Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

dividing rational numbers

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

lol...why u closed it?
guys this is for a kid ...thanks for your coperation and muku...is your question scalared value tensor?
|dw:1348682390341:dw| this way we divide rational number p/q lets say your question is 7/5 @vikayefremova can you take a pain to come here

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

yeah
@mukushla see you soon :)
|dw:1348682537294:dw|
this is not the problem, im trying to figure out how to do this.. |dw:1348682653856:dw|
we have to divide 7 by 5 ....so first of all multiply 5 by 1 write 1 in the quotient..now write 5 underneath 7 , now subtract 5 from 7 your remainder is 2 ..after that you can divide it further, then use decimal ...putting a decimal will bring a zero in front of remainder 2 it will become 20 ///now multiply 5 by4 you'll get 20 and subtract 20 from 20 your division is over since remainder is zero ...okay?
\[\frac{ 2 }{ 6 }\div \frac{ 5 }{ 7 }= \frac{ 2 }{ 6 }*\frac{ 7 }{ 5 }\]
cross multiply?
the term after the divisional sign is take as inverse ....|dw:1348682884282:dw|
\[\frac{ 2*7 }{ 6*5 }\] clear?
it is not cross multiplication
oh okay.. let me see :P
you'll get \[\frac{ 7 }{ 15 }\]
oh
still confused?
yeahh :/
|dw:1348683051435:dw|
now?
maybe..
see 6/2=3 ...similarly just think |dw:1348683164352:dw|
2*3=6 and \[\frac{ 2*3 }{ 2}=\frac{ 6 }{ 2 }=3\] now?
yes i think i got it.. thanks!
|dw:1348683269161:dw|
|dw:1348683491745:dw| just divide numerator and denominator by 2 ...now?
2/2=1 and 6/2=3
okay i understand, thanks
yea i know :)
it's nothing just a formula for rational number division\[\frac{ p }{ q }\div \frac{ r }{ s }=\frac{ p }{ q }*\frac{ s }{ r }=\frac{ p*s }{ q*r }\] this is a general formula :)
okay thanks :)
question ??
umm.. wait a just sec!
k
1 Attachment
\[10^{-7}= 0.0000001\] just add number of (n-1) zero in front of one..means one less zero after decimal then the given power...here power is 7 you need to put 6 zeroes and 1 after decimal
okay thanks
next
1 Attachment
?
calculate the values
3^4=81 which is the biggest of all
okay :) next...
1 Attachment
area of square = side*side=x^2=225 x=15 she needs to fence...3 sides so total length= 15+15+15=45
thanks :D
next
1 Attachment
\[-\sqrt{456}=-21.35\] and this lies between D
-22 and -21 ..next
1 Attachment
\[5.3*10^{-3}\]
okay :)
next ....
1 Attachment
fencing = perimeter.... now let's say side= x area of square= x^2= 2000 x= 44.72 fencing= 44.72*4= 179
\[\frac{ \sqrt{25} }{ \sqrt{16} }+\frac{ 3 }{ 4 }=\frac{ 5 }{ 4 }+\frac{ 3 }{ 4 }\]
8/4=2
1 Attachment
5,600,000
1 Attachment
6*6*6=216=volume
S=6, volume= s*s*s=6*6*6=216
1 Attachment
\[3^2+5^0+2^{-2}=9+1+\frac{ 1 }{ 4 }=\frac{ 36+4+1 }{ 4 }=\frac{ 41 }{ 4 }=10\frac{ 1 }{ 4 }\]
\[10\frac{ 1 }{ 4 }=\frac{ 10*4+1 }{ 4 }=\frac{ 41 }{ 4 }\] clear?
yes.. clear, thank you :)
next
\[\frac{ 10^9 }{ 10^5 }=10^{9-5}=10^4\] bases are same power will be subtracted in division
