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amistre64
 4 years ago
so what we learned today ....
if a doesnt divide b, but a divides bc; then a divides c.
amistre64
 4 years ago
so what we learned today .... if a doesnt divide b, but a divides bc; then a divides c.

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amistre64
 4 years ago
Best ResponseYou've already chosen the best response.3we also learned that if a divides bc, then a divides bcn ..... 30 minutes of my life gone :/

KingGeorge
 4 years ago
Best ResponseYou've already chosen the best response.2Believe it or not, that's not inherently obvious. Depending on what structures you're using, if a doesn't divide b, but a does divide bc, it doesn't necessarily divide c.

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.0I'ma delete this shortly afterward, but can anyone help me http://openstudy.com/study#/updates/5064b1f2e4b0583d5cd3facc Also, does that apply for matrix algebra?

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.3mattrix algebra has quirks in that its .. cant recall. ring, field, group ??

KingGeorge
 4 years ago
Best ResponseYou've already chosen the best response.2Number theory is an easy example, but you can define a ring with zero divisors, and suddenly, if ab=0, then neither a nor b must be 0.

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.0o.o show me the logic!

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.3teacher did show us at the begining of the year about her thesis work on abstract algebra and made us write up Zmod 12 tables for addition and multiplication

KingGeorge
 4 years ago
Best ResponseYou've already chosen the best response.2Zmod12 is a nice example. 2*6=0=3*4

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.0No that's not helpful I don't understand zmods lool

KingGeorge
 4 years ago
Best ResponseYou've already chosen the best response.22*6 mod 12=0 If you understand modular multiplication, it's what you would imagine Zmod12 would be.

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.3if a not b; the (a,b)=1; therefore 1 = ax+by multiply each side by c c = acx+bcy aacx abcy , it was given in the thrm that abc therefore a  (acx+bcy) a  c

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.3all the 0 mod 12s have no recipricals :)

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.3.... er, no multiplicative inversai

inkyvoyd
 4 years ago
Best ResponseYou've already chosen the best response.0I look at wikipedia and see funny symbols. http://en.wikipedia.org/wiki/Modular_arithmetic I quit this party.

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.3There must be some way out of here, said the joker to the thief. There's too much confusion ... I can't get no relief

KingGeorge
 4 years ago
Best ResponseYou've already chosen the best response.2Well, if it's coprime to 12 it has a multiplicative inverse....
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