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woleraymond
 3 years ago
The capacitance of a variable radio capacitor can be changed from 50PF to 95PF by turning the dial from 0 to 180 degrees. With the dial set at 180 degrees , the capacitor is connected to a 400V battery. After charging the capacitor is disconnected from the battery and the dial is turned to 0 degrees.
a  What is the charge on the capacitor
b What is the p.d across the capacitor when the dial reads 0 degrees.
c  WHat is the energy of the capacitor in this position?
woleraymond
 3 years ago
The capacitance of a variable radio capacitor can be changed from 50PF to 95PF by turning the dial from 0 to 180 degrees. With the dial set at 180 degrees , the capacitor is connected to a 400V battery. After charging the capacitor is disconnected from the battery and the dial is turned to 0 degrees. a  What is the charge on the capacitor b What is the p.d across the capacitor when the dial reads 0 degrees. c  WHat is the energy of the capacitor in this position?

This Question is Closed

radar
 3 years ago
Best ResponseYou've already chosen the best response.1a. Q=CV=(95 10^12)(400) = 38 10^9 coulomb b.760 volts c. Use approriate equation (I don't have it memorized)

woleraymond
 3 years ago
Best ResponseYou've already chosen the best response.0@radar how did you arrive at your answer pls explain @experimentX @RaphaelFilgueiras @Algebraic! any info

RaphaelFilgueiras
 3 years ago
Best ResponseYou've already chosen the best response.2c) E=1/2 C V²

RaphaelFilgueiras
 3 years ago
Best ResponseYou've already chosen the best response.2@woleraymond are you there?

RaphaelFilgueiras
 3 years ago
Best ResponseYou've already chosen the best response.2what you didnt understood?

woleraymond
 3 years ago
Best ResponseYou've already chosen the best response.0how did @radar arrive at 760 volts for question b..also what impact does the turning have on the capacitor

RaphaelFilgueiras
 3 years ago
Best ResponseYou've already chosen the best response.2the charge will be the same,when you turn the dial to zero degrees ,you will change the capacitance for 50 PF

RaphaelFilgueiras
 3 years ago
Best ResponseYou've already chosen the best response.2then q=c.v> 38E9=50E12.v>v=760

RaphaelFilgueiras
 3 years ago
Best ResponseYou've already chosen the best response.2now energy will be 1/2.c.v²=1/2. 50E12.(760²)

RaphaelFilgueiras
 3 years ago
Best ResponseYou've already chosen the best response.214.4 microjoules
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