okay :D
you've got a lot more in line....next?
1 Attachment
just a few more ;)
only 15 questions..
anything divided by zero...is infinity..so it is not a real number
only 15 hahaha
yes :)
next
1 Attachment
2 more questions left! :P
\[8.8^8=8^{8+1}=8^9\] bases are same..so power will be added in multiplication
don't worry...doesn't matter you've left with 100 or 10 ..keep shooting
okay, last one.. for sure :D
1 Attachment
\[\frac{ -4 }{ 2 }=\frac{ -2 }{ 1 }\]
don't worry about it..next
well that is it.. thanks! :D
i said not to worry..
wow.. :) thank you
1 Attachment
where we made the mistake? by thats awesome...you did it :) congrats
*by the way
i forgot to answer one more question.. but still this is very good, thank you soo much :) i would'v never done this without you :)
damn....can't you do the one that you have left with
nope.. i can only try once.. too late :D
hmm...
yeahh :)
1 Attachment
we have done this..
nope this is different one, it just looks like it :P
come on it asks for the volume of cube which is = side*side*side=6*6*6=216
all you have to do is multiply?? no division?
no...it is already give in your question that volume=\[s^3= s*s*s\] since s=6
6*6*6=216
@vikayefremova clear? if yes then next
yes clear :) i didnt know it was that easy.. lol
1 Attachment
\[(-8)(-8)(-8)*h=(-8)^{1+1+1}*h=(-8)^3*h\] since bases are same ..power will be added ...and power of (-8) is 1
thanks :D
1 Attachment
\[d=16*t^2=16*(3)^2=16*9=144\] you have to put t=3 in the given formula to find out distance traveled
?
how do i find the greatest value?? multiply?
1 Attachment
2^5=2*2*2*2*2=32 similarly 3^4=3*3*3*3 4^3=4*4*4 5^2=5*5
ohhh :D i see.. thanks! i get it now :D
cool
1 Attachment
\[(-6)^{-2}=\frac{ 1 }{ (-6)^2 }=\frac{ 1 }{ 36 }\]
\[x^{-b}=\frac{ 1 }{ x^b }\]
1 Attachment
\[8^0-(11-2^4)^{-2}=1-(11-2*2*2*2)^{-2}=1-(11-16)^{-2}=1-(-5)^{-2}\] then \[1-(-5)^{-2}=1-\frac{ 1 }{ (-5)^2 }=1-\frac{ 1 }{ 25 }=\frac{ 25-1 }{ 25 }=\frac{ 24 }{ 25 }\]
\[a^0=1\]
yes, clear :) thank you
:)
1 Attachment
\[4.2^{-3}+10^{-1}=4*\frac{ 1 }{ 2^3 }+\frac{ 1 }{ 10 }=\frac{ 4 }{ 8 }+\frac{ 1 }{ 10 }\] then \[\frac{ 4 }{ 8 }+\frac{ 1 }{ 10 }=\frac{ 1 }{ 2 }+\frac{ 1 }{ 10 }=\frac{ 5+1 }{ 10 }=\frac{ 6 }{ 10 }=\frac{ 3 }{ 5 }\]
??
|dw:1348739944093:dw|
:)
\[3^{-2}=\frac{ 1 }{ 3^2 }=\frac{ 1 }{ 3*3 }\] can you do the rest?
1/9?
yea yea :)
yayy :P thats was soo hard :P lol
:D
soo.. next?? :P
of course...next please
this is too much..
??
lol i think you just showed me how to do this :/
yea yea..wait a sec :)
\[10^{-3}=\frac{ 1 }{ 1000 }=0.001\]
:D
clear?
sure.. let me just write this down, im afraid i might forget this in a few minutes :P lol
cool
thanks :)
next?
um.. i think thats it for now :/
i mean for this assignment :P
fine
okay fine, one more... Evaluate: (-8)0
-8*0=0 ..anything multiplied by 0 =0
ohh okay, well thats it :)
you sure ?
yup.. well im not done with everything.. i mean am done with this assignment.. :D

Not the answer you are looking for?

Search for more explanations.

Ask your own question