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Coolsector Group TitleBest ResponseYou've already chosen the best response.1
f(x)<y > y < f(x) < y
 2 years ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
f(x) > y > f(x) > y , f(x) < y
 2 years ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
can you do it now ?
 2 years ago

xRAWRRx3 Group TitleBest ResponseYou've already chosen the best response.0
um, no, I don't get what you mean by all that..
 2 years ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
ok if we divide the equation by 1 what will we get ?
 2 years ago

xRAWRRx3 Group TitleBest ResponseYou've already chosen the best response.0
well, my teacher said to change the < to a = when I solve these types of problems so i would get: 2m1 = 2
 2 years ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
ok if you want to do it this way you dont have to divide.. but if you done it already now you know to find m's that satisfy 2m1 = 2 ?
 2 years ago

xRAWRRx3 Group TitleBest ResponseYou've already chosen the best response.0
well, to get rid of the absolute values first, I just seperated it into 2m 1 = 2 and 2m 1 = 2 like my teacher told me to and I got the answers 1/2 and 3/2 but when I tried to check it, it doesn't seem right..
 2 years ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
you have to plug now some m<1/2 like m = 1 1/2 < m < 3/2 lke m = 1 and m>3/2 like m = 2 in the original equation and see if it holds
 2 years ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
when does it hold?
 2 years ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
are you there?
 2 years ago

xRAWRRx3 Group TitleBest ResponseYou've already chosen the best response.0
yeah sorry, I tried numbers but it didn't work...
 2 years ago

xRAWRRx3 Group TitleBest ResponseYou've already chosen the best response.0
can someone else tell me how to solve this or if I'm doing something wrong?
 2 years ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
why? when you plug m=1 what do you get?
 2 years ago

xRAWRRx3 Group TitleBest ResponseYou've already chosen the best response.0
i get 4 <2
 2 years ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
so it holds isnt it?
 2 years ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
4 is indeed smaller than 2
 2 years ago

xRAWRRx3 Group TitleBest ResponseYou've already chosen the best response.0
yes, I know but the answers i got for m and every other number works too which shouldn't be happening
 2 years ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
it works for every m
 2 years ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
it is obvious.. the original question is negative number < 2 so it always holds i wanted to work on the technique with you
 2 years ago

xRAWRRx3 Group TitleBest ResponseYou've already chosen the best response.0
i don't get how that can work though...so the answer is that all numbers work?
 2 years ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
yes it is obvious .. all the negative numbers are smaller than 2
 2 years ago

Coolsector Group TitleBest ResponseYou've already chosen the best response.1
if you didnt see it at the original question you could see it when you asked yourself 2m1 = 2 ? it is never happens .. since left hand side of the equation is always positive !!
 2 years ago

xRAWRRx3 Group TitleBest ResponseYou've already chosen the best response.0
ohhhh, okay, thank you :)
 2 years ago
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