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Ignore resistance

7.9 seconds.

OH, show the work. Right haha. I thought it was a joke question so I just put the answer.

haha I was going to make him start with m/s^2

@cgreenwade2000 aww man.. we should've done that!

\[1000=32.2t ^{2}\]

Awesome! I will have to print this out and take to my teacher :)

Let us now compute the velocity that your turkey has when it hits the ground. Knowing that the y-component or the vertical component is subject to gravitational attraction of 32.2ft/s^2 and keeping in mind that gravity attracts downwards, we write the equation,\[s_y=-\frac{1}{2}at^2\]Take the derivative,\[v_y=-at\]Let's for the sake of the argument assume that t=7.8811 is the actual correct answer. We input that here and compute,\[v_y=-32.2*7.8811=-253.77\]Now, using the equation we've derived, namely \[s=v_0t+\frac{1}{2}at^2\]We create a scenario where we first throw the turkey 1000ft up, and then it falls down. To do this we know that the initial speed is 253.77[ft/s] so we input that as v0=253.77.\[s(t)=253.77t-\frac{1}{2}32.2t^2\]Note the minus sign in the equation comes from the fact that acceleration pulls downwards. Now let's plot this and see what happens. As you can see the object first goes to 1000ft from our throw, then goes down in a matter of 7.8811 seconds. Exactly equal to the time it takes to go to 1000ft, if we were to throw it.