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gifty91

  • 3 years ago

A 50 kg person is standing on a bathroom scale in an elevator moving upward. a.) if the scale reads 56 kg, what is the magnitude of upward acceleration of the elevator (m/s^2)? b.) Now the elevator is traveling up while slowing down. If the magnitude of deceleration is the same as that in part (a), what is reading given by the scale?

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  1. Yahoo!
    • 3 years ago
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    \[R = m(g+a)\] \[560 = 50 (10 +a)\] \[560 = 500 + 50a\] \[60 = 50a\] \[a = \frac{ 6 }{ 5 } = 1.2m/s^2\]

  2. Algebraic!
    • 3 years ago
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    b) travelling up, decelerating: N = m(g- 6/5) N = m*8.8 = 440 N (scale reading)

  3. gifty91
    • 3 years ago
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    Thanks Yahoo! =)

  4. gifty91
    • 3 years ago
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    @Algebraic - thanks for replying to the question. I think they're wanting the answer to be in kg, so would I just convert the 440 N to kg? Or do I use another formula to find it?

  5. Yahoo!
    • 3 years ago
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    @gifty91 Do u have the answer key with u

  6. Yahoo!
    • 3 years ago
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    @gifty91

  7. gifty91
    • 3 years ago
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    Not really.. I just get 5 attempts at a question, and after the 5th attempt, it'll only show me the correct answer.

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