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anonymous
 4 years ago
Solve the system of equations by graphing
3x + 2y = 2
4x + 5y = 28
anonymous
 4 years ago
Solve the system of equations by graphing 3x + 2y = 2 4x + 5y = 28

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Do you have a graphing calculator or other utilities?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Or do they want you to actually draw it. (Either way should be fine)

Geometry_Hater
 4 years ago
Best ResponseYou've already chosen the best response.1You need to graph it and then look for a point of its intersection

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Unfortunately I do not have a graphing calculator.

Geometry_Hater
 4 years ago
Best ResponseYou've already chosen the best response.1You can download one onto your computer

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I would just use wolframalpha. The way these equations work out, there's no way you'd get an accurate answer on pencil/paper.

Geometry_Hater
 4 years ago
Best ResponseYou've already chosen the best response.1or use a free one here http://my.hrw.com/math06_07/nsmedia/tools/Graph_Calculator/graphCalc.html

Geometry_Hater
 4 years ago
Best ResponseYou've already chosen the best response.1So to start you need to get y by itself in both equations

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0http://www.wolframalpha.com/input/?i=3x+%2B+2y+%3D+2+and+4x+%2B+5y+%3D+28

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0If you were using a TI calculator or some similar, you would have to isolate y.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Get y by itself in both equations.

Geometry_Hater
 4 years ago
Best ResponseYou've already chosen the best response.13x + 2y = 2 Subtract 3x ......2y = 3x 2 Divide by 2........ y= 3/2x  1 Do the same for the other one

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh okay. Let me work that out.
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