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this problem involves friction

I think we can use work-kinetic energy theorem.

hopefully :)
I seem to come up with 2 different answers; and i know one of them is wrong.

The aceleration must be constant right?

\[a=\frac{2d}{t^2}\]
\[v=at=\frac{2d}{t}\]
\[K_e=\frac12mv^2\]
energy lost to friction
\[P_e-K_e\]

assume a constant acceleration yes

You're did it correct i think

do you know the co-efficient of sliding friction?

not outright; but that can be calculated with given information i believe

Hmm, actually we don't need \(\mu\) since time is known.

mmm true.

hey you know that v=2d/t^2.
So KE is just 1/2 mv^2.

i mean, what else do you want?

The problem maybe 1.638 sec isn't the correct time :)

yes, v=3m/s in that case.

its pretty good, we slid the penny 5 times and averaged it out

at first the velocity of the Ke i just worked out threw me for a loop

you actually measured 3m/s!?

i couldnt see why the velocity from v=2d/t wasnt matching up :)

the 3 m/s was not measured, it was calculated

oh i thought you performed an experiment with a penny..

yes. This works no matter what the friction is (even 0).

..and a change in time, but thats a given :)

yes.

lol, great; i minute ten watching a sock slide down a banister ....

x)