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rannsan

  • 3 years ago

completely simplify (x-2)/(8x^2- 32)

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  1. Outkast3r09
    • 3 years ago
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    \[\frac{x-2}{8x^2-32}\]

  2. apoorwa
    • 3 years ago
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    (x-2)/(8(x^2-4))

  3. apoorwa
    • 3 years ago
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    (x-2)/(8(x+2)(x-2)) \[\frac{ (x-2) }{ (8(x+2)(x-2)) }\]

  4. Outkast3r09
    • 3 years ago
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    first factor out an 8 out of the bottom \[\frac{x-2}{8(x^2-4)}\] next use \[(a-b)^2 =(a-b)(a+b)\] when a and b are perfect squares

  5. apoorwa
    • 3 years ago
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    cancel the common now

  6. Outkast3r09
    • 3 years ago
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    \[a^2-b^2=(a+b)(a-b)\]

  7. rannsan
    • 3 years ago
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    ok

  8. rannsan
    • 3 years ago
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    1/8(x+2) is this right?

  9. rannsan
    • 3 years ago
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    = (x-2)/8(x^2-4) = (x-2)/8(x+2)(x-2) = 1/8(x+2)

  10. apoorwa
    • 3 years ago
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    yes thats absolutely corret:)

  11. rannsan
    • 3 years ago
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    Thank you

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