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|dw:1348800828515:dw|
how do you draw the inequalities?

2+2i will be at angle pi/2, but has a distance from the origin of \(2\sqrt 2\), not 1.

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correct, but not to scale

im working on the ineqs btw, just wait plz

Okay. got it.

can you draw it out?

Yes. But ill just give u the eq., and you'll draw it.

Simplify that and you'll get a nice cartesian inequality

Follow similar steps for the other one.

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why is it pi/2?
\[\arg ,~z=\tan^{-1}(\frac{b}{a})=\tan^{-1}\frac{2}{2}=\frac{\pi}{4}\]

oh, i ment that

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hmm im not sure about the inequalities yet , ill think about them

how did you derive
|z - 1 | < | z - i | ?

see if you can solve the first question

| x + 3a | > 2 | x - 2a | , a > 0 , solve

i think you can do that in cases,
case 1 : x > -3a

for that you just square both sides and get answer

\[x^2+6ax+9a^2 > 4(x^2-4ax+4a^2)\]

ok

\[-3x^2+22ax-7>0\]

yes

then use the quadratic formula?

\[x=\frac{11}{3}a \pm\frac{\sqrt{547}}{3}\]

what about the other ones, can you solve them

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hint for 7 ii

Spoilers/Hints/Maybe
from Mark Scheme for Exam
http://www.xtremepapers.com/papers/CIE/Cambridge%20International%20A%20and%20AS%20Level/Mathematics%20(9709)/9709_s10_ms_31.pdf

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u could be there

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