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Libniz

  • 3 years ago

2 balls are chosen randomly from an urn containing 8 white, 4 black, 2 orange ball. Suppose you win 2 dollars for each black ball and lose 1 dollar for each white ball selected. Let X be the net winning , Find a) S_x my answer is for a) (-2,1,2)

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  1. Libniz
    • 3 years ago
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    b) asked for pmf P_x (8/14)^2 x=-2 (4/14)*(8/14) x=1 (4/14)^2 x=2

  2. Libniz
    • 3 years ago
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    @zarkon

  3. Libniz
    • 3 years ago
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    @myininaya

  4. MathLegend
    • 3 years ago
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    What type of math is this? Algebra 1?

  5. MathLegend
    • 3 years ago
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    Honestly, I have no clue.

  6. OpenstudyUser
    • 3 years ago
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    lol

  7. Libniz
    • 3 years ago
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    probability

  8. Zarkon
    • 3 years ago
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    sampling with or without replacement?

  9. Libniz
    • 3 years ago
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    didn't say anything about replacement so I think without

  10. Zarkon
    • 3 years ago
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    if it is without...then your pmf is not correct

  11. Libniz
    • 3 years ago
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    what is it mean by "replacement"?

  12. Zarkon
    • 3 years ago
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    if it is replacement then you pick a ball...look at it ..put it back then randomly sample again with all 14 balls

  13. Libniz
    • 3 years ago
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    I think ,from the wording; we are pulling two balls out at the same time

  14. Zarkon
    • 3 years ago
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    that is what I am thinking

  15. Zarkon
    • 3 years ago
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    so you need to redo your pmf

  16. Zarkon
    • 3 years ago
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    if you get black balls then you get $2 each correct

  17. Libniz
    • 3 years ago
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    yes

  18. Zarkon
    • 3 years ago
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    so one possibility is that you win $4

  19. Libniz
    • 3 years ago
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    white ball, I lost $1

  20. Zarkon
    • 3 years ago
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    BB=$4 BO=$2 OB=$2 BW=$1 WB=$1 ...

  21. Zarkon
    • 3 years ago
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    so X can take the values 4,2,1,0,-1,-2

  22. Zarkon
    • 3 years ago
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    agree?

  23. Libniz
    • 3 years ago
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    oh, I see, I omitted orange which I shouldn't have

  24. Libniz
    • 3 years ago
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    so how would I write PMF?

  25. Zarkon
    • 3 years ago
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    what i s the probability of 2 blacks? ie $4

  26. Libniz
    • 3 years ago
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    (8/14)*(7/13)

  27. Zarkon
    • 3 years ago
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    ok what about winning $2

  28. Libniz
    • 3 years ago
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    (4/14)(2/13) or (2/14)(4/13) ?

  29. Zarkon
    • 3 years ago
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    winning $2 is BO or OB

  30. Zarkon
    • 3 years ago
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    there are 8 blacks...i see no 8's in your solution

  31. Zarkon
    • 3 years ago
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    lol.....there are 8 W

  32. Zarkon
    • 3 years ago
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    4 black...so prob of BB is \[\frac{4}{14}\cdot\frac{3}{13}\]

  33. Zarkon
    • 3 years ago
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    not what you had above

  34. Zarkon
    • 3 years ago
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    so \[P(X=4)=\frac{4}{14}\cdot\frac{3}{13}\]

  35. Libniz
    • 3 years ago
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    right , so for $2 (4/14)(2/13) or (2/14)(4/13) (4/14)(2/13)+(2/14)(4/13)=

  36. Zarkon
    • 3 years ago
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    yes

  37. Zarkon
    • 3 years ago
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    the sum of the two

  38. Libniz
    • 3 years ago
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    I understand now; I really appreciate your help

  39. Zarkon
    • 3 years ago
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    no problem

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