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so what we learned today ....
if a doesnt divide b, but a divides bc; then a divides c.
 one year ago
 one year ago
so what we learned today .... if a doesnt divide b, but a divides bc; then a divides c.
 one year ago
 one year ago

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amistre64Best ResponseYou've already chosen the best response.3
we also learned that if a divides bc, then a divides bcn ..... 30 minutes of my life gone :/
 one year ago

KingGeorgeBest ResponseYou've already chosen the best response.2
Believe it or not, that's not inherently obvious. Depending on what structures you're using, if a doesn't divide b, but a does divide bc, it doesn't necessarily divide c.
 one year ago

amistre64Best ResponseYou've already chosen the best response.3
number theory ... :)
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.0
I'ma delete this shortly afterward, but can anyone help me http://openstudy.com/study#/updates/5064b1f2e4b0583d5cd3facc Also, does that apply for matrix algebra?
 one year ago

amistre64Best ResponseYou've already chosen the best response.3
mattrix algebra has quirks in that its .. cant recall. ring, field, group ??
 one year ago

KingGeorgeBest ResponseYou've already chosen the best response.2
Number theory is an easy example, but you can define a ring with zero divisors, and suddenly, if ab=0, then neither a nor b must be 0.
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.0
o.o show me the logic!
 one year ago

amistre64Best ResponseYou've already chosen the best response.3
teacher did show us at the begining of the year about her thesis work on abstract algebra and made us write up Zmod 12 tables for addition and multiplication
 one year ago

KingGeorgeBest ResponseYou've already chosen the best response.2
Zmod12 is a nice example. 2*6=0=3*4
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.0
No that's not helpful I don't understand zmods lool
 one year ago

KingGeorgeBest ResponseYou've already chosen the best response.2
2*6 mod 12=0 If you understand modular multiplication, it's what you would imagine Zmod12 would be.
 one year ago

amistre64Best ResponseYou've already chosen the best response.3
if a not b; the (a,b)=1; therefore 1 = ax+by multiply each side by c c = acx+bcy aacx abcy , it was given in the thrm that abc therefore a  (acx+bcy) a  c
 one year ago

amistre64Best ResponseYou've already chosen the best response.3
all the 0 mod 12s have no recipricals :)
 one year ago

amistre64Best ResponseYou've already chosen the best response.3
.... er, no multiplicative inversai
 one year ago

inkyvoydBest ResponseYou've already chosen the best response.0
I look at wikipedia and see funny symbols. http://en.wikipedia.org/wiki/Modular_arithmetic I quit this party.
 one year ago

amistre64Best ResponseYou've already chosen the best response.3
There must be some way out of here, said the joker to the thief. There's too much confusion ... I can't get no relief
 one year ago

KingGeorgeBest ResponseYou've already chosen the best response.2
Well, if it's coprime to 12 it has a multiplicative inverse....
 one year ago
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