Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

Can someone check my calc prob and tell me if my answer is correct? Find the derivative of the function. y=Ine^x

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SIGN UP FOR FREE
y(prime)=1/x(e^x)+e^x(In) and my answer is y(prime)=e^x(1/x+In)
y=lne^x=e^x de^x/dx =e^x
u lost me

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

hold the phone \(\ln(e^x)=x\)
well the problem has absolutely No parenthesis
sorry do u knw dat log n exp are mirror fns and that why they cancel out each other
ya is it 1
okay?
is the correct ans 1
i have no idea this is an even problem and my book does not carry evens numbered problems
\[y=\ln_ex\] ?
No simply lne^x
lne^x = xlne = x So y = x Now derivative it.
y=In e^x
see ur que was to diff y= lne^x now as i said ln and exp cancels out each other so lne^x=x ie y=x dx/dx=1
you guys are completely confusing me
did u get tis
Do you know logarithm properties?
one question, is it possible to cancel well when rewritten.....ln=1/w so we have 1/x e^x is it possible to cancel out the x's?
NO
i mean ln=1/x
\[\ln a^b = b \ln a \]
ya
So \[\ln e^x = x \ln e\]
And ln e = 1
Do you know logarithm properties?
i did
you can do that way too but rem tis log n exponential r mirrors function dats y can cancel them out and wat micahwood50 says is also correct
Well, so y = x. Now derivative it.
1
Yeah. y' = 1
okay thanks
No problem. Glad I helped you.
:]

Not the answer you are looking for?

Search for more explanations.

Ask your own question