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Libniz Group Title

2 balls are chosen randomly from an urn containing 8 white, 4 black, 2 orange ball. Suppose you win 2 dollars for each black ball and lose 1 dollar for each white ball selected. Let X be the net winning , Find a) S_x my answer is for a) (-2,1,2)

  • 2 years ago
  • 2 years ago

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  1. Libniz Group Title
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    b) asked for pmf P_x (8/14)^2 x=-2 (4/14)*(8/14) x=1 (4/14)^2 x=2

    • 2 years ago
  2. Libniz Group Title
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    @zarkon

    • 2 years ago
  3. Libniz Group Title
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    @myininaya

    • 2 years ago
  4. MathLegend Group Title
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    What type of math is this? Algebra 1?

    • 2 years ago
  5. MathLegend Group Title
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    Honestly, I have no clue.

    • 2 years ago
  6. OpenstudyUser Group Title
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    lol

    • 2 years ago
  7. Libniz Group Title
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    probability

    • 2 years ago
  8. Zarkon Group Title
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    sampling with or without replacement?

    • 2 years ago
  9. Libniz Group Title
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    didn't say anything about replacement so I think without

    • 2 years ago
  10. Zarkon Group Title
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    if it is without...then your pmf is not correct

    • 2 years ago
  11. Libniz Group Title
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    what is it mean by "replacement"?

    • 2 years ago
  12. Zarkon Group Title
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    if it is replacement then you pick a ball...look at it ..put it back then randomly sample again with all 14 balls

    • 2 years ago
  13. Libniz Group Title
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    I think ,from the wording; we are pulling two balls out at the same time

    • 2 years ago
  14. Zarkon Group Title
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    that is what I am thinking

    • 2 years ago
  15. Zarkon Group Title
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    so you need to redo your pmf

    • 2 years ago
  16. Zarkon Group Title
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    if you get black balls then you get $2 each correct

    • 2 years ago
  17. Libniz Group Title
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    yes

    • 2 years ago
  18. Zarkon Group Title
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    so one possibility is that you win $4

    • 2 years ago
  19. Libniz Group Title
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    white ball, I lost $1

    • 2 years ago
  20. Zarkon Group Title
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    BB=$4 BO=$2 OB=$2 BW=$1 WB=$1 ...

    • 2 years ago
  21. Zarkon Group Title
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    so X can take the values 4,2,1,0,-1,-2

    • 2 years ago
  22. Zarkon Group Title
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    agree?

    • 2 years ago
  23. Libniz Group Title
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    oh, I see, I omitted orange which I shouldn't have

    • 2 years ago
  24. Libniz Group Title
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    so how would I write PMF?

    • 2 years ago
  25. Zarkon Group Title
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    what i s the probability of 2 blacks? ie $4

    • 2 years ago
  26. Libniz Group Title
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    (8/14)*(7/13)

    • 2 years ago
  27. Zarkon Group Title
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    ok what about winning $2

    • 2 years ago
  28. Libniz Group Title
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    (4/14)(2/13) or (2/14)(4/13) ?

    • 2 years ago
  29. Zarkon Group Title
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    winning $2 is BO or OB

    • 2 years ago
  30. Zarkon Group Title
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    there are 8 blacks...i see no 8's in your solution

    • 2 years ago
  31. Zarkon Group Title
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    lol.....there are 8 W

    • 2 years ago
  32. Zarkon Group Title
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    4 black...so prob of BB is \[\frac{4}{14}\cdot\frac{3}{13}\]

    • 2 years ago
  33. Zarkon Group Title
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    not what you had above

    • 2 years ago
  34. Zarkon Group Title
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    so \[P(X=4)=\frac{4}{14}\cdot\frac{3}{13}\]

    • 2 years ago
  35. Libniz Group Title
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    right , so for $2 (4/14)(2/13) or (2/14)(4/13) (4/14)(2/13)+(2/14)(4/13)=

    • 2 years ago
  36. Zarkon Group Title
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    yes

    • 2 years ago
  37. Zarkon Group Title
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    the sum of the two

    • 2 years ago
  38. Libniz Group Title
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    I understand now; I really appreciate your help

    • 2 years ago
  39. Zarkon Group Title
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    no problem

    • 2 years ago
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