anonymous
  • anonymous
How do I find the difference quotient? I already have the function of x and the equation and the restriction. How do I start?
Mathematics
schrodinger
  • schrodinger
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RadEn
  • RadEn
share ur question, please...
anonymous
  • anonymous
i have already plugged in (3+h) for x. what do i do next? @RadEn
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RadEn
  • RadEn
about derivative by using limit methods, right ?

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anonymous
  • anonymous
\(f(6)=5\) so we keep that number
anonymous
  • anonymous
then compute \[f(6+h)=5+6(6+h)-(6+h)^2\] to get \[5+36+6h-(36+12h+h^2)\] \[=5-6h-h^2\] then subtract 5 so that \(f(6+h)-f(6)=-6h-h^2\) divide by \(h\) and get \(-6-h\)
anonymous
  • anonymous
so i don't divide by H until i have plugged in both 6+h and 6 and simplified both? @satellite73
RadEn
  • RadEn
smart way : f(x) = 5+6x-x^2 f'(x) = 6-2x if u want find value of f'(6), u just plug in x=6 into f'(x) so, f'(6)=6-2(6)=6-12= ????????? but if u want using limit's method, like @satellite73 said
anonymous
  • anonymous
you do not divide by \(h\) until the end one reason is that you cannot divide by \(h\) until you have simplified the numerator so that everything without an \(h\) in it is gone
anonymous
  • anonymous
Thank you!! both of your answers were very helpful!
anonymous
  • anonymous
yw

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