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anonymous
 4 years ago
How do I find the difference quotient? I already have the function of x and the equation and the restriction. How do I start?
anonymous
 4 years ago
How do I find the difference quotient? I already have the function of x and the equation and the restriction. How do I start?

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RadEn
 4 years ago
Best ResponseYou've already chosen the best response.0share ur question, please...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i have already plugged in (3+h) for x. what do i do next? @RadEn

RadEn
 4 years ago
Best ResponseYou've already chosen the best response.0about derivative by using limit methods, right ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\(f(6)=5\) so we keep that number

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0then compute \[f(6+h)=5+6(6+h)(6+h)^2\] to get \[5+36+6h(36+12h+h^2)\] \[=56hh^2\] then subtract 5 so that \(f(6+h)f(6)=6hh^2\) divide by \(h\) and get \(6h\)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so i don't divide by H until i have plugged in both 6+h and 6 and simplified both? @satellite73

RadEn
 4 years ago
Best ResponseYou've already chosen the best response.0smart way : f(x) = 5+6xx^2 f'(x) = 62x if u want find value of f'(6), u just plug in x=6 into f'(x) so, f'(6)=62(6)=612= ????????? but if u want using limit's method, like @satellite73 said

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you do not divide by \(h\) until the end one reason is that you cannot divide by \(h\) until you have simplified the numerator so that everything without an \(h\) in it is gone

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thank you!! both of your answers were very helpful!
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