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Calculate the mass of ammonia produced of 2g N2 reacts with 1g H2.

Chemistry
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have you got an equation for the reaction
no

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Other answers:

do you know the for mula for ammonia?
is it NH_3 ?
nh3
so far we have \[N_2+H_2 \longrightarrow NH_3\] right?
can you balance the equation for number of H and N on each side?
UR EQ IS NT APPEARING
oh,
N_2 + H_2 ⟶ NH_3
so to make the product we need thee time as much H as N
\[N_2+3H_2\rightarrow2NH_3\] You get no of moles required from this equation! Convert them in terms of weight.. Find limiting reactant (the reactant whose quantity is less than required)! limiting reactant will determine the amount of product formed!
Is this always the case??
ITS AGAIN APPEARING MATHS PROCCESING ERROR
i think ujjwal is right
N2 + 3H2 ---> 2NH3
So the moles are: For nitrogen, 28g/28g/mol = 1.0 mole N2 For hydrogen 25g/2g/mole = 12.5 moles @ujjwal right...
which is the limiting reagent ?
Obviously, hydrogen is in excess and nitrogen is the limiting reagant
so according to the balanced equation the theoretical yield will be 2 moles of NH_3
yep! 2 mol of NH3 will be yielded!
the molar mass of ammonia is (1x14+3x1) g/mol
can you finish @Ruchi. ?
@mayank i'm nt getting u properly
Where are u stuck @Ruchi.?
Did u understand the part where the moles are calculated?

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