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hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0u know a method to corvert a decimal number to other base number?

vikrantg4
 2 years ago
Best ResponseYou've already chosen the best response.0oops.. sorry.. keep dividing the number by 13 and note down remainders.. and taking remainders from down to up.. right hexadecimal equivalents of them :P

Esmy
 2 years ago
Best ResponseYou've already chosen the best response.116629 / 13 = 1279 1279 * 13 = 16627 16629  16627 = 2 16629 in base 13 is 7752 ?

vikrantg4
 2 years ago
Best ResponseYou've already chosen the best response.0damn i am sorry !! :(

Esmy
 2 years ago
Best ResponseYou've already chosen the best response.1? :D wait I'm not right :(

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0@vikrantg4 whats hexadecimal equivalent ?? u copied that from somewhere ?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0your first step is correct @Esmy , u get the remainder=2

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.02nd step also correct, u get remainder = 5

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.03rd step correct, remainder = 7

Esmy
 2 years ago
Best ResponseYou've already chosen the best response.1I'm I correct over all :'D

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.0another method would be to write down the exponential values of a base 13 system, and work it from there 13^4 13^3 13^2 13^1 13^0 28561 2197 169 13 1

Esmy
 2 years ago
Best ResponseYou've already chosen the best response.1Ohh :o okay that seems cool. Ill try that one in my next one :)

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.0:) just to refresh my memory .... 16,629 is divisible by 13^3: 7 times , 1250 left over 1250 is divisible 13^2: 7 times , 67 left over 67 is divisible 13^1: 5 times , 2 left over \[16,629_{10}=7752_{13} \]
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