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Let X be a discrete random variables with PMF given by :
P_X(x)= x/15 ,{x=1,2,3,4,5}
0 , otherwise
b)let Y=(X3)^2, find range Y, S_Y , PMF of Y
 one year ago
 one year ago
Let X be a discrete random variables with PMF given by : P_X(x)= x/15 ,{x=1,2,3,4,5} 0 , otherwise b)let Y=(X3)^2, find range Y, S_Y , PMF of Y
 one year ago
 one year ago

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LibnizBest ResponseYou've already chosen the best response.0
P_X(x)= x/15 ,{x=1,2,3,4,5} 0 , otherwise so to find range using Y y= (X3)^2 ((x/15)3)^2 y= (1/15 3)^2 (44/45)^2 to 0
 one year ago

ZarkonBest ResponseYou've already chosen the best response.2
x takes the values 1,2,3,4,5 y=(x3)^2 plug those x values into the above equation
 one year ago

ZarkonBest ResponseYou've already chosen the best response.2
yes...so X takes the values 1,2,3,4,5 Y=(X3)^2 plug those X values into the above equation :)
 one year ago

LibnizBest ResponseYou've already chosen the best response.0
(13)^2,(23)^2,(33)^2,(43)^2,(53)^3 4,1,0,1,4
 one year ago

ZarkonBest ResponseYou've already chosen the best response.2
that is the range (or support)
 one year ago

ZarkonBest ResponseYou've already chosen the best response.2
now you can find the pmf
 one year ago

LibnizBest ResponseYou've already chosen the best response.0
so y=(x3)^2 do we solve for x?
 one year ago

ZarkonBest ResponseYou've already chosen the best response.2
\[P_{Y}(0)=P_{X}(3)\] \[P_{Y}(1)=P_{X}(2)+P_{X}(4)\] \[P_{Y}(4)=P_{X}(1)+P_{X}(5)\]
 one year ago

LibnizBest ResponseYou've already chosen the best response.0
can you explain me how you got that?
 one year ago

ZarkonBest ResponseYou've already chosen the best response.2
\[P_{Y}(1)=P(Y=1)=P(X=2\text{ or }X=4)\] \[=P(X=2)+P(X=4)=P_{X}(2)+P_{X}(4)\]
 one year ago

LibnizBest ResponseYou've already chosen the best response.0
still figuring out the last post
 one year ago

LibnizBest ResponseYou've already chosen the best response.0
I understand you sum because it is 'or' but why is P(y=1) = P(x=2 or x=4)
 one year ago

ZarkonBest ResponseYou've already chosen the best response.2
\[Y=(X3)^2\] \[1=(23)^2\] \[1=(43)^2\] if I tell you Y=1 then either X=2 or X=4
 one year ago

LibnizBest ResponseYou've already chosen the best response.0
so that's just P(Y=1) do we find Y=1,2,3,4,5?
 one year ago

ZarkonBest ResponseYou've already chosen the best response.2
Y only takes the values 0,1,4
 one year ago

LibnizBest ResponseYou've already chosen the best response.0
got it , thanks; I wish you were my probability professor
 one year ago
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