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mdkk

  • 2 years ago

(x+h) squared - x squared divided by h

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  1. myininaya
    • 2 years ago
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    \[\frac{(x+h)^2-x^2}{h}\]

  2. heedcom
    • 2 years ago
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    what is th question

  3. myininaya
    • 2 years ago
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    What would you like to do with this? Simplify?

  4. mdkk
    • 2 years ago
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    yes, i known i would have to multiple the x+h by itself but then i am not sure what to do with the inside terms once i do that

  5. myininaya
    • 2 years ago
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    \[(x+h)^2=?\]

  6. myininaya
    • 2 years ago
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    So after you do what you just said what does that expand to?

  7. 03453660
    • 2 years ago
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    use this formula (a+b)^2 = a^2 + 2ab + b^2 here a=x and b=h

  8. mdkk
    • 2 years ago
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    yes right now i have x^2 + 2xh + h^2 -x^2 divided by h

  9. mdkk
    • 2 years ago
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    and i think i would cancel the x^2 and -x^2

  10. 03453660
    • 2 years ago
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    yes exactly

  11. mdkk
    • 2 years ago
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    but when i get to 2xh+h^2 divied by h can i cancel the h in the 2xh with the other h's or can i not do that because it is a term with x? if that makes sense

  12. myininaya
    • 2 years ago
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    You have h in the denominator

  13. myininaya
    • 2 years ago
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    You can factor out h on top And assuming h does not equal 0 You can do what after that?

  14. 03453660
    • 2 years ago
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    you can cancel it out with the h in the dennomenator

  15. mdkk
    • 2 years ago
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    so would the final answer im left with be 2x + h ?

  16. 03453660
    • 2 years ago
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    yap

  17. myininaya
    • 2 years ago
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    Yes! :)

  18. mdkk
    • 2 years ago
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    oh alright, thank you both!

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