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@Algebraic! any clues

|dw:1348695082199:dw|

is it clear?

not clear at all

the forces are equal in magnitude and opposite in direction.

| e*E1 |=| e*E2 |
E1 = kq1/(r1)^2
E2 = kq2/(r2^2)

E1 = kq1/(r1)^2 = E2 = kq2/(r2)^2
kq1/(r1)^2 = kq2/(r2)^2
kq1/(x)^2 = kq2/(.4-x)^2

solve the quadratic for x

clear now?

+4e charge is at x=0; +2e charge is at x=.4

|dw:1348774582953:dw|

there is no 4 its 40..also the (0,0) isnt the x,y pairs?

.4

ok?

so u mean the 3rd charge is in the middle of both charge?

how do we solve this kind of quadratic
4e/x^2 = 2e/(4-x)^2

4e/x^2 = 2e/(.4-x)^2

cross multiply

4e(.4-x)^2 = 2ex^2

x is 2.3

@Algebraic! do you believe i just saw the .4 and not 4...thanks a lot