

• This Question is Closed
1. mukushla

lol...why u closed it?

2. ghazi

guys this is for a kid ...thanks for your coperation and muku...is your question scalared value tensor?

3. ghazi

|dw:1348682390341:dw| this way we divide rational number p/q lets say your question is 7/5 @vikayefremova can you take a pain to come here

4. mukushla

yeah

5. ghazi

@mukushla see you soon :)

6. ghazi

|dw:1348682537294:dw|

7. vikayefremova

this is not the problem, im trying to figure out how to do this.. |dw:1348682653856:dw|

8. ghazi

we have to divide 7 by 5 ....so first of all multiply 5 by 1 write 1 in the quotient..now write 5 underneath 7 , now subtract 5 from 7 your remainder is 2 ..after that you can divide it further, then use decimal ...putting a decimal will bring a zero in front of remainder 2 it will become 20 ///now multiply 5 by4 you'll get 20 and subtract 20 from 20 your division is over since remainder is zero ...okay?

9. ghazi

$\frac{ 2 }{ 6 }\div \frac{ 5 }{ 7 }= \frac{ 2 }{ 6 }*\frac{ 7 }{ 5 }$

10. vikayefremova

cross multiply?

11. ghazi

the term after the divisional sign is take as inverse ....|dw:1348682884282:dw|

12. ghazi

$\frac{ 2*7 }{ 6*5 }$ clear?

13. ghazi

it is not cross multiplication

14. vikayefremova

oh okay.. let me see :P

15. ghazi

you'll get $\frac{ 7 }{ 15 }$

16. vikayefremova

oh

17. ghazi

still confused?

18. vikayefremova

yeahh :/

19. ghazi

|dw:1348683051435:dw|

20. ghazi

now?

21. vikayefremova

maybe..

22. ghazi

see 6/2=3 ...similarly just think |dw:1348683164352:dw|

23. ghazi

2*3=6 and $\frac{ 2*3 }{ 2}=\frac{ 6 }{ 2 }=3$ now?

24. vikayefremova

yes i think i got it.. thanks!

25. ghazi

|dw:1348683269161:dw|

26. ghazi

|dw:1348683491745:dw| just divide numerator and denominator by 2 ...now?

27. ghazi

2/2=1 and 6/2=3

28. vikayefremova

okay i understand, thanks

29. ghazi

yea i know :)

30. ghazi

it's nothing just a formula for rational number division$\frac{ p }{ q }\div \frac{ r }{ s }=\frac{ p }{ q }*\frac{ s }{ r }=\frac{ p*s }{ q*r }$ this is a general formula :)

31. vikayefremova

okay thanks :)

32. ghazi

@vikayefremova

33. ghazi

question ??

34. vikayefremova

umm.. wait a just sec!

35. ghazi

k

36. vikayefremova

37. ghazi

$10^{-7}= 0.0000001$ just add number of (n-1) zero in front of one..means one less zero after decimal then the given power...here power is 7 you need to put 6 zeroes and 1 after decimal

38. vikayefremova

okay thanks

39. ghazi

next

40. vikayefremova

41. vikayefremova

?

42. ghazi

calculate the values

43. ghazi

3^4=81 which is the biggest of all

44. vikayefremova

okay :) next...

45. ghazi

area of square = side*side=x^2=225 x=15 she needs to fence...3 sides so total length= 15+15+15=45

46. ghazi

@vikayefremova ??

47. vikayefremova

thanks :D

48. ghazi

next

49. vikayefremova

50. ghazi

$-\sqrt{456}=-21.35$ and this lies between D

51. ghazi

-22 and -21 ..next

52. vikayefremova

53. ghazi

$5.3*10^{-3}$

54. vikayefremova

okay :)

55. ghazi

next ....

56. vikayefremova

57. ghazi

fencing = perimeter.... now let's say side= x area of square= x^2= 2000 x= 44.72 fencing= 44.72*4= 179

58. vikayefremova

59. ghazi

$\frac{ \sqrt{25} }{ \sqrt{16} }+\frac{ 3 }{ 4 }=\frac{ 5 }{ 4 }+\frac{ 3 }{ 4 }$

60. ghazi

8/4=2

61. vikayefremova

62. ghazi

5,600,000

63. vikayefremova

64. ghazi

6*6*6=216=volume

65. ghazi

S=6, volume= s*s*s=6*6*6=216

66. vikayefremova

67. ghazi

$3^2+5^0+2^{-2}=9+1+\frac{ 1 }{ 4 }=\frac{ 36+4+1 }{ 4 }=\frac{ 41 }{ 4 }=10\frac{ 1 }{ 4 }$

68. ghazi

$10\frac{ 1 }{ 4 }=\frac{ 10*4+1 }{ 4 }=\frac{ 41 }{ 4 }$ clear?

69. vikayefremova

yes.. clear, thank you :)

70. ghazi

next

71. vikayefremova

72. ghazi

$\frac{ 10^9 }{ 10^5 }=10^{9-5}=10^4$ bases are same power will be subtracted in division

73. vikayefremova

okay :D

74. ghazi

you've got a lot more in line....next?

75. vikayefremova

76. vikayefremova

just a few more ;)

77. vikayefremova

only 15 questions..

