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DLSBest ResponseYou've already chosen the best response.0
\[\lim_{x \rightarrow \infty }\frac{x^4+2x^3+3}{2x^4x+2}\]
 one year ago

DLSBest ResponseYou've already chosen the best response.0
x+1 is a factor of this right?
 one year ago

TomLikesPhysicsBest ResponseYou've already chosen the best response.1
I think it is one half. Because you got up and downstairs and x^4 which I think is a special case and in which the limit approaches the coefficents before these two identical powers of x which is 1upstairs and 2 downstairs  1/2.
 one year ago

TomLikesPhysicsBest ResponseYou've already chosen the best response.1
If you would use the L`Hopital Rule you would end up with it.
 one year ago

TomLikesPhysicsBest ResponseYou've already chosen the best response.1
Do you want to see the calculation?
 one year ago

DLSBest ResponseYou've already chosen the best response.0
\[\lim_{x \rightarrow \infty }\frac{3x^4+4x^3+}{4x^4+x^2+7}\] I'm trying to do this with the same concept but i'm getting 5/7 @TomLikesPhysics ?
 one year ago

DLSBest ResponseYou've already chosen the best response.0
\[\frac{12x^3+12x^2}{16x^3+2x}\]
 one year ago

TomLikesPhysicsBest ResponseYou've already chosen the best response.1
the one where you got 5/7
 one year ago

DLSBest ResponseYou've already chosen the best response.0
but how is it gaining infinity/infinity?
 one year ago

TomLikesPhysicsBest ResponseYou've already chosen the best response.1
How it gains infinity? You take the limit where x goes to infinity. So both terms grow. Is that what you meant?
 one year ago

DLSBest ResponseYou've already chosen the best response.0
it is something+infinity is it samething?
 one year ago

DLSBest ResponseYou've already chosen the best response.0
\[\lim_{x \rightarrow \infty } \frac{x^3+x^2+4}{x^2+8}\] are you gettng 1 here?
 one year ago

TomLikesPhysicsBest ResponseYou've already chosen the best response.1
Here it should be infinity. You got downstairs an x^2 and upstairs and x^3. So the x^3 "is stronger" and wins and therefore the whole thing goes to infinity.
 one year ago

DLSBest ResponseYou've already chosen the best response.0
No,I solved according to what you said and got this: \[\frac{3x^2+2x}{2x}\] so I got 3x+1=1?
 one year ago

TomLikesPhysicsBest ResponseYou've already chosen the best response.1
How do you end up with 3x+1=1 if you got a fraction?
 one year ago

DLSBest ResponseYou've already chosen the best response.0
\[\frac{3x^2}{2x} + \frac{2x}{2x}\]
 one year ago

DLSBest ResponseYou've already chosen the best response.0
I ended up with: \[\frac{3}{2}x+1\]
 one year ago

TomLikesPhysicsBest ResponseYou've already chosen the best response.1
k but if you got 3x+1 and let x approach infinity (taking the limit) than you end up with infinity.
 one year ago

DLSBest ResponseYou've already chosen the best response.0
okay! if it was 1/x and x==> infinity it would have been 1 RIGHT?
 one year ago

TomLikesPhysicsBest ResponseYou've already chosen the best response.1
limit x> inf. of ax+b is alsways infinity. The b does not matter in the long run and nether does a while x gets bigger and bigger.
 one year ago

TomLikesPhysicsBest ResponseYou've already chosen the best response.1
If you got 1/x and x gets bigger and bigger you would get a limit which is 0.
 one year ago

TomLikesPhysicsBest ResponseYou've already chosen the best response.1
1/x as x approaches infinity is 0. 1/x as x approaches 0 is infinity.
 one year ago

DLSBest ResponseYou've already chosen the best response.0
\[\lim_{x \rightarrow 0} \frac{\cos7x\cos9x}{\cos3x\cos5x}\] These ones?
 one year ago

TomLikesPhysicsBest ResponseYou've already chosen the best response.1
I don´t know. Have not seen this one before.^^ Never dealt with limits and sine or cosine.
 one year ago

DLSBest ResponseYou've already chosen the best response.0
okay..book did a direct step after this : \[\frac{2\sin8xsinx}{2\sin4xsinx} \]
 one year ago

TomLikesPhysicsBest ResponseYou've already chosen the best response.1
^^ First time I see that kind of stuff. I´m sorry but with that I can not help you.
 one year ago
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