The length of a rectangle is 7 inches more than the width. The perimeter is 42 inches. Find the length and width

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The length of a rectangle is 7 inches more than the width. The perimeter is 42 inches. Find the length and width

Mathematics
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Cool, so for that rectangle, perimeter is 42. How do you find the perimeter?
Do you know the formula for finding the perimeter of an object?

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Other answers:

i think its p=2l+2w
yeah, in this case for the rectangle, P = 2*length + 2*width. So you have values for the length and the width, right? L = x + 7 W = x
Plug those values into the perimeter function, what does the equation look like after doing that?
my equation looks like this 42=2(7)+2w 42-14=28 which makes w = 14 then for L 14+7=21 am i right
Getting there, so the values you have for each dimension are actually variables - (x+7), and x Therefore P = 2*L + 2*W becomes L = x + 7 W = x P = 2*(x+7) + 2*(x) 42 = 2*(x+7) + 2*(x)
Because there is only one variable, one unknown, that being 'x', we can easily then solve for it from the adjusted equation.
Does that make sense? Give that equation a shot, and solve for x.
x=7
Definitely! that's it, so L = ? and W = ?
Just have to do that last step and you're donw
Quite easy after finding x...
so w = 7 and l=14
Nice work
thanks

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