ahoymewmew
can someone help me with radicals? please :(
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Calle87
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hey
ahoymewmew
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hello @Calle87
Calle87
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question?
ahoymewmew
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its this. @Calle87
christiano123
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okay whats the question
ahoymewmew
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its in the attachment. @christiano123
Calle87
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ok, so i have row d done
Calle87
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\[\sqrt{18}+2\sqrt{75}-\sqrt{48}\]
ahoymewmew
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okay c: @Calle87 thanks.
Calle87
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so with radicals you can simplify each one by splitting them into smaller radicals
Calle87
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\[\sqrt{18}=\sqrt{9}\sqrt{2}=3\sqrt{2}\]
ahoymewmew
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like the square root of 18, is a decimal so you break it down and use a number that equals to 18 like 9x2 and since its still big you can simplify 9x3? @Calle87
Calle87
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\[2\sqrt{75}=2(\sqrt{25})(\sqrt{3})=2(5)\sqrt{3}=10\sqrt{3}\]
Calle87
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ya see what i did?
Calle87
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\[\sqrt{9}\sqrt{2}\]
Calle87
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whats the square root of 9?
ahoymewmew
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3 @Calle87
ahoymewmew
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so 2 cant be simplified but 9 can oh i see
Calle87
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ya they dont want decimals
Calle87
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you want the largest possible square root with the smallest
Calle87
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ie 9 and 2 for 18
ahoymewmew
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aha i just dont understand the last one were it has y @Calle87
Calle87
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ok so the last one,
ahoymewmew
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yea @Calle87 the y's confuse me with the exponents.
Calle87
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\[3(\sqrt{2y})(\sqrt{y^2})\]
Calle87
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\[\sqrt{2y^3}=\sqrt{2y}\sqrt{y^2}\]
Calle87
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see what i did?
ahoymewmew
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and what if there is a number on the outside of the sqrt and one on the inside? do you just bring the outside one down and fin the sqrt of the inside? @Calle87
Calle87
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\[3(\sqrt{2y})(\sqrt{y^2})\]
Calle87
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what is the square root of y^2?
ahoymewmew
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is it y?
Calle87
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yes!! :)
Calle87
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\[3(\sqrt{2y})(y)\]
Calle87
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\[3y \sqrt{2y}\]
Calle87
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first expression is simplified
Calle87
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can you do the 2nd?
ahoymewmew
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oh i get it is the second one A? i think it is c: @Calle87
Calle87
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of the last row
ahoymewmew
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the last one? @Calle87
Calle87
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it is c
Calle87
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the second one is C
Calle87
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the last row is E
Calle87
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fourth row is D
ahoymewmew
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oh i thought it was a because of the 3 and the 4 sqrt
Calle87
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what are you asking?
ahoymewmew
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because i saw the second one say 3y sqrt 4y and i thought it was the first one because it said 3 sqrt 2 because 4's sqrt is 2.
Calle87
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so you are having problems with the second row?
ahoymewmew
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no i got an a c: thanks :D
Calle87
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ok, so no more?
ahoymewmew
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yea no more thanks :D i understand them now c:
Calle87
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cool! great job @ahoymewmew