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Solve the system of equations by graphing
3x + 2y = 2
4x + 5y = 28
 one year ago
 one year ago
Solve the system of equations by graphing 3x + 2y = 2 4x + 5y = 28
 one year ago
 one year ago

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qpHalcy0nBest ResponseYou've already chosen the best response.0
Do you have a graphing calculator or other utilities?
 one year ago

qpHalcy0nBest ResponseYou've already chosen the best response.0
Or do they want you to actually draw it. (Either way should be fine)
 one year ago

Geometry_HaterBest ResponseYou've already chosen the best response.1
You need to graph it and then look for a point of its intersection
 one year ago

DiscordBest ResponseYou've already chosen the best response.0
Unfortunately I do not have a graphing calculator.
 one year ago

Geometry_HaterBest ResponseYou've already chosen the best response.1
You can download one onto your computer
 one year ago

qpHalcy0nBest ResponseYou've already chosen the best response.0
I would just use wolframalpha. The way these equations work out, there's no way you'd get an accurate answer on pencil/paper.
 one year ago

Geometry_HaterBest ResponseYou've already chosen the best response.1
or use a free one here http://my.hrw.com/math06_07/nsmedia/tools/Graph_Calculator/graphCalc.html
 one year ago

Geometry_HaterBest ResponseYou've already chosen the best response.1
So to start you need to get y by itself in both equations
 one year ago

qpHalcy0nBest ResponseYou've already chosen the best response.0
http://www.wolframalpha.com/input/?i=3x+%2B+2y+%3D+2+and+4x+%2B+5y+%3D+28
 one year ago

qpHalcy0nBest ResponseYou've already chosen the best response.0
If you were using a TI calculator or some similar, you would have to isolate y.
 one year ago

qpHalcy0nBest ResponseYou've already chosen the best response.0
Get y by itself in both equations.
 one year ago

Geometry_HaterBest ResponseYou've already chosen the best response.1
3x + 2y = 2 Subtract 3x ......2y = 3x 2 Divide by 2........ y= 3/2x  1 Do the same for the other one
 one year ago

DiscordBest ResponseYou've already chosen the best response.0
Oh okay. Let me work that out.
 one year ago
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