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precal

  • 3 years ago

Solve for x S=2x^2+4xh

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  1. inkyvoyd
    • 3 years ago
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    Treat S and h as constants.

  2. inkyvoyd
    • 3 years ago
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    Move S over to the other side. Then, 2x^2+(4h)x-S=0 Now use the quadratic equation, setting a=2, 4h=b, and c=-S

  3. precal
    • 3 years ago
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    oh I see it now, I saw a and b but did not think about S

  4. inkyvoyd
    • 3 years ago
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    Yeah :S

  5. precal
    • 3 years ago
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    |dw:1348777428990:dw|this is the book solution

  6. precal
    • 3 years ago
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    just if you were wondering... Thanks again

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