Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Libniz

  • 2 years ago

A production line yields two types of devices: Type1 devices occur with probability p1 and work for an average time T1, Type2 devices occur with probability p2 and work for an average time T2, such that p1+p2=1 and T2>T1. The time a device works is modeled as a geometrical distribution. Let X be the time a device chosen uniformly at random works. Find the distribution of X.

  • This Question is Closed
  1. Libniz
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @satellite73

  2. Libniz
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I am having trouble setting it up

  3. satellite73
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok i have to think geometric distribution is \(P(n) = p(1-p)^n\) right?

  4. Libniz
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes

  5. satellite73
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    jesus i have no idea. it tell you average is \(T_1\) and i think that means \(\frac{1-p_1}{p_1}=T_1\)

  6. satellite73
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    let me try to write this correctly \[T_1=\frac{p_2}{p_1}\] and \[T_2=\frac{p_1}{p_2}\] but i am not sure that helps solve the problem do you have an example to work off of ?

  7. Libniz
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    no, this is a practice exam

  8. Libniz
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    that's ok, thanks for your help

  9. satellite73
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok forget that last noise i wrote, it is ridiculous and i am embarrassed maybe it is much simpler we pick device \(T_1\) with probability \(p_1\) and device \(T_2\) with probability \(p_2\) could it be as simple as \(p_1T_1+p_2T_2\)

  10. satellite73
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    no that isn't right either, at least i don't think so what text are you using?

  11. Libniz
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I am actually having troubling understanding what is being asked

  12. satellite73
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i think you are being asked the following: pick a device at random, put \(X\) = amount of time it runs. Find the distribution of \(X\)

  13. satellite73
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    in other words, find a formula for \(P(X=k)\) the probability the device runs for time \(k\)

  14. satellite73
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    but really i am stuck so i should shut up. but perhaps i have a text with something similar, which is why i asked what text you were using

  15. Libniz
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    probability and schocastic process by yates

  16. satellite73
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    nope, sorry

  17. Libniz
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @phi

  18. phi
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    do you know how to combine two geometric distributions?

  19. Libniz
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    no

  20. phi
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    that is what they are asking

  21. satellite73
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i should delete my embarrassing answer now we will get a real one i hope

  22. Libniz
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    can you show me how to combine distributions

  23. phi
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    No answer from me, I never learned this stuff. But it might be a negative binomial distribution.

  24. Libniz
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    alright, thanks anyway

  25. phi
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    if you get the answer, please post it.

  26. Libniz
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I will ask zarkon, when he comes on; hopefully before my quiz though

  27. Libniz
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @zarkon

  28. Zarkon
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    is that the full problem?

  29. Libniz
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes

  30. Zarkon
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I'm a little confused ... Type1 devices occur with probability p1 ... Type2 devices occur with probability p2 vs "a device chosen uniformly" are they chosen uniformly or with probabilities p1,p2

  31. Libniz
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    screen shot in case I mistyped something

    1 Attachment
  32. Zarkon
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I don't think the problem is worded very well especally near the end. here is how I see the problem let \(d1,d2\) be device 1 and device 2 then \[P(X\le x)=P((X\le x,d1)\text{ or }(X\le x,d2))\] \[=P(X\le x|d1)P(d1)+P(X\le x|d2)P(d2)\]

  33. Zarkon
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[=P(X\le x|d1)p1+P(X\le x|d2)p2\]

  34. Zarkon
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    though I could be misinterpreting the problem (since I don't think it is totally clear)

  35. Libniz
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yeah, I had hard time even understanding what they were asking for

  36. Zarkon
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I would ask your prof...problem isn't clear to me and I have taught courses in mathematical statistics.

  37. Libniz
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so this is conditional probability problem?

  38. Zarkon
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    based on what read it looks like you need to use conditional prob for at least part of the problem

  39. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.