Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
Libniz
Group Title
Let X be a discrete random variables with PMF given by :
P_X(x)= x/15 ,{x=1,2,3,4,5}
0 , otherwise
b)let Y=(X3)^2, find range Y, S_Y , PMF of Y
 2 years ago
 2 years ago
Libniz Group Title
Let X be a discrete random variables with PMF given by : P_X(x)= x/15 ,{x=1,2,3,4,5} 0 , otherwise b)let Y=(X3)^2, find range Y, S_Y , PMF of Y
 2 years ago
 2 years ago

This Question is Closed

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.0
@amistre64
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.2
where are you stuck?
 2 years ago

Libniz Group TitleBest ResponseYou've already chosen the best response.0
P_X(x)= x/15 ,{x=1,2,3,4,5} 0 , otherwise so to find range using Y y= (X3)^2 ((x/15)3)^2 y= (1/15 3)^2 (44/45)^2 to 0
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.2
x takes the values 1,2,3,4,5 y=(x3)^2 plug those x values into the above equation
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.2
for the range(support)
 2 years ago

Libniz Group TitleBest ResponseYou've already chosen the best response.0
oh, it is X, not x
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.2
yes...so X takes the values 1,2,3,4,5 Y=(X3)^2 plug those X values into the above equation :)
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.2
ok...do what I wrote
 2 years ago

Libniz Group TitleBest ResponseYou've already chosen the best response.0
(13)^2,(23)^2,(33)^2,(43)^2,(53)^3 4,1,0,1,4
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.2
that is the range (or support)
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.2
now you can find the pmf
 2 years ago

Libniz Group TitleBest ResponseYou've already chosen the best response.0
so y=(x3)^2 do we solve for x?
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.2
\[P_{Y}(0)=P_{X}(3)\] \[P_{Y}(1)=P_{X}(2)+P_{X}(4)\] \[P_{Y}(4)=P_{X}(1)+P_{X}(5)\]
 2 years ago

Libniz Group TitleBest ResponseYou've already chosen the best response.0
can you explain me how you got that?
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.2
\[P_{Y}(1)=P(Y=1)=P(X=2\text{ or }X=4)\] \[=P(X=2)+P(X=4)=P_{X}(2)+P_{X}(4)\]
 2 years ago

Libniz Group TitleBest ResponseYou've already chosen the best response.0
still figuring out the last post
 2 years ago

Libniz Group TitleBest ResponseYou've already chosen the best response.0
I understand you sum because it is 'or' but why is P(y=1) = P(x=2 or x=4)
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.2
\[Y=(X3)^2\] \[1=(23)^2\] \[1=(43)^2\] if I tell you Y=1 then either X=2 or X=4
 2 years ago

Libniz Group TitleBest ResponseYou've already chosen the best response.0
so that's just P(Y=1) do we find Y=1,2,3,4,5?
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.2
Y only takes the values 0,1,4
 2 years ago

Libniz Group TitleBest ResponseYou've already chosen the best response.0
got it , thanks; I wish you were my probability professor
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.