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Esmy
Group Title
Use truth tables to test the validity of the argument.
p → ~q
q → ~p
∴ p ∨ q
 2 years ago
 2 years ago
Esmy Group Title
Use truth tables to test the validity of the argument. p → ~q q → ~p ∴ p ∨ q
 2 years ago
 2 years ago

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Esmy Group TitleBest ResponseYou've already chosen the best response.1
Case p=T and q=T [(p > ~q) ^ (q > ~p)] > (p V q) [(T > ~T) ^ (T > ~T)] > (T V T) [(T > F ) ^ (T > F)] > T [ F ^ F ] > T F > T T
 2 years ago

Esmy Group TitleBest ResponseYou've already chosen the best response.1
All four cases come out T, so the argument is valid. I think lol.
 2 years ago

A.Avinash_Goutham Group TitleBest ResponseYou've already chosen the best response.0
u need to verify that using a truth table?
 2 years ago

Esmy Group TitleBest ResponseYou've already chosen the best response.1
p q ~p ~q p > ~q q > ~p p v q T T F F F F T T F F T T T T F T T F T T T F F T T T T F Hmmm... I change my answer its invalid
 2 years ago

A.Avinash_Goutham Group TitleBest ResponseYou've already chosen the best response.0
then u need to make a dumbo table with all the combinations of p and q and verify it or u can use this p>q = (~p) v q
 2 years ago

Esmy Group TitleBest ResponseYou've already chosen the best response.1
"p > ~q" and "q > ~p" the last row has T and T so the conclusion is false?
 2 years ago

A.Avinash_Goutham Group TitleBest ResponseYou've already chosen the best response.0
actuall it mean that u shud conside the cases on when both of them are true
 2 years ago

Esmy Group TitleBest ResponseYou've already chosen the best response.1
Oh I totally miss understood the question
 2 years ago

Esmy Group TitleBest ResponseYou've already chosen the best response.1
So how would you do that? :o
 2 years ago

Esmy Group TitleBest ResponseYou've already chosen the best response.1
help can you explain to how you do it :/
 2 years ago

A.Avinash_Goutham Group TitleBest ResponseYou've already chosen the best response.0
consider those case when p → ~q q → ~p are true find them
 2 years ago

Esmy Group TitleBest ResponseYou've already chosen the best response.1
can you explain like in steps :/ I understand in steps.
 2 years ago

A.Avinash_Goutham Group TitleBest ResponseYou've already chosen the best response.0
hmm consider those inputs for which p → ~q is true q → ~p is true
 2 years ago

A.Avinash_Goutham Group TitleBest ResponseYou've already chosen the best response.0
lol sorry....... u shud try and understand
 2 years ago

A.Avinash_Goutham Group TitleBest ResponseYou've already chosen the best response.0
ok fine q → ~p is true for first three columns in the table
 2 years ago

Esmy Group TitleBest ResponseYou've already chosen the best response.1
p q ~p ~q ∼p∨q (∼p∨q)→ ∼q ———————————————————————————————— T T F F T F T F F T F T F T T F T F F F T T T T Like this :D
 2 years ago

A.Avinash_Goutham Group TitleBest ResponseYou've already chosen the best response.0
u dont need help gal jus think
 2 years ago

Esmy Group TitleBest ResponseYou've already chosen the best response.1
Blagh I am thats why I'm asking if I did right or not
 2 years ago

Esmy Group TitleBest ResponseYou've already chosen the best response.1
Okay I'm guessing i didn't do that one right so ill work on another one.
 2 years ago

A.Avinash_Goutham Group TitleBest ResponseYou've already chosen the best response.0
lol draw truth tables for p → ~q q → ~p and pvq see when p → ~q q → ~p are true pvq is true
 2 years ago

Esmy Group TitleBest ResponseYou've already chosen the best response.1
(~p V q) > ~q (~T V F) > ~F (F V F) > T F > T T So (~p V q) > ~q is true.
 2 years ago

Esmy Group TitleBest ResponseYou've already chosen the best response.1
Blagh W/e I'm right I've done everything... :l
 2 years ago

Esmy Group TitleBest ResponseYou've already chosen the best response.1
q p (q → ~p) → (q ∧ ~p) T T T T F T F T F F F F
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
the first two statements are identical \[p\to \lnot q\iff q\to \lnot p\] one is the contrapositive of the other
 2 years ago

Esmy Group TitleBest ResponseYou've already chosen the best response.1
hmmm is my table okay :/ ?
 2 years ago

Esmy Group TitleBest ResponseYou've already chosen the best response.1
I've done like three so far _
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
let me right it correctly \[\begin{array}{cccccc} P & Q & \lnot{}P & \lnot{}Q & P\to\lnot{}Q & Q\to\lnot{}P \\ \hline T & T & F & F & F & F \\ T& F & F & T & T & T \\ F & T & T & F & T & T \\ F & F & T & T & T & T \\ \hline \end{array}\]
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.0
the final step is put in the column p v q (this is the first problem) An argument is INVALID if and only if it is logically possible for the conclusion to be false even though every premise is assumed to be true.
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
if you want to check your truth table, use this nice site here takes a second to get used to 0 and 1 instead of T and F, and a minute to learn the syntax but it is really useful http://www.kwi.dk/projects/php/truthtable/?
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
but try to think "logically" meaning like a human being instead of using T and F the first statement and the second statement are identical, one is the contrapositive of the other. so you do not need them both, they say the same thing
 2 years ago

Esmy Group TitleBest ResponseYou've already chosen the best response.1
so none of my tables where right :/ ...
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.0
this looks ok, The argument is invalid because of the last row p q ~p ~q p > ~q q > ~p p v q T T F F F F T T F F T T T T F T T F T T T F F T T T T F Hmmm... I change my answer its invalid
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
P: it is raining Q: i will go to the store \(P\to \lnot Q\) if it is raining then i will not go the the store \(Q\to \lnot P\) if i go to the store, then it is not raining they are identical statements from that, can we conclude that is is raining or i go to the store?
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
of course not! maybe it is sunny and i stay home anyway!
 2 years ago

Esmy Group TitleBest ResponseYou've already chosen the best response.1
Oh okay :o... I c I c
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.0
I don't see the other problems..... with premises and conclusion
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.0
I mean, did you post them?
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.0
Is this one of the problems (~p V q) > ~q ? with premise ~p v q and conclusion ~q
 2 years ago

Esmy Group TitleBest ResponseYou've already chosen the best response.1
I posted my answer and everything D:?
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.0
because it looks invalid p q (~p V q) ~q 0 0 1 1 OK 0 1 1 0 INVALID 1 0 0 1 OK 1 1 1 0 INVALID
 2 years ago

Esmy Group TitleBest ResponseYou've already chosen the best response.1
did you do this one or I did I forgot...
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.0
somewhere way up above you typed (~p V q) > ~q (~T V F) > ~F (F V F) > T F > T T So (~p V q) > ~q is true. I am not sure what the problem is, I'm guessing the first line. But your conclusion is not correct, because you did not test every case
 2 years ago

Esmy Group TitleBest ResponseYou've already chosen the best response.1
Oh lol thats just one of them lol. I did so many that I got lost ... but that I found out wasn't correct after all the thinking ;l
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.0
good, sounds like you have a handle on it.
 2 years ago
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