Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

3*3 • 3*7 (*exponents) Ben is trying to solve the above expression. He takes the following steps: Ben multiplies the bases together to get 9 as the base of his answer. Ben adds the exponents together to get 10 for the exponent of his answer. Ben arrives at the answer 910. Which step(s) did he make a mistake on and what was the mistake?

I got my questions answered at in under 10 minutes. Go to now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly


Get your free account and access expert answers to this and thousands of other questions

Ben made a lot of mistakes.
The sign for an exponent is ^. So it would look like 3^3 times 3^7.
3^3 = 27 3^7 = 2187

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

2187 times 27 = 59,049.
Knowing the properties of exponents would tell us that you add the exponents when you multiply numbers with the same base.
So, you add the product of each, which would make 2214?

Not the answer you are looking for?

Search for more explanations.

Ask your own question