Let A be the total surface area of a rectangular container of square base and height, h. At a certain instant, the surface area is decreasing at 24 cm^2/s while the width of the base is 5 cm and increasing at 2 cm/s. Determine whether the height is increasing or decreasing at that instant if the height is 3 cm. (Ans: dh/dt = -4.4 cm/s)
Somebody PLEAAAAAASSSEEE explain this to me. :(

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okay :/ how do i solve it?

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