A community for students.
Here's the question you clicked on:
 0 viewing
gifty91
 3 years ago
A 50 kg person is standing on a bathroom scale in an elevator moving upward.
a.) if the scale reads 56 kg, what is the magnitude of upward acceleration of the elevator (m/s^2)?
b.) Now the elevator is traveling up while slowing down. If the magnitude of deceleration is the same as that in part (a), what is reading given by the scale?
gifty91
 3 years ago
A 50 kg person is standing on a bathroom scale in an elevator moving upward. a.) if the scale reads 56 kg, what is the magnitude of upward acceleration of the elevator (m/s^2)? b.) Now the elevator is traveling up while slowing down. If the magnitude of deceleration is the same as that in part (a), what is reading given by the scale?

This Question is Closed

Yahoo!
 3 years ago
Best ResponseYou've already chosen the best response.0\[R = m(g+a)\] \[560 = 50 (10 +a)\] \[560 = 500 + 50a\] \[60 = 50a\] \[a = \frac{ 6 }{ 5 } = 1.2m/s^2\]

Algebraic!
 3 years ago
Best ResponseYou've already chosen the best response.0b) travelling up, decelerating: N = m(g 6/5) N = m*8.8 = 440 N (scale reading)

gifty91
 3 years ago
Best ResponseYou've already chosen the best response.0@Algebraic  thanks for replying to the question. I think they're wanting the answer to be in kg, so would I just convert the 440 N to kg? Or do I use another formula to find it?

Yahoo!
 3 years ago
Best ResponseYou've already chosen the best response.0@gifty91 Do u have the answer key with u

gifty91
 3 years ago
Best ResponseYou've already chosen the best response.0Not really.. I just get 5 attempts at a question, and after the 5th attempt, it'll only show me the correct answer.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.