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rannsan

  • 3 years ago

Simplify........... (8x^2)/(x^2-9 ) ∙ (x^2+ 6x+9 )/(16x^3)

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  1. apoorwa
    • 3 years ago
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    try this in the same way as i told you the previous

  2. rannsan
    • 3 years ago
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    [8x^2/[(x-3)(x+3)] * [(x+3)^2/(16x^3)] then I Cancel any factor common to a numerator and a denominiator, such as 8,x^2,(x+3), and get [1/(x-3)] * [(x+3)/x] Multiply to get: = (x/3)/[x(x-3)] correct???

  3. apoorwa
    • 3 years ago
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    just a min let me check

  4. apoorwa
    • 3 years ago
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    its partly correct you missed writing something

  5. apoorwa
    • 3 years ago
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    (x+3)/(2x(x-3))

  6. rannsan
    • 3 years ago
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    oops what did I miss?

  7. rannsan
    • 3 years ago
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    ahhh I see thank you. I really suck at math, I am trying though.

  8. apoorwa
    • 3 years ago
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    maths is fun.... just love it

  9. rannsan
    • 3 years ago
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    I actually hate it, but I am almost 50yrs old and taking this again since high school. I was never taught algebra (the correct way) so I never learned the rules.

  10. rannsan
    • 3 years ago
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    I have one more week and my algebra days will be over thank goodness, I wish I did like it.

  11. apoorwa
    • 3 years ago
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    oh..it ok... you may ask for help any time....

  12. rannsan
    • 3 years ago
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    thank you

  13. apoorwa
    • 3 years ago
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    can you help me with probability

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