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Ruchi.

  • 2 years ago

Calculate the mass of ammonia produced of 2g N2 reacts with 1g H2.

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  1. Ruchi.
    • 2 years ago
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    @TheMind @ujjwal @ajprincess

  2. UnkleRhaukus
    • 2 years ago
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    have you got an equation for the reaction

  3. Ruchi.
    • 2 years ago
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    no

  4. UnkleRhaukus
    • 2 years ago
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    do you know the for mula for ammonia?

  5. UnkleRhaukus
    • 2 years ago
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    is it NH_3 ?

  6. Ruchi.
    • 2 years ago
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    nh3

  7. UnkleRhaukus
    • 2 years ago
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    so far we have \[N_2+H_2 \longrightarrow NH_3\] right?

  8. Ruchi.
    • 2 years ago
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    @@@UnkleRhaukus

  9. UnkleRhaukus
    • 2 years ago
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    can you balance the equation for number of H and N on each side?

  10. Ruchi.
    • 2 years ago
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    UR EQ IS NT APPEARING

  11. UnkleRhaukus
    • 2 years ago
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    oh,

  12. UnkleRhaukus
    • 2 years ago
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    N_2 + H_2 ⟶ NH_3

  13. UnkleRhaukus
    • 2 years ago
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    so to make the product we need thee time as much H as N

  14. ujjwal
    • 2 years ago
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    \[N_2+3H_2\rightarrow2NH_3\] You get no of moles required from this equation! Convert them in terms of weight.. Find limiting reactant (the reactant whose quantity is less than required)! limiting reactant will determine the amount of product formed!

  15. bthemesandtricks
    • 2 years ago
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    Is this always the case??

  16. Ruchi.
    • 2 years ago
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    ITS AGAIN APPEARING MATHS PROCCESING ERROR

  17. mayankdevnani
    • 2 years ago
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    i think ujjwal is right

  18. mayankdevnani
    • 2 years ago
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    N2 + 3H2 ---> 2NH3

  19. mayankdevnani
    • 2 years ago
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    So the moles are: For nitrogen, 28g/28g/mol = 1.0 mole N2 For hydrogen 25g/2g/mole = 12.5 moles @ujjwal right...

  20. UnkleRhaukus
    • 2 years ago
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    which is the limiting reagent ?

  21. mayankdevnani
    • 2 years ago
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    Obviously, hydrogen is in excess and nitrogen is the limiting reagant

  22. mayankdevnani
    • 2 years ago
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    @UnkleRhaukus

  23. UnkleRhaukus
    • 2 years ago
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    so according to the balanced equation the theoretical yield will be 2 moles of NH_3

  24. ujjwal
    • 2 years ago
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    yep! 2 mol of NH3 will be yielded!

  25. UnkleRhaukus
    • 2 years ago
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    the molar mass of ammonia is (1x14+3x1) g/mol

  26. UnkleRhaukus
    • 2 years ago
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    can you finish @Ruchi. ?

  27. Ruchi.
    • 2 years ago
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    @mayank i'm nt getting u properly

  28. Ruchi.
    • 2 years ago
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    @taylorrrr @ajprincess @imron07 @TheMind @Vikt0r hlp me out

  29. ajprincess
    • 2 years ago
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    Where are u stuck @Ruchi.?

  30. ajprincess
    • 2 years ago
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    Did u understand the part where the moles are calculated?

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