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davester248 Group TitleBest ResponseYou've already chosen the best response.0
The answer will always be that number to the square root of infinity.
 2 years ago

badreferences Group TitleBest ResponseYou've already chosen the best response.2
\[\mathbb C^\infty\]Like this?
 2 years ago

extremity Group TitleBest ResponseYou've already chosen the best response.0
Why are all polynomials C^infinity? I mean, if we consider the polynomial f(x)=x^2...how does that satisfy the definition. ps. badreferences u are correct
 2 years ago

badreferences Group TitleBest ResponseYou've already chosen the best response.2
That means it's infinite dimensional complex. Are you in a modern algebra class?
 2 years ago

extremity Group TitleBest ResponseYou've already chosen the best response.0
ok whats\[C^\infty(R)\] cause thats what im getting at
 2 years ago

badreferences Group TitleBest ResponseYou've already chosen the best response.2
I'm a little hazy, but isn't that the CauchyReimmann surface?
 2 years ago

badreferences Group TitleBest ResponseYou've already chosen the best response.2
Wait, no, nevermind, ignore me.
 2 years ago

badreferences Group TitleBest ResponseYou've already chosen the best response.2
What class is this?
 2 years ago

extremity Group TitleBest ResponseYou've already chosen the best response.0
higher linear algebra
 2 years ago

extremity Group TitleBest ResponseYou've already chosen the best response.0
its not very specific, but its a linear map !!
 2 years ago

helder_edwin Group TitleBest ResponseYou've already chosen the best response.1
\(C^\infty\) means that it can be differentiated infinitelymany times.
 2 years ago

davester248 Group TitleBest ResponseYou've already chosen the best response.0
Exactly, amen
 2 years ago

badreferences Group TitleBest ResponseYou've already chosen the best response.2
\(\mathbb C^\infty\) means something else.
 2 years ago

extremity Group TitleBest ResponseYou've already chosen the best response.0
\[C^\infty(R)>C^\infty(R)\]
 2 years ago

badreferences Group TitleBest ResponseYou've already chosen the best response.2
\(C\) or \(\mathbb C\)?
 2 years ago

extremity Group TitleBest ResponseYou've already chosen the best response.0
single C. I see. Now, wolfram says that all polynomials are C^infty. Can someone explain to be how f(x) = ax^2 +bx+c is C^infty? considering that it is a polynomial?
 2 years ago

badreferences Group TitleBest ResponseYou've already chosen the best response.2
Ah okay. \(C(R)\) means the complex conjugate of \(R\). This is the sansserif \(C\) as opposed to the shell \(\mathbb C\).
 2 years ago

badreferences Group TitleBest ResponseYou've already chosen the best response.2
At least, in particle physics. Maybe it has another meaning in higher linear algebra. Apologies. Infinity complex conjugates doesn't sound right.
 2 years ago

badreferences Group TitleBest ResponseYou've already chosen the best response.2
@TuringTest Hehe, you're better at math than me.
 2 years ago

badreferences Group TitleBest ResponseYou've already chosen the best response.2
@Zarkon You too get in here.
 2 years ago

extremity Group TitleBest ResponseYou've already chosen the best response.0
All good guys ! http://sci4um.com/about19318.html So f(x)=0 is C^infinity :) im happy now ! thanks guys !
 2 years ago

badreferences Group TitleBest ResponseYou've already chosen the best response.2
Manifold calculus? Hard stuff to learn in linear algebra.
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.1
I think it's what @helder_edwin said. Any polynomial can be differentiated to 0 by taking n+1 derivatives where n is the order of the polynomial. The derivative of 0 is 0, which can, of course, be differentiated ad infinitum. Hence all (at least finitedegree, I don't know about otherwise) polynomials are infinitely differentiable.
 2 years ago

badreferences Group TitleBest ResponseYou've already chosen the best response.2
Yes, @extremity found it. Why do they use the same symbol as the one you use when you learn about symmetry in physics?
 2 years ago

badreferences Group TitleBest ResponseYou've already chosen the best response.2
Two completely different things.
 2 years ago
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