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heckyeahrobin Group Title

How do I find the difference quotient? I already have the function of x and the equation and the restriction. How do I start?

  • 2 years ago
  • 2 years ago

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  1. RadEn Group Title
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    share ur question, please...

    • 2 years ago
  2. heckyeahrobin Group Title
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    i have already plugged in (3+h) for x. what do i do next? @RadEn

    • 2 years ago
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  3. RadEn Group Title
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    about derivative by using limit methods, right ?

    • 2 years ago
  4. satellite73 Group Title
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    \(f(6)=5\) so we keep that number

    • 2 years ago
  5. satellite73 Group Title
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    then compute \[f(6+h)=5+6(6+h)-(6+h)^2\] to get \[5+36+6h-(36+12h+h^2)\] \[=5-6h-h^2\] then subtract 5 so that \(f(6+h)-f(6)=-6h-h^2\) divide by \(h\) and get \(-6-h\)

    • 2 years ago
  6. heckyeahrobin Group Title
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    so i don't divide by H until i have plugged in both 6+h and 6 and simplified both? @satellite73

    • 2 years ago
  7. RadEn Group Title
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    smart way : f(x) = 5+6x-x^2 f'(x) = 6-2x if u want find value of f'(6), u just plug in x=6 into f'(x) so, f'(6)=6-2(6)=6-12= ????????? but if u want using limit's method, like @satellite73 said

    • 2 years ago
  8. satellite73 Group Title
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    you do not divide by \(h\) until the end one reason is that you cannot divide by \(h\) until you have simplified the numerator so that everything without an \(h\) in it is gone

    • 2 years ago
  9. heckyeahrobin Group Title
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    Thank you!! both of your answers were very helpful!

    • 2 years ago
  10. satellite73 Group Title
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    yw

    • 2 years ago
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