Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
Renee99
Group Title
Chemistry question: What is the mass, in grams, of a sample of 6.12 × 1024 atoms of manganese (Mn)?
6.12x10^24 atoms x 1 mol/6.02x10^23 atoms = 10.166 rounded to 10.2
10.2 mol x 54.9380g/1 mol = 558.505 = 559g
I was just wondering if I rounded to high to get the right amount of sig figs? Is my answer correct or should I change it?
 one year ago
 one year ago
Renee99 Group Title
Chemistry question: What is the mass, in grams, of a sample of 6.12 × 1024 atoms of manganese (Mn)? 6.12x10^24 atoms x 1 mol/6.02x10^23 atoms = 10.166 rounded to 10.2 10.2 mol x 54.9380g/1 mol = 558.505 = 559g I was just wondering if I rounded to high to get the right amount of sig figs? Is my answer correct or should I change it?
 one year ago
 one year ago

This Question is Closed

Renee99 Group TitleBest ResponseYou've already chosen the best response.1
I did it again, but I didn't round and this is what I got: 6.12x10^24 atoms x 1 mol/6.02x10^23 atoms = 10.166 10.166 mol x 54.9380g/1 mol = 558.499g
 one year ago

Susan9419 Group TitleBest ResponseYou've already chosen the best response.1
i think your right i just did the problem and came up with the same answer ;D
 one year ago

Renee99 Group TitleBest ResponseYou've already chosen the best response.1
the first one or the second one?
 one year ago

Susan9419 Group TitleBest ResponseYou've already chosen the best response.1
the second one ;D
 one year ago

Renee99 Group TitleBest ResponseYou've already chosen the best response.1
okay, then I'll go with that one! thank you!
 one year ago

Susan9419 Group TitleBest ResponseYou've already chosen the best response.1
no problemo ;D
 one year ago

Renee99 Group TitleBest ResponseYou've already chosen the best response.1
I will say though, I think I might have written the second one incorrectly. For some reason, I din't feel like it's written correctly...
 one year ago

Susan9419 Group TitleBest ResponseYou've already chosen the best response.1
it should be written like this i mole= 588.499g so u wrote it right ;D
 one year ago

Renee99 Group TitleBest ResponseYou've already chosen the best response.1
doesn't it have to have 3 sig figs though?
 one year ago

Renee99 Group TitleBest ResponseYou've already chosen the best response.1
so would I just change it to 558g?
 one year ago

Renee99 Group TitleBest ResponseYou've already chosen the best response.1
im just not sure, I just know my teacher is very strict about sig figs
 one year ago

Susan9419 Group TitleBest ResponseYou've already chosen the best response.1
yes if u need 3 sig figs then 558 would be correct ;D i was just trying to be accurate sorry!!
 one year ago

Renee99 Group TitleBest ResponseYou've already chosen the best response.1
no no, don't be sorry, I like accuracy! lol :) I just wanted to make sure
 one year ago

Renee99 Group TitleBest ResponseYou've already chosen the best response.1
Thanks again for ur help!
 one year ago

Susan9419 Group TitleBest ResponseYou've already chosen the best response.1
uhhuh no problem ;D
 one year ago

Renee99 Group TitleBest ResponseYou've already chosen the best response.1
Okay, yeah so just to clarify, my answer is going to be this: 6.12x10^24 atoms x 1 mol/6.02x10^23 atoms = 10.166 10.166 mol x 54.9380g/1 mol = 558.499 = 558g :)
 one year ago

Susan9419 Group TitleBest ResponseYou've already chosen the best response.1
yea thats right ;D
 one year ago

Renee99 Group TitleBest ResponseYou've already chosen the best response.1
okie dokie! :D
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.