mathslover
Can |x| ever be negative in any case?
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mukushla
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nope
Libniz
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yes
Libniz
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|x| can't
mathslover
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|i| is negative or positive
mukushla
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=1 is positive
jmodel12
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Absolutely! My X is negative 50% of the time.
chandhuru
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modulus i is positive
mathslover
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\[|\sqrt{-1}| = ?\]
0^2 + 1^2 = 1 ?
mukushla
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\[\text{magnitude of everything}\ge0\]
mathslover
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|(a+ib)^2| = a^2+b^2 ?
mathslover
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|a+ib|^2 = a^2+b^2
hartnn
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|a+ib| = sqrt(a^2+b^2)
mathslover
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Yep..
Thanks @mukushla and @Libniz and @hartnn
mukushla
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no problem
Perseverance
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no because |x| = √(X² ) so even if you get any number + or - the number will be squared first making it to be + then it will be rooted to give you the number