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 2 years ago
Let X be a discrete random variables with PMF given by :
P_X(x)= x/15 ,{x=1,2,3,4,5}
0 , otherwise
b)let Y=(X3)^2, find range Y, S_Y , PMF of Y
 2 years ago
Let X be a discrete random variables with PMF given by : P_X(x)= x/15 ,{x=1,2,3,4,5} 0 , otherwise b)let Y=(X3)^2, find range Y, S_Y , PMF of Y

This Question is Closed

Libniz
 2 years ago
Best ResponseYou've already chosen the best response.0P_X(x)= x/15 ,{x=1,2,3,4,5} 0 , otherwise so to find range using Y y= (X3)^2 ((x/15)3)^2 y= (1/15 3)^2 (44/45)^2 to 0

Zarkon
 2 years ago
Best ResponseYou've already chosen the best response.2x takes the values 1,2,3,4,5 y=(x3)^2 plug those x values into the above equation

Zarkon
 2 years ago
Best ResponseYou've already chosen the best response.2yes...so X takes the values 1,2,3,4,5 Y=(X3)^2 plug those X values into the above equation :)

Libniz
 2 years ago
Best ResponseYou've already chosen the best response.0(13)^2,(23)^2,(33)^2,(43)^2,(53)^3 4,1,0,1,4

Zarkon
 2 years ago
Best ResponseYou've already chosen the best response.2that is the range (or support)

Zarkon
 2 years ago
Best ResponseYou've already chosen the best response.2now you can find the pmf

Libniz
 2 years ago
Best ResponseYou've already chosen the best response.0so y=(x3)^2 do we solve for x?

Zarkon
 2 years ago
Best ResponseYou've already chosen the best response.2\[P_{Y}(0)=P_{X}(3)\] \[P_{Y}(1)=P_{X}(2)+P_{X}(4)\] \[P_{Y}(4)=P_{X}(1)+P_{X}(5)\]

Libniz
 2 years ago
Best ResponseYou've already chosen the best response.0can you explain me how you got that?

Zarkon
 2 years ago
Best ResponseYou've already chosen the best response.2\[P_{Y}(1)=P(Y=1)=P(X=2\text{ or }X=4)\] \[=P(X=2)+P(X=4)=P_{X}(2)+P_{X}(4)\]

Libniz
 2 years ago
Best ResponseYou've already chosen the best response.0still figuring out the last post

Libniz
 2 years ago
Best ResponseYou've already chosen the best response.0I understand you sum because it is 'or' but why is P(y=1) = P(x=2 or x=4)

Zarkon
 2 years ago
Best ResponseYou've already chosen the best response.2\[Y=(X3)^2\] \[1=(23)^2\] \[1=(43)^2\] if I tell you Y=1 then either X=2 or X=4

Libniz
 2 years ago
Best ResponseYou've already chosen the best response.0so that's just P(Y=1) do we find Y=1,2,3,4,5?

Zarkon
 2 years ago
Best ResponseYou've already chosen the best response.2Y only takes the values 0,1,4

Libniz
 2 years ago
Best ResponseYou've already chosen the best response.0got it , thanks; I wish you were my probability professor
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