78. ghazi

anything divided by zero...is infinity..so it is not a real number

79. ghazi

only 15 hahaha

80. vikayefremova

yes :)

81. ghazi

next

82. vikayefremova

83. vikayefremova

2 more questions left! :P

84. ghazi

$8.8^8=8^{8+1}=8^9$ bases are same..so power will be added in multiplication

85. ghazi

don't worry...doesn't matter you've left with 100 or 10 ..keep shooting

86. vikayefremova

okay, last one.. for sure :D

87. ghazi

$\frac{ -4 }{ 2 }=\frac{ -2 }{ 1 }$

88. ghazi

don't worry about it..next

89. vikayefremova

well that is it.. thanks! :D

90. ghazi

i said not to worry..

91. vikayefremova

wow.. :) thank you

92. ghazi

where we made the mistake? by thats awesome...you did it :) congrats

93. ghazi

*by the way

94. vikayefremova

i forgot to answer one more question.. but still this is very good, thank you soo much :) i would'v never done this without you :)

95. ghazi

damn....can't you do the one that you have left with

96. vikayefremova

nope.. i can only try once.. too late :D

97. ghazi

hmm...

98. vikayefremova

yeahh :)

99. ghazi

@vikayefremova next?

100. vikayefremova

101. ghazi

we have done this..

102. vikayefremova

nope this is different one, it just looks like it :P

103. ghazi

come on it asks for the volume of cube which is = side*side*side=6*6*6=216

104. vikayefremova

all you have to do is multiply?? no division?

105. ghazi

no...it is already give in your question that volume=$s^3= s*s*s$ since s=6

106. ghazi

6*6*6=216

107. ghazi

@vikayefremova clear? if yes then next

108. vikayefremova

yes clear :) i didnt know it was that easy.. lol

109. ghazi

$(-8)(-8)(-8)*h=(-8)^{1+1+1}*h=(-8)^3*h$ since bases are same ..power will be added ...and power of (-8) is 1

110. vikayefremova

thanks :D

111. ghazi

$d=16*t^2=16*(3)^2=16*9=144$ you have to put t=3 in the given formula to find out distance traveled

112. ghazi

@vikayefremova next

113. ghazi

?

114. vikayefremova

how do i find the greatest value?? multiply?

115. ghazi

2^5=2*2*2*2*2=32 similarly 3^4=3*3*3*3 4^3=4*4*4 5^2=5*5

116. vikayefremova

ohhh :D i see.. thanks! i get it now :D

117. ghazi

cool

118. vikayefremova

119. ghazi

$(-6)^{-2}=\frac{ 1 }{ (-6)^2 }=\frac{ 1 }{ 36 }$

120. ghazi

$x^{-b}=\frac{ 1 }{ x^b }$

121. vikayefremova

122. ghazi

$8^0-(11-2^4)^{-2}=1-(11-2*2*2*2)^{-2}=1-(11-16)^{-2}=1-(-5)^{-2}$ then $1-(-5)^{-2}=1-\frac{ 1 }{ (-5)^2 }=1-\frac{ 1 }{ 25 }=\frac{ 25-1 }{ 25 }=\frac{ 24 }{ 25 }$

123. ghazi

$a^0=1$

124. ghazi

@vikayefremova clear?

125. vikayefremova

yes, clear :) thank you

126. ghazi

:)

127. vikayefremova

128. ghazi

$4.2^{-3}+10^{-1}=4*\frac{ 1 }{ 2^3 }+\frac{ 1 }{ 10 }=\frac{ 4 }{ 8 }+\frac{ 1 }{ 10 }$ then $\frac{ 4 }{ 8 }+\frac{ 1 }{ 10 }=\frac{ 1 }{ 2 }+\frac{ 1 }{ 10 }=\frac{ 5+1 }{ 10 }=\frac{ 6 }{ 10 }=\frac{ 3 }{ 5 }$

129. ghazi

??

130. vikayefremova

|dw:1348739944093:dw|

131. ghazi

:)

132. ghazi

$3^{-2}=\frac{ 1 }{ 3^2 }=\frac{ 1 }{ 3*3 }$ can you do the rest?

133. vikayefremova

1/9?

134. ghazi

yea yea :)

135. vikayefremova

yayy :P thats was soo hard :P lol

136. ghazi

:D

137. vikayefremova

soo.. next?? :P

138. ghazi

of course...next please

139. vikayefremova

this is too much..

140. ghazi

??

141. vikayefremova

lol i think you just showed me how to do this :/

142. ghazi

yea yea..wait a sec :)

143. ghazi

$10^{-3}=\frac{ 1 }{ 1000 }=0.001$

144. vikayefremova

:D

145. ghazi

clear?

146. vikayefremova

sure.. let me just write this down, im afraid i might forget this in a few minutes :P lol

147. ghazi

cool

148. vikayefremova

thanks :)

149. ghazi

next?

150. vikayefremova

um.. i think thats it for now :/

151. vikayefremova

i mean for this assignment :P

152. ghazi

fine

153. vikayefremova

okay fine, one more... Evaluate: (-8)0

154. ghazi

-8*0=0 ..anything multiplied by 0 =0

155. vikayefremova

ohh okay, well thats it :)

156. ghazi

you sure ?

157. vikayefremova

yup.. well im not done with everything.. i mean am done with this assignment.. :D

#### Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy