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suvesh253
 2 years ago
Best ResponseYou've already chosen the best response.0doesnot exist as inverse only possible for oneone function

mukushla
 2 years ago
Best ResponseYou've already chosen the best response.1y=x ? inverse of this will not be a function

mukushla
 2 years ago
Best ResponseYou've already chosen the best response.1inverse exist x=y but its not a function

ganeshie8
 2 years ago
Best ResponseYou've already chosen the best response.0mod is not 11 function

suvesh253
 2 years ago
Best ResponseYou've already chosen the best response.0modulus is a manyone function hence it's inverse not possible

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2c= a mod b = > corresponds to

Mikael
 2 years ago
Best ResponseYou've already chosen the best response.1NO PROBLEMAS SENIOUR @hartnn ! Let B be the set of ordered pairs of pairsofnumbers, in other words pairs of points in the plane: \[ b \in B \,\,\iff b=(P_1, P_2) \] then the inverse function of \[Abs^{1}(y) = ((y,y),(y,y)) \] and a medal , naturally. forgive my humbleness...

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2whats and how ? \(Abs^{1}(y) = ((y,y),(y,y))\)

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2if i have y=x mod 7, how would i find its inverse ?

Mikael
 2 years ago
Best ResponseYou've already chosen the best response.1The Abs is of course x not the algebraic coincidence of names.

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2i eas talking about remainder

suvesh253
 2 years ago
Best ResponseYou've already chosen the best response.0if modulus is with only number then it is oneone and inverse will exist

Mikael
 2 years ago
Best ResponseYou've already chosen the best response.1Anyway also for remainder possible to invert \[ mod:\,r_{Ideal} \rightarrow r \\ mod^{1}: r \rightarrow r_{Ideal}\]

Mikael
 2 years ago
Best ResponseYou've already chosen the best response.1and a , the action that should not be asked but anyway received :)

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2but i didn't understand....

Mikael
 2 years ago
Best ResponseYou've already chosen the best response.1Learn about Ideals even if you dont have them :) http://en.wikipedia.org/wiki/Ideal_(ring_theory)

Mikael
 2 years ago
Best ResponseYou've already chosen the best response.1MEdals, Medals gentleman for the wondering scholar ....! Keep them falling !

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2hmmm...didn't study ideals, i'll go through them, thanks

Mikael
 2 years ago
Best ResponseYou've already chosen the best response.1Everybody that did  pls gratify

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0i think the question is maybe something different, are you asking how do you solve \[x\equiv y (mod n)\] for \(y\) if you know \(x\) ?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2yes, i wrote somewhere in between = > correcponds to

Mikael
 2 years ago
Best ResponseYou've already chosen the best response.1If that was the question I would not solve it  but it was not!

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0so for example solve \( 5\equiv x\text{ mod } 3\)

Mikael
 2 years ago
Best ResponseYou've already chosen the best response.1No uniqueness  only an IDEAL OF ANSWERS

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2there are many (or infinite ?) values of x in 5=x mod 3 ??

Mikael
 2 years ago
Best ResponseYou've already chosen the best response.1Yes  they form an IDEAL

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0ideals live in arbitrary rings, and are not necessary for understanding elementary number theory

Mikael
 2 years ago
Best ResponseYou've already chosen the best response.1Anyway the set pf answers here IS an Ideal.

Mikael
 2 years ago
Best ResponseYou've already chosen the best response.1By the way the only proper way to make equivalence necessary for "REMAINDER CALCULUS" is bu using ideals. Elementary  well yes.

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2ok, thank you @Mikael i'll go through IDEALS and ask u if i have any doubts. thanks to @satellite73 also :)

Mikael
 2 years ago
Best ResponseYou've already chosen the best response.1Firstly is the "cyclical group". It will give you the applications. Only then that. This takes you further

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2any good reference for such things(other than wikipedia) where these things are explained in lucid manner ?

Mikael
 2 years ago
Best ResponseYou've already chosen the best response.11 mathdl.maa.org/images/upload_library/22/Polya/Brenton.pdf en.wikipedia.org/wiki/Elementary_group_theory math.uc.edu/~hodgestj/Abstract%20Algebra/GroupTheory512.pdf www.rowan.edu/.../Some%20Elementary%20Group%20Theory.pdf

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2because of those ... i cannot get the reference

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2only last one i couldn't get

Mikael
 2 years ago
Best ResponseYou've already chosen the best response.1Just ggle "elementary remainder group theory"
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