## Ruchi. 3 years ago Calculate the mass of ammonia produced of 2g N2 reacts with 1g H2.

1. Ruchi.

@TheMind @ujjwal @ajprincess

2. UnkleRhaukus

have you got an equation for the reaction

3. Ruchi.

no

4. UnkleRhaukus

do you know the for mula for ammonia?

5. UnkleRhaukus

is it NH_3 ?

6. Ruchi.

nh3

7. UnkleRhaukus

so far we have $N_2+H_2 \longrightarrow NH_3$ right?

8. Ruchi.

@@@UnkleRhaukus

9. UnkleRhaukus

can you balance the equation for number of H and N on each side?

10. Ruchi.

UR EQ IS NT APPEARING

11. UnkleRhaukus

oh,

12. UnkleRhaukus

N_2 + H_2 ⟶ NH_3

13. UnkleRhaukus

so to make the product we need thee time as much H as N

14. ujjwal

$N_2+3H_2\rightarrow2NH_3$ You get no of moles required from this equation! Convert them in terms of weight.. Find limiting reactant (the reactant whose quantity is less than required)! limiting reactant will determine the amount of product formed!

15. bthemesandtricks

Is this always the case??

16. Ruchi.

ITS AGAIN APPEARING MATHS PROCCESING ERROR

17. mayankdevnani

i think ujjwal is right

18. mayankdevnani

N2 + 3H2 ---> 2NH3

19. mayankdevnani

So the moles are: For nitrogen, 28g/28g/mol = 1.0 mole N2 For hydrogen 25g/2g/mole = 12.5 moles @ujjwal right...

20. UnkleRhaukus

which is the limiting reagent ?

21. mayankdevnani

Obviously, hydrogen is in excess and nitrogen is the limiting reagant

22. mayankdevnani

@UnkleRhaukus

23. UnkleRhaukus

so according to the balanced equation the theoretical yield will be 2 moles of NH_3

24. ujjwal

yep! 2 mol of NH3 will be yielded!

25. UnkleRhaukus

the molar mass of ammonia is (1x14+3x1) g/mol

26. UnkleRhaukus

can you finish @Ruchi. ?

27. Ruchi.

@mayank i'm nt getting u properly

28. Ruchi.

@taylorrrr @ajprincess @imron07 @TheMind @Vikt0r hlp me out

29. ajprincess

Where are u stuck @Ruchi.?

30. ajprincess

Did u understand the part where the moles are calculated?