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jaersyn Group Title

integrate (cscx)^3 >_>

  • 2 years ago
  • 2 years ago

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  1. RadEn Group Title
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    integration by parts it will work

    • 2 years ago
  2. RadEn Group Title
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    int (cscx)^3 = int (cscx)^2 cscx dx let u=cscx du=.... dv=(cscx)^2 dx v=int(cscx)^2 dx v=..... and next use parts rule : int(udv) = uv-int(vdu)

    • 2 years ago
  3. RadEn Group Title
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    but i was stuck to find int(cscx) dx, @TuringTest ^^ lol

    • 2 years ago
  4. RadEn Group Title
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    i'm not sure int (cscx)dx = ln(sinx)

    • 2 years ago
  5. Directrix Group Title
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    @RadEn OpenStudy values the Learning process - not the ‘Give you an answer’ process •Don’t post only answers - guide the asker to a solution. http://openstudy.com/code-of-conduct

    • 2 years ago
  6. experimentX Group Title
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    \[ \int \csc ^3xdx = \int (1 + \cot^2 x) \csc x \; dx\]

    • 2 years ago
  7. jaersyn Group Title
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    is there another trig identity i'm supposed to use? u-substitution isn't working

    • 2 years ago
  8. Jemurray3 Group Title
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    There is something of a trick to this... try \[\int \frac{ \sin(x)}{\sin^2(x) } dx\]

    • 2 years ago
  9. jaersyn Group Title
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    i'm not sure how you got that

    • 2 years ago
  10. jaersyn Group Title
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    its not (cosx)^2 / (sinx)^3?

    • 2 years ago
  11. Jemurray3 Group Title
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    I'm talking about integrating cosecant.

    • 2 years ago
  12. experimentX Group Title
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    use the same technique as used here http://en.wikipedia.org/wiki/Integral_of_secant_cubed

    • 2 years ago
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