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hartnn
Group Title
inverse of mod function?
like y= x mod p,
1=5 mod 2
how do i get 5 from {1,2}
 2 years ago
 2 years ago
hartnn Group Title
inverse of mod function? like y= x mod p, 1=5 mod 2 how do i get 5 from {1,2}
 2 years ago
 2 years ago

This Question is Closed

suvesh253 Group TitleBest ResponseYou've already chosen the best response.0
doesnot exist as inverse only possible for oneone function
 2 years ago

mukushla Group TitleBest ResponseYou've already chosen the best response.1
y=x ? inverse of this will not be a function
 2 years ago

mukushla Group TitleBest ResponseYou've already chosen the best response.1
inverse exist x=y but its not a function
 2 years ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.0
mod is not 11 function
 2 years ago

suvesh253 Group TitleBest ResponseYou've already chosen the best response.0
modulus is a manyone function hence it's inverse not possible
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
c= a mod b = > corresponds to
 2 years ago

Mikael Group TitleBest ResponseYou've already chosen the best response.1
NO PROBLEMAS SENIOUR @hartnn ! Let B be the set of ordered pairs of pairsofnumbers, in other words pairs of points in the plane: \[ b \in B \,\,\iff b=(P_1, P_2) \] then the inverse function of \[Abs^{1}(y) = ((y,y),(y,y)) \] and a medal , naturally. forgive my humbleness...
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
whats and how ? \(Abs^{1}(y) = ((y,y),(y,y))\)
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
if i have y=x mod 7, how would i find its inverse ?
 2 years ago

Mikael Group TitleBest ResponseYou've already chosen the best response.1
The Abs is of course x not the algebraic coincidence of names.
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
i eas talking about remainder
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
like 5 mod 2 is 1
 2 years ago

suvesh253 Group TitleBest ResponseYou've already chosen the best response.0
if modulus is with only number then it is oneone and inverse will exist
 2 years ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
x = sgn(x) .x
 2 years ago

Mikael Group TitleBest ResponseYou've already chosen the best response.1
Anyway also for remainder possible to invert \[ mod:\,r_{Ideal} \rightarrow r \\ mod^{1}: r \rightarrow r_{Ideal}\]
 2 years ago

Mikael Group TitleBest ResponseYou've already chosen the best response.1
and a , the action that should not be asked but anyway received :)
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
but i didn't understand....
 2 years ago

Mikael Group TitleBest ResponseYou've already chosen the best response.1
thx oh exalted one !
 2 years ago

Mikael Group TitleBest ResponseYou've already chosen the best response.1
Learn about Ideals even if you dont have them :) http://en.wikipedia.org/wiki/Ideal_(ring_theory)
 2 years ago

Mikael Group TitleBest ResponseYou've already chosen the best response.1
MEdals, Medals gentleman for the wondering scholar ....! Keep them falling !
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
hmmm...didn't study ideals, i'll go through them, thanks
 2 years ago

Mikael Group TitleBest ResponseYou've already chosen the best response.1
Everybody that did  pls gratify
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
i think the question is maybe something different, are you asking how do you solve \[x\equiv y (mod n)\] for \(y\) if you know \(x\) ?
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
yes, i wrote somewhere in between = > correcponds to
 2 years ago

Mikael Group TitleBest ResponseYou've already chosen the best response.1
If that was the question I would not solve it  but it was not!
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
so for example solve \( 5\equiv x\text{ mod } 3\)
 2 years ago

Mikael Group TitleBest ResponseYou've already chosen the best response.1
No uniqueness  only an IDEAL OF ANSWERS
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
there are many (or infinite ?) values of x in 5=x mod 3 ??
 2 years ago

Mikael Group TitleBest ResponseYou've already chosen the best response.1
Yes  they form an IDEAL
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
ideals live in arbitrary rings, and are not necessary for understanding elementary number theory
 2 years ago

Mikael Group TitleBest ResponseYou've already chosen the best response.1
Anyway the set pf answers here IS an Ideal.
 2 years ago

Mikael Group TitleBest ResponseYou've already chosen the best response.1
By the way the only proper way to make equivalence necessary for "REMAINDER CALCULUS" is bu using ideals. Elementary  well yes.
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
ok, thank you @Mikael i'll go through IDEALS and ask u if i have any doubts. thanks to @satellite73 also :)
 2 years ago

Mikael Group TitleBest ResponseYou've already chosen the best response.1
Firstly is the "cyclical group". It will give you the applications. Only then that. This takes you further
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
any good reference for such things(other than wikipedia) where these things are explained in lucid manner ?
 2 years ago

Mikael Group TitleBest ResponseYou've already chosen the best response.1
http://en.wikipedia.org/wiki/Modular_arithmetic
 2 years ago

Mikael Group TitleBest ResponseYou've already chosen the best response.1
1 mathdl.maa.org/images/upload_library/22/Polya/Brenton.pdf en.wikipedia.org/wiki/Elementary_group_theory math.uc.edu/~hodgestj/Abstract%20Algebra/GroupTheory512.pdf www.rowan.edu/.../Some%20Elementary%20Group%20Theory.pdf
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
because of those ... i cannot get the reference
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.2
only last one i couldn't get
 2 years ago

Mikael Group TitleBest ResponseYou've already chosen the best response.1
Just ggle "elementary remainder group theory"
 2 years ago
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