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heckyeahrobin

  • 2 years ago

How do I find the difference quotient? I already have the function of x and the equation and the restriction. How do I start?

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  1. RadEn
    • 2 years ago
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    share ur question, please...

  2. heckyeahrobin
    • 2 years ago
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    i have already plugged in (3+h) for x. what do i do next? @RadEn

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  3. RadEn
    • 2 years ago
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    about derivative by using limit methods, right ?

  4. satellite73
    • 2 years ago
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    \(f(6)=5\) so we keep that number

  5. satellite73
    • 2 years ago
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    then compute \[f(6+h)=5+6(6+h)-(6+h)^2\] to get \[5+36+6h-(36+12h+h^2)\] \[=5-6h-h^2\] then subtract 5 so that \(f(6+h)-f(6)=-6h-h^2\) divide by \(h\) and get \(-6-h\)

  6. heckyeahrobin
    • 2 years ago
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    so i don't divide by H until i have plugged in both 6+h and 6 and simplified both? @satellite73

  7. RadEn
    • 2 years ago
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    smart way : f(x) = 5+6x-x^2 f'(x) = 6-2x if u want find value of f'(6), u just plug in x=6 into f'(x) so, f'(6)=6-2(6)=6-12= ????????? but if u want using limit's method, like @satellite73 said

  8. satellite73
    • 2 years ago
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    you do not divide by \(h\) until the end one reason is that you cannot divide by \(h\) until you have simplified the numerator so that everything without an \(h\) in it is gone

  9. heckyeahrobin
    • 2 years ago
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    Thank you!! both of your answers were very helpful!

  10. satellite73
    • 2 years ago
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    yw

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