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anonymous
 3 years ago
integrate (cscx)^3
>_>
anonymous
 3 years ago
integrate (cscx)^3 >_>

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RadEn
 3 years ago
Best ResponseYou've already chosen the best response.0integration by parts it will work

RadEn
 3 years ago
Best ResponseYou've already chosen the best response.0int (cscx)^3 = int (cscx)^2 cscx dx let u=cscx du=.... dv=(cscx)^2 dx v=int(cscx)^2 dx v=..... and next use parts rule : int(udv) = uvint(vdu)

RadEn
 3 years ago
Best ResponseYou've already chosen the best response.0but i was stuck to find int(cscx) dx, @TuringTest ^^ lol

RadEn
 3 years ago
Best ResponseYou've already chosen the best response.0i'm not sure int (cscx)dx = ln(sinx)

Directrix
 3 years ago
Best ResponseYou've already chosen the best response.2@RadEn OpenStudy values the Learning process  not the ‘Give you an answer’ process •Don’t post only answers  guide the asker to a solution. http://openstudy.com/codeofconduct

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.0\[ \int \csc ^3xdx = \int (1 + \cot^2 x) \csc x \; dx\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0is there another trig identity i'm supposed to use? usubstitution isn't working

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0There is something of a trick to this... try \[\int \frac{ \sin(x)}{\sin^2(x) } dx\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i'm not sure how you got that

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0its not (cosx)^2 / (sinx)^3?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I'm talking about integrating cosecant.

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.0use the same technique as used here http://en.wikipedia.org/wiki/Integral_of_secant_cubed
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