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DLS Group Title

Limits

  • one year ago
  • one year ago

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  1. DLS Group Title
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    \[\lim_{x \rightarrow \infty }\frac{x^4+2x^3+3}{2x^4-x+2}\]

    • one year ago
  2. DLS Group Title
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    x+1 is a factor of this right?

    • one year ago
  3. DLS Group Title
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    however,no use..

    • one year ago
  4. TomLikesPhysics Group Title
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    I think it is one half. Because you got up- and downstairs and x^4 which I think is a special case and in which the limit approaches the coefficents before these two identical powers of x which is 1upstairs and 2 downstairs - 1/2.

    • one year ago
  5. DLS Group Title
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    it is 1/2 only but how

    • one year ago
  6. TomLikesPhysics Group Title
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    If you would use the L`Hopital Rule you would end up with it.

    • one year ago
  7. TomLikesPhysics Group Title
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    Do you want to see the calculation?

    • one year ago
  8. DLS Group Title
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    \[\lim_{x \rightarrow \infty }\frac{3x^4+4x^3+}{4x^4+x^2+7}\] I'm trying to do this with the same concept but i'm getting 5/7 @TomLikesPhysics ?

    • one year ago
  9. DLS Group Title
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    +5

    • one year ago
  10. DLS Group Title
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    *

    • one year ago
  11. DLS Group Title
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    \[\frac{12x^3+12x^2}{16x^3+2x}\]

    • one year ago
  12. TomLikesPhysics Group Title
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    should be 3/4

    • one year ago
  13. DLS Group Title
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    ??

    • one year ago
  14. TomLikesPhysics Group Title
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    the one where you got 5/7

    • one year ago
  15. DLS Group Title
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    okay got it!

    • one year ago
  16. DLS Group Title
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    but how is it gaining infinity/infinity?

    • one year ago
  17. TomLikesPhysics Group Title
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    How it gains infinity? You take the limit where x goes to infinity. So both terms grow. Is that what you meant?

    • one year ago
  18. DLS Group Title
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    it is something+infinity is it samething?

    • one year ago
  19. DLS Group Title
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    \[\lim_{x \rightarrow \infty } \frac{x^3+x^2+4}{x^2+8}\] are you gettng 1 here?

    • one year ago
  20. TomLikesPhysics Group Title
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    Here it should be infinity. You got downstairs an x^2 and upstairs and x^3. So the x^3 "is stronger" and wins and therefore the whole thing goes to infinity.

    • one year ago
  21. DLS Group Title
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    No,I solved according to what you said and got this: \[\frac{3x^2+2x}{2x}\] so I got 3x+1=1?

    • one year ago
  22. TomLikesPhysics Group Title
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    How do you end up with 3x+1=1 if you got a fraction?

    • one year ago
  23. DLS Group Title
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    \[\frac{3x^2}{2x} + \frac{2x}{2x}\]

    • one year ago
  24. DLS Group Title
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    I ended up with: \[\frac{3}{2}x+1\]

    • one year ago
  25. TomLikesPhysics Group Title
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    k but if you got 3x+1 and let x approach infinity (taking the limit) than you end up with infinity.

    • one year ago
  26. DLS Group Title
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    okay! if it was 1/x and x==> infinity it would have been 1 RIGHT?

    • one year ago
  27. TomLikesPhysics Group Title
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    limit x-> inf. of ax+b is alsways infinity. The b does not matter in the long run and nether does a while x gets bigger and bigger.

    • one year ago
  28. DLS Group Title
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    Great.Clear now :)

    • one year ago
  29. TomLikesPhysics Group Title
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    If you got 1/x and x gets bigger and bigger you would get a limit which is 0.

    • one year ago
  30. DLS Group Title
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    yeah!

    • one year ago
  31. TomLikesPhysics Group Title
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    1/x as x approaches infinity is 0. 1/x as x approaches 0 is infinity.

    • one year ago
  32. DLS Group Title
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    \[\lim_{x \rightarrow 0} \frac{\cos7x-\cos9x}{\cos3x-\cos5x}\] These ones?

    • one year ago
  33. TomLikesPhysics Group Title
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    I don´t know. Have not seen this one before.^^ Never dealt with limits and sine or cosine.

    • one year ago
  34. DLS Group Title
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    okay..book did a direct step after this :| \[\frac{2\sin8xsinx}{2\sin4xsinx} \]

    • one year ago
  35. TomLikesPhysics Group Title
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    ^^ First time I see that kind of stuff. I´m sorry but with that I can not help you.

    • one year ago
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