anonymous
  • anonymous
Calculate the mass of ammonia produced of 2g N2 reacts with 1g H2.
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
@TheMind @ujjwal @ajprincess
UnkleRhaukus
  • UnkleRhaukus
have you got an equation for the reaction
anonymous
  • anonymous
no

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UnkleRhaukus
  • UnkleRhaukus
do you know the for mula for ammonia?
UnkleRhaukus
  • UnkleRhaukus
is it NH_3 ?
anonymous
  • anonymous
nh3
UnkleRhaukus
  • UnkleRhaukus
so far we have \[N_2+H_2 \longrightarrow NH_3\] right?
anonymous
  • anonymous
@@@UnkleRhaukus
UnkleRhaukus
  • UnkleRhaukus
can you balance the equation for number of H and N on each side?
anonymous
  • anonymous
UR EQ IS NT APPEARING
UnkleRhaukus
  • UnkleRhaukus
oh,
UnkleRhaukus
  • UnkleRhaukus
N_2 + H_2 ⟶ NH_3
UnkleRhaukus
  • UnkleRhaukus
so to make the product we need thee time as much H as N
ujjwal
  • ujjwal
\[N_2+3H_2\rightarrow2NH_3\] You get no of moles required from this equation! Convert them in terms of weight.. Find limiting reactant (the reactant whose quantity is less than required)! limiting reactant will determine the amount of product formed!
anonymous
  • anonymous
Is this always the case??
anonymous
  • anonymous
ITS AGAIN APPEARING MATHS PROCCESING ERROR
mayankdevnani
  • mayankdevnani
i think ujjwal is right
mayankdevnani
  • mayankdevnani
N2 + 3H2 ---> 2NH3
mayankdevnani
  • mayankdevnani
So the moles are: For nitrogen, 28g/28g/mol = 1.0 mole N2 For hydrogen 25g/2g/mole = 12.5 moles @ujjwal right...
UnkleRhaukus
  • UnkleRhaukus
which is the limiting reagent ?
mayankdevnani
  • mayankdevnani
Obviously, hydrogen is in excess and nitrogen is the limiting reagant
mayankdevnani
  • mayankdevnani
@UnkleRhaukus
UnkleRhaukus
  • UnkleRhaukus
so according to the balanced equation the theoretical yield will be 2 moles of NH_3
ujjwal
  • ujjwal
yep! 2 mol of NH3 will be yielded!
UnkleRhaukus
  • UnkleRhaukus
the molar mass of ammonia is (1x14+3x1) g/mol
UnkleRhaukus
  • UnkleRhaukus
can you finish @Ruchi. ?
anonymous
  • anonymous
@mayank i'm nt getting u properly
anonymous
  • anonymous
@taylorrrr @ajprincess @imron07 @TheMind @Vikt0r hlp me out
ajprincess
  • ajprincess
Where are u stuck @Ruchi.?
ajprincess
  • ajprincess
Did u understand the part where the moles are calculated?

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