A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing


  • 4 years ago

Rank with respect to boiling point. What am I doing wrong? CH3CH2CH2OH > (CH3)2CH(C=0)H > CH3CH2CO2H > HO2C(CH2)2CO2H > (CH3CH2)2NH > (CH3)2CHCH2CH3 > CH4

  • This Question is Closed
  1. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    HO2C-C(CH2)-CO2H>CH3CH2CO2H>CH3CH2CH2OH>(CH3CH2)2NH>(CH3)2CH(C=O)H>branched chain> methane. Boiling points are based on polarity and weight. More polar and more heavy, the higher the boiling point. Hydrogen bonds are favored whenever possible. That way, acids almost always take preference. Hope that helps

  2. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...


  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.