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Ruchi.

Calculate the mass of ammonia produced of 2g N2 reacts with 1g H2.

  • one year ago
  • one year ago

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  1. Ruchi.
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    @TheMind @ujjwal @ajprincess

    • one year ago
  2. UnkleRhaukus
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    have you got an equation for the reaction

    • one year ago
  3. Ruchi.
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    no

    • one year ago
  4. UnkleRhaukus
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    do you know the for mula for ammonia?

    • one year ago
  5. UnkleRhaukus
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    is it NH_3 ?

    • one year ago
  6. Ruchi.
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    nh3

    • one year ago
  7. UnkleRhaukus
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    so far we have \[N_2+H_2 \longrightarrow NH_3\] right?

    • one year ago
  8. Ruchi.
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    @@@UnkleRhaukus

    • one year ago
  9. UnkleRhaukus
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    can you balance the equation for number of H and N on each side?

    • one year ago
  10. Ruchi.
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    UR EQ IS NT APPEARING

    • one year ago
  11. UnkleRhaukus
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    oh,

    • one year ago
  12. UnkleRhaukus
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    N_2 + H_2 ⟶ NH_3

    • one year ago
  13. UnkleRhaukus
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    so to make the product we need thee time as much H as N

    • one year ago
  14. ujjwal
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    \[N_2+3H_2\rightarrow2NH_3\] You get no of moles required from this equation! Convert them in terms of weight.. Find limiting reactant (the reactant whose quantity is less than required)! limiting reactant will determine the amount of product formed!

    • one year ago
  15. bthemesandtricks
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    Is this always the case??

    • one year ago
  16. Ruchi.
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    ITS AGAIN APPEARING MATHS PROCCESING ERROR

    • one year ago
  17. mayankdevnani
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    i think ujjwal is right

    • one year ago
  18. mayankdevnani
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    N2 + 3H2 ---> 2NH3

    • one year ago
  19. mayankdevnani
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    So the moles are: For nitrogen, 28g/28g/mol = 1.0 mole N2 For hydrogen 25g/2g/mole = 12.5 moles @ujjwal right...

    • one year ago
  20. UnkleRhaukus
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    which is the limiting reagent ?

    • one year ago
  21. mayankdevnani
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    Obviously, hydrogen is in excess and nitrogen is the limiting reagant

    • one year ago
  22. mayankdevnani
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    @UnkleRhaukus

    • one year ago
  23. UnkleRhaukus
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    so according to the balanced equation the theoretical yield will be 2 moles of NH_3

    • one year ago
  24. ujjwal
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    yep! 2 mol of NH3 will be yielded!

    • one year ago
  25. UnkleRhaukus
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    the molar mass of ammonia is (1x14+3x1) g/mol

    • one year ago
  26. UnkleRhaukus
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    can you finish @Ruchi. ?

    • one year ago
  27. Ruchi.
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    @mayank i'm nt getting u properly

    • one year ago
  28. Ruchi.
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    @taylorrrr @ajprincess @imron07 @TheMind @Vikt0r hlp me out

    • one year ago
  29. ajprincess
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    Where are u stuck @Ruchi.?

    • one year ago
  30. ajprincess
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    Did u understand the part where the moles are calculated?

    • one year ago
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