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Alright, freshman accelerated honors geometry problem. I need ton of help. How do you find the distance between a point and a line?
Ex:
Line L contains points (11,1) and (3,11). Point P has coordinates (1,1).
HELP.
 one year ago
 one year ago
Alright, freshman accelerated honors geometry problem. I need ton of help. How do you find the distance between a point and a line? Ex: Line L contains points (11,1) and (3,11). Point P has coordinates (1,1). HELP.
 one year ago
 one year ago

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LukecrayonzBest ResponseYou've already chosen the best response.1
Ever consider you shouldn't be in accelerated honors geometry?
 one year ago

321drew123Best ResponseYou've already chosen the best response.0
No? This is actually the only topic we've covered that I don't understand. I feel like that was an insult...
 one year ago

estudierBest ResponseYou've already chosen the best response.0
Slope of line L gives you slope of perpendicular.....
 one year ago

yummydumBest ResponseYou've already chosen the best response.1
okay so you need to use the distance formula to find the distance between two points :) \[d=\sqrt {(y_2y_1)+(x_2x_1)}\]
 one year ago

cgreenwade2000Best ResponseYou've already chosen the best response.0
estudier? What?
 one year ago

LukecrayonzBest ResponseYou've already chosen the best response.1
Find midpoint between the two points on the given line, use distance formula to find the distance between the given point and the midpoint.
 one year ago

yummydumBest ResponseYou've already chosen the best response.1
so using that you would get \[L=\sqrt{(11+1)+(311)}\]
 one year ago

321drew123Best ResponseYou've already chosen the best response.0
All I know is that I need to find the point the coordinate is closest to on the line, then use the slope to find the length of the line its used to.
 one year ago

LukecrayonzBest ResponseYou've already chosen the best response.1
No, Yummy, this is the correct way.
 one year ago

321drew123Best ResponseYou've already chosen the best response.0
yummydum, thats the distance from an endpoint to the point, not the line.
 one year ago

yummydumBest ResponseYou've already chosen the best response.1
okay well go with what sire crayon has to saay
 one year ago

LukecrayonzBest ResponseYou've already chosen the best response.1
You're finding a farther distance than needed
 one year ago

yummydumBest ResponseYou've already chosen the best response.1
i was getting to that
 one year ago

estudierBest ResponseYou've already chosen the best response.0
http://math.ucsd.edu/~wgarner/math4c/derivations/distance/distptline.htm
 one year ago

LukecrayonzBest ResponseYou've already chosen the best response.1
http://screensnapr.com/v/14wXYK.jpg
 one year ago

LukecrayonzBest ResponseYou've already chosen the best response.1
Explanation, answer is 8.6.
 one year ago

LukecrayonzBest ResponseYou've already chosen the best response.1
@yummydum your distance was 12.17, much farther than the actual distance.
 one year ago

321drew123Best ResponseYou've already chosen the best response.0
estudier that is not how i remember us learning it in school, we learned a shorter way
 one year ago

estudierBest ResponseYou've already chosen the best response.0
It is short, they are just explaining everything in great detail.
 one year ago

yummydumBest ResponseYou've already chosen the best response.1
again...that wasnt my final answer i was getting to the point...but i see uve got this covered
 one year ago

LukecrayonzBest ResponseYou've already chosen the best response.1
estudier that makes it look very confusing :P
 one year ago

321drew123Best ResponseYou've already chosen the best response.0
Ok i think i understand it now. Thanks Luke
 one year ago
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