## Renee99 3 years ago Chemistry question: What is the mass, in grams, of a sample of 6.12 × 1024 atoms of manganese (Mn)? 6.12x10^24 atoms x 1 mol/6.02x10^23 atoms = 10.166 rounded to 10.2 10.2 mol x 54.9380g/1 mol = 558.505 = 559g I was just wondering if I rounded to high to get the right amount of sig figs? Is my answer correct or should I change it?

1. Renee99

I did it again, but I didn't round and this is what I got: 6.12x10^24 atoms x 1 mol/6.02x10^23 atoms = 10.166 10.166 mol x 54.9380g/1 mol = 558.499g

2. Susan9419

i think your right i just did the problem and came up with the same answer ;D

3. Renee99

the first one or the second one?

4. Susan9419

the second one ;D

5. Renee99

okay, then I'll go with that one! thank you!

6. Susan9419

no problemo ;D

7. Renee99

I will say though, I think I might have written the second one incorrectly. For some reason, I din't feel like it's written correctly...

8. Renee99

don't*

9. Susan9419

it should be written like this i mole= 588.499g so u wrote it right ;D

10. Renee99

doesn't it have to have 3 sig figs though?

11. Renee99

so would I just change it to 558g?

12. Renee99

im just not sure, I just know my teacher is very strict about sig figs

13. Susan9419

yes if u need 3 sig figs then 558 would be correct ;D i was just trying to be accurate sorry!!

14. Renee99

no no, don't be sorry, I like accuracy! lol :) I just wanted to make sure

15. Renee99

Thanks again for ur help!

16. Susan9419

uh-huh no problem ;D

17. Renee99

Okay, yeah so just to clarify, my answer is going to be this: 6.12x10^24 atoms x 1 mol/6.02x10^23 atoms = 10.166 10.166 mol x 54.9380g/1 mol = 558.499 = 558g :)

18. Susan9419

yea thats right ;D

19. Renee99

okie dokie! :D