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integrate (cscx)^3 >_>

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integration by parts it will work
int (cscx)^3 = int (cscx)^2 cscx dx let u=cscx du=.... dv=(cscx)^2 dx v=int(cscx)^2 dx v=..... and next use parts rule : int(udv) = uv-int(vdu)
but i was stuck to find int(cscx) dx, @TuringTest ^^ lol

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i'm not sure int (cscx)dx = ln(sinx)
@RadEn OpenStudy values the Learning process - not the ‘Give you an answer’ process •Don’t post only answers - guide the asker to a solution.
\[ \int \csc ^3xdx = \int (1 + \cot^2 x) \csc x \; dx\]
is there another trig identity i'm supposed to use? u-substitution isn't working
There is something of a trick to this... try \[\int \frac{ \sin(x)}{\sin^2(x) } dx\]
i'm not sure how you got that
its not (cosx)^2 / (sinx)^3?
I'm talking about integrating cosecant.
use the same technique as used here

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