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woleraymond
Group Title
The capacitance of a variable radio capacitor can be changed from 50PF to 95PF by turning the dial from 0 to 180 degrees. With the dial set at 180 degrees , the capacitor is connected to a 400V battery. After charging the capacitor is disconnected from the battery and the dial is turned to 0 degrees.
a  What is the charge on the capacitor
b What is the p.d across the capacitor when the dial reads 0 degrees.
c  WHat is the energy of the capacitor in this position?
 one year ago
 one year ago
woleraymond Group Title
The capacitance of a variable radio capacitor can be changed from 50PF to 95PF by turning the dial from 0 to 180 degrees. With the dial set at 180 degrees , the capacitor is connected to a 400V battery. After charging the capacitor is disconnected from the battery and the dial is turned to 0 degrees. a  What is the charge on the capacitor b What is the p.d across the capacitor when the dial reads 0 degrees. c  WHat is the energy of the capacitor in this position?
 one year ago
 one year ago

This Question is Closed

radar Group TitleBest ResponseYou've already chosen the best response.1
a. Q=CV=(95 10^12)(400) = 38 10^9 coulomb b.760 volts c. Use approriate equation (I don't have it memorized)
 one year ago

woleraymond Group TitleBest ResponseYou've already chosen the best response.0
@radar how did you arrive at your answer pls explain @experimentX @RaphaelFilgueiras @Algebraic! any info
 one year ago

Algebraic! Group TitleBest ResponseYou've already chosen the best response.0
which part?
 one year ago

RaphaelFilgueiras Group TitleBest ResponseYou've already chosen the best response.2
c) E=1/2 C V²
 one year ago

RaphaelFilgueiras Group TitleBest ResponseYou've already chosen the best response.2
@woleraymond are you there?
 one year ago

woleraymond Group TitleBest ResponseYou've already chosen the best response.0
yep im here
 one year ago

RaphaelFilgueiras Group TitleBest ResponseYou've already chosen the best response.2
what you didnt understood?
 one year ago

woleraymond Group TitleBest ResponseYou've already chosen the best response.0
how did @radar arrive at 760 volts for question b..also what impact does the turning have on the capacitor
 one year ago

RaphaelFilgueiras Group TitleBest ResponseYou've already chosen the best response.2
the charge will be the same,when you turn the dial to zero degrees ,you will change the capacitance for 50 PF
 one year ago

RaphaelFilgueiras Group TitleBest ResponseYou've already chosen the best response.2
then q=c.v> 38E9=50E12.v>v=760
 one year ago

RaphaelFilgueiras Group TitleBest ResponseYou've already chosen the best response.2
now energy will be 1/2.c.v²=1/2. 50E12.(760²)
 one year ago

RaphaelFilgueiras Group TitleBest ResponseYou've already chosen the best response.2
14.4 microjoules
 one year ago

woleraymond Group TitleBest ResponseYou've already chosen the best response.0
interesting....
 one year ago
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