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Hectro_1

  • 3 years ago

Chain Rule Calculus f(x)=(2x-7)^3 I NEEED HELP!!

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  1. bahrom7893
    • 3 years ago
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    3(2x-7)^2 * (2*1-0)

  2. Hectro_1
    • 3 years ago
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    may i ask how you got that?

  3. bahrom7893
    • 3 years ago
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    (f(x))^a = a(f(x))^(a-1) * f'(x)

  4. Dido525
    • 3 years ago
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    f'(x) = 3(2x-7)^2 * d/(dx (2x-7) =3(2x-7)^2(2) =6(2x-7)^2

  5. suneja
    • 3 years ago
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    cant u jst simplify tis using formula for (a-b)^3=a^3+3ab^2-3a^2b-b^3 and then diff tis.. its much easier than to use product rule

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