xRAWRRx3
Solve:
-|2m-1| < 2
and please explain how to solve it.
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Coolsector
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|f(x)|<y
->
-y < f(x) < y
Coolsector
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|f(x)| > y
->
f(x) > y , f(x) < -y
Coolsector
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can you do it now ?
xRAWRRx3
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um, no, I don't get what you mean by all that..
Coolsector
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ok if we divide the equation by -1 what will we get ?
xRAWRRx3
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well, my teacher said to change the < to a = when I solve these types of problems so i would get:
|2m-1| = -2
Coolsector
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ok if you want to do it this way you dont have to divide.. but if you done it already
now you know to find m's that satisfy |2m-1| = -2 ?
xRAWRRx3
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well, to get rid of the absolute values first, I just seperated it into 2m -1 = -2 and 2m -1 = 2 like my teacher told me to and I got the answers -1/2 and 3/2 but when I tried to check it, it doesn't seem right..
Coolsector
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you have to plug now some m<-1/2 like m = -1
-1/2 < m < 3/2 lke m = 1
and m>3/2 like m = 2
in the original equation and see if it holds
Coolsector
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when does it hold?
Coolsector
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are you there?
xRAWRRx3
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yeah sorry, I tried numbers but it didn't work...
xRAWRRx3
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can someone else tell me how to solve this or if I'm doing something wrong?
Coolsector
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why? when you plug m=-1
what do you get?
xRAWRRx3
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i get -4 <2
Coolsector
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so it holds isnt it?
Coolsector
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-4 is indeed smaller than 2
xRAWRRx3
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yes, I know but the answers i got for m and every other number works too which shouldn't be happening
Coolsector
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it works for every m
Coolsector
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it is obvious.. the original question is negative number < 2
so it always holds
i wanted to work on the technique with you
xRAWRRx3
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i don't get how that can work though...so the answer is that all numbers work?
Coolsector
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yes it is obvious ..
all the negative numbers are smaller than 2
Coolsector
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if you didnt see it at the original question you could see it when you asked yourself
|2m-1| = -2
?
it is never happens .. since left hand side of the equation is always positive !!
xRAWRRx3
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ohhhh, okay, thank you :)
Coolsector
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yw;)