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heckyeahrobin

How do I find the difference quotient? I already have the function of x and the equation and the restriction. How do I start?

  • one year ago
  • one year ago

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  1. RadEn
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    share ur question, please...

    • one year ago
  2. heckyeahrobin
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    i have already plugged in (3+h) for x. what do i do next? @RadEn

    • one year ago
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  3. RadEn
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    about derivative by using limit methods, right ?

    • one year ago
  4. satellite73
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    \(f(6)=5\) so we keep that number

    • one year ago
  5. satellite73
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    then compute \[f(6+h)=5+6(6+h)-(6+h)^2\] to get \[5+36+6h-(36+12h+h^2)\] \[=5-6h-h^2\] then subtract 5 so that \(f(6+h)-f(6)=-6h-h^2\) divide by \(h\) and get \(-6-h\)

    • one year ago
  6. heckyeahrobin
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    so i don't divide by H until i have plugged in both 6+h and 6 and simplified both? @satellite73

    • one year ago
  7. RadEn
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    smart way : f(x) = 5+6x-x^2 f'(x) = 6-2x if u want find value of f'(6), u just plug in x=6 into f'(x) so, f'(6)=6-2(6)=6-12= ????????? but if u want using limit's method, like @satellite73 said

    • one year ago
  8. satellite73
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    you do not divide by \(h\) until the end one reason is that you cannot divide by \(h\) until you have simplified the numerator so that everything without an \(h\) in it is gone

    • one year ago
  9. heckyeahrobin
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    Thank you!! both of your answers were very helpful!

    • one year ago
  10. satellite73
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    yw

    • one year ago
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