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lilly21

  • 2 years ago

Can someone check my calc prob and tell me if my answer is correct? Find the derivative of the function. y=Ine^x

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  1. lilly21
    • 2 years ago
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    y(prime)=1/x(e^x)+e^x(In) and my answer is y(prime)=e^x(1/x+In)

  2. suneja
    • 2 years ago
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    y=lne^x=e^x de^x/dx =e^x

  3. lilly21
    • 2 years ago
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    u lost me

  4. satellite73
    • 2 years ago
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    hold the phone \(\ln(e^x)=x\)

  5. lilly21
    • 2 years ago
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    well the problem has absolutely No parenthesis

  6. suneja
    • 2 years ago
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    sorry do u knw dat log n exp are mirror fns and that why they cancel out each other

  7. suneja
    • 2 years ago
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    ya is it 1

  8. lilly21
    • 2 years ago
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    okay?

  9. suneja
    • 2 years ago
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    is the correct ans 1

  10. lilly21
    • 2 years ago
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    i have no idea this is an even problem and my book does not carry evens numbered problems

  11. UnkleRhaukus
    • 2 years ago
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    \[y=\ln_ex\] ?

  12. lilly21
    • 2 years ago
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    No simply lne^x

  13. micahwood50
    • 2 years ago
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    lne^x = xlne = x So y = x Now derivative it.

  14. lilly21
    • 2 years ago
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    y=In e^x

  15. suneja
    • 2 years ago
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    see ur que was to diff y= lne^x now as i said ln and exp cancels out each other so lne^x=x ie y=x dx/dx=1

  16. lilly21
    • 2 years ago
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    you guys are completely confusing me

  17. suneja
    • 2 years ago
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    did u get tis

  18. micahwood50
    • 2 years ago
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    Do you know logarithm properties?

  19. lilly21
    • 2 years ago
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    one question, is it possible to cancel well when rewritten.....ln=1/w so we have 1/x e^x is it possible to cancel out the x's?

  20. suneja
    • 2 years ago
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    NO

  21. lilly21
    • 2 years ago
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    i mean ln=1/x

  22. micahwood50
    • 2 years ago
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    \[\ln a^b = b \ln a \]

  23. suneja
    • 2 years ago
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    ya

  24. micahwood50
    • 2 years ago
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    So \[\ln e^x = x \ln e\]

  25. micahwood50
    • 2 years ago
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    And ln e = 1

  26. micahwood50
    • 2 years ago
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    Do you know logarithm properties?

  27. lilly21
    • 2 years ago
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    i did

  28. suneja
    • 2 years ago
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    you can do that way too but rem tis log n exponential r mirrors function dats y can cancel them out and wat micahwood50 says is also correct

  29. micahwood50
    • 2 years ago
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    Well, so y = x. Now derivative it.

  30. lilly21
    • 2 years ago
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    1

  31. micahwood50
    • 2 years ago
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    Yeah. y' = 1

  32. lilly21
    • 2 years ago
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    okay thanks

  33. micahwood50
    • 2 years ago
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    No problem. Glad I helped you.

  34. lilly21
    • 2 years ago
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    :]

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