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mdkk

(x+h) squared - x squared divided by h

  • one year ago
  • one year ago

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  1. myininaya
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    \[\frac{(x+h)^2-x^2}{h}\]

    • one year ago
  2. heedcom
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    what is th question

    • one year ago
  3. myininaya
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    What would you like to do with this? Simplify?

    • one year ago
  4. mdkk
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    yes, i known i would have to multiple the x+h by itself but then i am not sure what to do with the inside terms once i do that

    • one year ago
  5. myininaya
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    \[(x+h)^2=?\]

    • one year ago
  6. myininaya
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    So after you do what you just said what does that expand to?

    • one year ago
  7. 03453660
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    use this formula (a+b)^2 = a^2 + 2ab + b^2 here a=x and b=h

    • one year ago
  8. mdkk
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    yes right now i have x^2 + 2xh + h^2 -x^2 divided by h

    • one year ago
  9. mdkk
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    and i think i would cancel the x^2 and -x^2

    • one year ago
  10. 03453660
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    yes exactly

    • one year ago
  11. mdkk
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    but when i get to 2xh+h^2 divied by h can i cancel the h in the 2xh with the other h's or can i not do that because it is a term with x? if that makes sense

    • one year ago
  12. myininaya
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    You have h in the denominator

    • one year ago
  13. myininaya
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    You can factor out h on top And assuming h does not equal 0 You can do what after that?

    • one year ago
  14. 03453660
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    you can cancel it out with the h in the dennomenator

    • one year ago
  15. mdkk
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    so would the final answer im left with be 2x + h ?

    • one year ago
  16. 03453660
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    yap

    • one year ago
  17. myininaya
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    Yes! :)

    • one year ago
  18. mdkk
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    oh alright, thank you both!

    • one year ago
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