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davester248Best ResponseYou've already chosen the best response.0
The answer will always be that number to the square root of infinity.
 one year ago

badreferencesBest ResponseYou've already chosen the best response.2
\[\mathbb C^\infty\]Like this?
 one year ago

extremityBest ResponseYou've already chosen the best response.0
Why are all polynomials C^infinity? I mean, if we consider the polynomial f(x)=x^2...how does that satisfy the definition. ps. badreferences u are correct
 one year ago

badreferencesBest ResponseYou've already chosen the best response.2
That means it's infinite dimensional complex. Are you in a modern algebra class?
 one year ago

extremityBest ResponseYou've already chosen the best response.0
ok whats\[C^\infty(R)\] cause thats what im getting at
 one year ago

badreferencesBest ResponseYou've already chosen the best response.2
I'm a little hazy, but isn't that the CauchyReimmann surface?
 one year ago

badreferencesBest ResponseYou've already chosen the best response.2
Wait, no, nevermind, ignore me.
 one year ago

badreferencesBest ResponseYou've already chosen the best response.2
What class is this?
 one year ago

extremityBest ResponseYou've already chosen the best response.0
higher linear algebra
 one year ago

extremityBest ResponseYou've already chosen the best response.0
its not very specific, but its a linear map !!
 one year ago

helder_edwinBest ResponseYou've already chosen the best response.1
\(C^\infty\) means that it can be differentiated infinitelymany times.
 one year ago

badreferencesBest ResponseYou've already chosen the best response.2
\(\mathbb C^\infty\) means something else.
 one year ago

extremityBest ResponseYou've already chosen the best response.0
\[C^\infty(R)>C^\infty(R)\]
 one year ago

badreferencesBest ResponseYou've already chosen the best response.2
\(C\) or \(\mathbb C\)?
 one year ago

extremityBest ResponseYou've already chosen the best response.0
single C. I see. Now, wolfram says that all polynomials are C^infty. Can someone explain to be how f(x) = ax^2 +bx+c is C^infty? considering that it is a polynomial?
 one year ago

badreferencesBest ResponseYou've already chosen the best response.2
Ah okay. \(C(R)\) means the complex conjugate of \(R\). This is the sansserif \(C\) as opposed to the shell \(\mathbb C\).
 one year ago

badreferencesBest ResponseYou've already chosen the best response.2
At least, in particle physics. Maybe it has another meaning in higher linear algebra. Apologies. Infinity complex conjugates doesn't sound right.
 one year ago

badreferencesBest ResponseYou've already chosen the best response.2
@TuringTest Hehe, you're better at math than me.
 one year ago

badreferencesBest ResponseYou've already chosen the best response.2
@Zarkon You too get in here.
 one year ago

extremityBest ResponseYou've already chosen the best response.0
All good guys ! http://sci4um.com/about19318.html So f(x)=0 is C^infinity :) im happy now ! thanks guys !
 one year ago

badreferencesBest ResponseYou've already chosen the best response.2
Manifold calculus? Hard stuff to learn in linear algebra.
 one year ago

TuringTestBest ResponseYou've already chosen the best response.1
I think it's what @helder_edwin said. Any polynomial can be differentiated to 0 by taking n+1 derivatives where n is the order of the polynomial. The derivative of 0 is 0, which can, of course, be differentiated ad infinitum. Hence all (at least finitedegree, I don't know about otherwise) polynomials are infinitely differentiable.
 one year ago

badreferencesBest ResponseYou've already chosen the best response.2
Yes, @extremity found it. Why do they use the same symbol as the one you use when you learn about symmetry in physics?
 one year ago

badreferencesBest ResponseYou've already chosen the best response.2
Two completely different things.
 one year ago
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